Critical path method in Software Engineering - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to identify the earliest start time for a task in the Critical Path Method.

Software Engineering

earliest_start = [1]

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Aduration

B0

Clatest_finish

Dtotal_float

Attempts:

3 left

💡 Hint

Common Mistakes

Using duration as the earliest start time.

Confusing earliest start with latest finish.

The earliest start time for the first task in a project is zero because it can begin immediately.

2fill in blank

medium

Complete the code to calculate the total float of a task.

Software Engineering

total_float = latest_start - [1]

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Aearliest_start

Bduration

Cearliest_finish

Dlatest_finish

Attempts:

3 left

💡 Hint

Common Mistakes

Using duration instead of earliest start.

Confusing latest finish with latest start.

Total float is the difference between the latest start and earliest start times of a task.

3fill in blank

hard

Fix the error in the code to calculate the earliest finish time of a task.

Software Engineering

earliest_finish = earliest_start [1] duration

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A-

B*

C+

D/

Attempts:

3 left

💡 Hint

Common Mistakes

Using subtraction instead of addition.

Using multiplication or division incorrectly.

The earliest finish time is the sum of earliest start time and task duration.

4fill in blank

hard

Fill both blanks to create a dictionary comprehension that maps tasks to their total float if the float is greater than zero.

Software Engineering

floats = {task: [1] for task, [2] in tasks.items() if [1] > 0}

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Atotal_float

Bduration

Cfloat_value

Dstart_time

Attempts:

3 left

💡 Hint

Common Mistakes

Using duration instead of total float.

Using inconsistent variable names.

This comprehension creates a dictionary of tasks with their total float values, but only includes those with float greater than zero.

5fill in blank

hard

Fill all three blanks to create a dictionary comprehension that maps task names in uppercase to their durations, but only for tasks with duration greater than 5.

Software Engineering

result = { [1]: [2] for [3], duration in tasks.items() if duration > 5}

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Atask.upper()

Bduration

Ctask

Dduration.upper()

Attempts:

3 left

💡 Hint

Common Mistakes

Using duration.upper() which is invalid.

Mixing up task and duration variables.

This comprehension creates a dictionary where keys are uppercase task names and values are durations, filtering tasks longer than 5 units.