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Spring Bootframework~10 mins

Dockerfile for Spring Boot in Spring Boot - Step-by-Step Execution

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Concept Flow - Dockerfile for Spring Boot
Start: Write Dockerfile
↓
Choose base image
↓
Copy jar file into image
↓
Set entrypoint to run jar
↓
Build Docker image
↓
Run container
↓
Spring Boot app runs inside container
This flow shows how a Dockerfile is created and used to build and run a Spring Boot application inside a container.
Execution Sample
Spring Boot
FROM openjdk:17-jdk-slim
COPY target/app.jar app.jar
ENTRYPOINT ["java", "-jar", "/app.jar"]
This Dockerfile uses an OpenJDK base image, copies the Spring Boot jar, and sets the command to run it.
Execution Table
StepDockerfile InstructionActionResult
1FROM openjdk:17-jdk-slimSelect base image with Java 17Base image ready with Java environment
2COPY target/app.jar app.jarCopy Spring Boot jar into imageapp.jar available inside image
3ENTRYPOINT ["java", "-jar", "/app.jar"]Set container start commandContainer will run the jar on start
4docker build -t springboot-app .Build Docker image from DockerfileImage 'springboot-app' created
5docker run -p 8080:8080 springboot-appRun container exposing port 8080Spring Boot app runs and listens on port 8080
💡 Container runs until stopped; Spring Boot app serves requests on port 8080
Variable Tracker
VariableStartAfter Step 1After Step 2After Step 3After Step 4After Step 5
Docker ImageNoneopenjdk:17-jdk-slimopenjdk + app.jarConfigured with ENTRYPOINTBuilt as springboot-appRunning container with app
Key Moments - 3 Insights
Why do we use 'COPY target/app.jar app.jar' instead of copying the whole project?
Because the Docker image only needs the compiled jar file to run the app, not the source code. This is shown in execution_table step 2.
What does ENTRYPOINT do in the Dockerfile?
ENTRYPOINT sets the command that runs when the container starts, here it runs the Spring Boot jar. See execution_table step 3.
Why do we expose port 8080 when running the container?
Spring Boot listens on port 8080 by default, so exposing it allows access from outside the container. See execution_table step 5.
Visual Quiz - 3 Questions
Test your understanding
Look at the execution table, what is the base image used in step 1?
Aopenjdk:8-jdk
Bubuntu:latest
Copenjdk:17-jdk-slim
Dspringboot:latest
💡 Hint
Check the Dockerfile Instruction column in step 1 of the execution_table.
At which step is the Spring Boot jar copied into the Docker image?
AStep 2
BStep 3
CStep 1
DStep 4
💡 Hint
Look for the COPY instruction in the execution_table.
If we change the ENTRYPOINT to run a different jar, which step would change?
AStep 2
BStep 3
CStep 1
DStep 5
💡 Hint
ENTRYPOINT is set in step 3 according to the execution_table.
Concept Snapshot
Dockerfile for Spring Boot:
FROM openjdk:17-jdk-slim
COPY target/app.jar app.jar
ENTRYPOINT ["java", "-jar", "/app.jar"]
Build image with 'docker build -t name .'
Run container with 'docker run -p 8080:8080 name'
Spring Boot app runs inside container on port 8080
Full Transcript
This visual execution shows how to create a Dockerfile for a Spring Boot application. First, we select a base image with Java 17. Then we copy the compiled Spring Boot jar file into the image. Next, we set the ENTRYPOINT to run the jar when the container starts. After writing the Dockerfile, we build the Docker image and then run a container exposing port 8080. The Spring Boot app runs inside the container and listens on port 8080. Key points include copying only the jar file, setting the correct ENTRYPOINT, and exposing the right port for access.

Practice

(1/5)
1. What is the main purpose of a Dockerfile in a Spring Boot project?
easy
A. To write the Java code for the Spring Boot application
B. To define how to package and run the Spring Boot app inside a container
C. To configure the database connection settings
D. To create unit tests for the Spring Boot app

Solution

  1. Step 1: Understand the role of Dockerfile

    A Dockerfile contains instructions to build a Docker image that packages the app and its environment.
  2. Step 2: Identify its use in Spring Boot

    For Spring Boot, it defines how to copy the app jar, expose ports, and run the app in a container.
  3. Final Answer:

    To define how to package and run the Spring Boot app inside a container -> Option B
  4. Quick Check:

