Risk monitoring and control in Software Engineering - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to define a risk monitoring function that logs risk status.

Software Engineering

def monitor_risk(risk_level):
    if risk_level > 5:
        [1]("High risk detected")

Drag options to blanks, or click blank then click option'

Alog

Bnotify

Cprint

Dalert

Attempts:

3 left

💡 Hint

Common Mistakes

Using undefined functions like 'log' or 'alert' without imports.

The print function outputs the message to the console, which is suitable for simple risk monitoring logs.

2fill in blank

medium

Complete the code to check if the risk status is 'critical' and trigger an alert.

Software Engineering

risk_status = 'critical'
if risk_status == [1]:
    print('Alert: Critical risk!')

Drag options to blanks, or click blank then click option'

A'high'

B'critical'

C'medium'

D'low'

Attempts:

3 left

💡 Hint

Common Mistakes

Forgetting quotes around string literals.

The code checks if risk_status equals the string 'critical' to trigger the alert.

3fill in blank

hard

Fix the error in the code to correctly update the risk level in the dictionary.

Software Engineering

risk_data = {'level': 3}
risk_data['level'] [1] 7

Drag options to blanks, or click blank then click option'

A-=

B==

C+=

D=

Attempts:

3 left

💡 Hint

Common Mistakes

Using '==' instead of '=' for assignment.

The single equals sign = assigns the value 7 to the key 'level'. Using == is a comparison, not assignment.

4fill in blank

hard

Fill both blanks to create a dictionary comprehension that filters risks with level greater than 4.

Software Engineering

filtered_risks = {k: v for k, v in risks.items() if v [1] [2]

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A>

B4

C<

D5

Attempts:

3 left

💡 Hint

Common Mistakes

Using '<' instead of '>' causing wrong filtering.

The comprehension filters items where the value v is greater than 4.

5fill in blank

hard

Fill all three blanks to create a dictionary comprehension that converts risk names to uppercase and filters risks with level at least 3.

Software Engineering

result = { [1]: [2] for [3] in risk_dict.items() if [2] >= 3 }

Drag options to blanks, or click blank then click option'

Ak.upper()

Bv

Ck, v

Drisk_dict

Attempts:

3 left

💡 Hint

Common Mistakes

Using the dictionary name instead of key variable in comprehension.

The comprehension uses k.upper() as the key, v as the value, and iterates over k, v in risk_dict.items(). It filters values where v is at least 3.