    Dockerfile = Package & run app [OK]
Hint: Dockerfile builds container image for your app [OK]
Common Mistakes:
  • Confusing Dockerfile with source code files
  • Thinking Dockerfile configures app logic
  • Assuming Dockerfile is for testing only
2. Which of the following is the correct syntax to copy the Spring Boot jar file into the Docker image in a Dockerfile?
easy
A. COPY /app.jar target/app.jar
B. MOVE target/app.jar /app.jar
C. ADD target/app.jar
D. COPY target/app.jar /app.jar

Solution

  1. Step 1: Understand COPY command syntax

    The COPY command syntax is: COPY source_path destination_path inside the image.
  2. Step 2: Apply to Spring Boot jar

    We copy the built jar from local 'target/app.jar' to '/app.jar' inside the image.
  3. Final Answer:

    COPY target/app.jar /app.jar -> Option D
  4. Quick Check:

    COPY source destination [OK]
Hint: COPY source then destination path [OK]
Common Mistakes:
  • Using MOVE instead of COPY
  • Missing destination path in ADD
  • Reversing source and destination paths
3. Given this Dockerfile snippet:
FROM openjdk:17-jdk-slim
COPY target/app.jar /app.jar
EXPOSE 8080
ENTRYPOINT ["java", "-jar", "/app.jar"]

What happens when you run the built Docker image?
medium
A. The container runs but does not start the app
B. The container fails because EXPOSE is missing
C. The container runs the Spring Boot app on port 8080
D. The container runs the app but on port 80

Solution

  1. Step 1: Analyze Dockerfile commands

    FROM sets base image with Java 17. COPY adds app.jar. EXPOSE 8080 declares port. ENTRYPOINT runs the jar.
  2. Step 2: Understand container behavior

    When run, container starts Java app listening on port 8080 as declared.
  3. Final Answer:

    The container runs the Spring Boot app on port 8080 -> Option C
  4. Quick Check:

    ENTRYPOINT runs app, EXPOSE 8080 [OK]
Hint: ENTRYPOINT runs app; EXPOSE shows port [OK]
Common Mistakes:
  • Thinking EXPOSE runs the app
  • Assuming default port 80 without config
  • Ignoring ENTRYPOINT command
4. You wrote this Dockerfile:
FROM openjdk:17-jdk-slim
COPY app.jar /app.jar
EXPOSE 8080
ENTRYPOINT ["java", "-jar", "/app.jar"]

But when running the container, it fails with 'file not found'. What is the likely cause?
medium
A. The jar file is not named 'app.jar' in the build folder
B. EXPOSE 8080 is missing
C. ENTRYPOINT syntax is incorrect
D. Base image openjdk:17-jdk-slim does not support Java

Solution

  1. Step 1: Check COPY source path

    COPY expects a local file named 'app.jar' but likely the jar is named differently or in a different folder.
  2. Step 2: Understand error cause

    If the jar is missing or misnamed, container cannot find '/app.jar' to run, causing failure.
  3. Final Answer:

    The jar file is not named 'app.jar' in the build folder -> Option A
  4. Quick Check:

    COPY source must match actual jar name [OK]
Hint: Check jar filename matches COPY source [OK]
Common Mistakes:
  • Assuming EXPOSE affects file copying
  • Miswriting ENTRYPOINT array syntax
  • Blaming base image for missing file
5. You want to optimize your Spring Boot Dockerfile to use a smaller image and faster startup. Which Dockerfile snippet achieves this best?
hard
A. FROM openjdk:17-jre-slim COPY target/app.jar /app.jar EXPOSE 8080 ENTRYPOINT ["java", "-jar", "/app.jar"]
B. FROM alpine COPY target/app.jar /app.jar EXPOSE 8080 ENTRYPOINT ["java", "-jar", "/app.jar"]
C. FROM openjdk:17-jdk-slim COPY target/app.jar /app.jar EXPOSE 8080 ENTRYPOINT ["java", "-jar", "/app.jar"]
D. FROM openjdk:17-jdk COPY target/app.jar /app.jar EXPOSE 8080 ENTRYPOINT ["java", "-jar", "/app.jar"]

Solution

  1. Step 1: Compare base images

    openjdk:17-jre-slim has only Java runtime, smaller than jdk images which include compilers.
  2. Step 2: Evaluate options for size and startup

    Using jre-slim reduces image size and speeds startup. Alpine lacks Java by default, causing errors.
  3. Final Answer:

    FROM openjdk:17-jre-slim COPY target/app.jar /app.jar EXPOSE 8080 ENTRYPOINT ["java", "-jar", "/app.jar"] -> Option A
  4. Quick Check:

    Use JRE slim for smaller, faster images [OK]
Hint: Use JRE slim base image for smaller Docker images [OK]
Common Mistakes:
  • Using full JDK image unnecessarily
  • Choosing Alpine without Java setup
  • Ignoring image size impact
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