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Snowflakecloud~10 mins

SELECT with Snowflake functions - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to select all columns from the table named 'employees'.

Snowflake
SELECT [1] FROM employees;
Drag options to blanks, or click blank then click option'
AEVERYTHING
BALL
CCOLUMNS
D*
Attempts:
3 left
💡 Hint
Common Mistakes
Using keywords like ALL or COLUMNS which are not valid for selecting all columns.
2fill in blank
medium

Complete the code to get the current date using a Snowflake function.

Snowflake
SELECT [1]();
Drag options to blanks, or click blank then click option'
ANOW
BCURRENT_DATE
CGETDATE
DTODAY
Attempts:
3 left
💡 Hint
Common Mistakes
Using NOW() which returns date and time, not just date.
3fill in blank
hard

Fix the error in the code to convert a string '2024-06-01' to a date type.

Snowflake
SELECT TO_DATE([1], 'YYYY-MM-DD');
Drag options to blanks, or click blank then click option'
A2024/06/01
B'2024/06/01'
C'2024-06-01'
D2024-06-01
Attempts:
3 left
💡 Hint
Common Mistakes
Not quoting the date string or using slashes instead of dashes.
4fill in blank
hard

Fill both blanks to select the first 5 rows ordered by salary descending.

Snowflake
SELECT * FROM employees ORDER BY salary [1] LIMIT [2];
Drag options to blanks, or click blank then click option'
ADESC
BASC
C5
D10
Attempts:
3 left
💡 Hint
Common Mistakes
Using ASC instead of DESC, or wrong limit number.
5fill in blank
hard

Fill all three blanks to select employee names in uppercase where salary is greater than 50000.

Snowflake
SELECT [1](name) FROM employees WHERE salary [2] [3];
Drag options to blanks, or click blank then click option'
AUPPER
B>
C50000
DLOWER
Attempts:
3 left
💡 Hint
Common Mistakes
Using LOWER instead of UPPER, or wrong comparison operator.

Practice

(1/5)
1. What does the COUNT(*) function do in a Snowflake SELECT query?
easy
A. Calculates the sum of all numeric values in a column
B. Counts only rows with non-null values in a specific column
C. Counts all rows in the selected table or result set
D. Formats a date value into a string

Solution

  1. Step 1: Understand COUNT(*) function

    The COUNT(*) counts every row regardless of nulls or values.
  2. Step 2: Compare with other options

    Options B, C, and D describe different functions like COUNT(column), SUM(), and TO_CHAR().
  3. Final Answer:

    Counts all rows in the selected table or result set -> Option C
  4. Quick Check:

    COUNT(*) counts all rows [OK]
Hint: COUNT(*) counts every row, no matter what [OK]
Common Mistakes:
  • Confusing COUNT(*) with COUNT(column)
  • Thinking COUNT(*) ignores nulls
  • Mixing COUNT with SUM or TO_CHAR
2. Which of the following is the correct syntax to convert a date column order_date to a string in format 'YYYY-MM-DD' using Snowflake?
easy
A. SELECT FORMAT_DATE(order_date, 'YYYY-MM-DD') FROM orders;
B. SELECT TO_CHAR(order_date, 'YYYY-MM-DD') FROM orders;
C. SELECT TO_STRING(order_date, 'YYYY-MM-DD') FROM orders;
D. SELECT CAST(order_date AS STRING, 'YYYY-MM-DD') FROM orders;

Solution

  1. Step 1: Identify the correct function for date to string

    Snowflake uses TO_CHAR() to format dates as strings.
  2. Step 2: Check syntax correctness

    SELECT TO_CHAR(order_date, 'YYYY-MM-DD') FROM orders; uses TO_CHAR(order_date, 'YYYY-MM-DD'), which is correct syntax. Others use invalid or non-existent functions.
  3. Final Answer:

    SELECT TO_CHAR(order_date, 'YYYY-MM-DD') FROM orders; -> Option B
  4. Quick Check:

    TO_CHAR formats dates to strings [OK]
Hint: Use TO_CHAR to format dates as strings [OK]
Common Mistakes:
  • Using TO_STRING instead of TO_CHAR
  • Trying FORMAT_DATE which doesn't exist in Snowflake
  • Incorrect CAST syntax for formatting
3. Given the table sales with column amount, what is the result of this query?
SELECT SUM(amount) FROM sales WHERE amount > 100;
medium
A. Sum of amounts greater than 100
B. Average of amounts greater than 100
C. Count of rows where amount is greater than 100
D. Sum of all amounts including those less or equal to 100

Solution

  1. Step 1: Understand the WHERE clause effect

    The WHERE clause filters rows to only those with amount > 100.
  2. Step 2: Understand SUM function

    SUM adds all values of amount from the filtered rows.
  3. Final Answer:

    Sum of amounts greater than 100 -> Option A
  4. Quick Check:

    SUM with WHERE filters sums filtered rows [OK]
Hint: WHERE filters rows before SUM calculation [OK]
Common Mistakes:
  • Including amounts less or equal to 100
  • Confusing SUM with COUNT or AVG
  • Ignoring WHERE clause effect
4. What is wrong with this Snowflake query?
SELECT TO_CHAR(order_date, YYYY-MM-DD) FROM orders;
medium
A. The date format string is not enclosed in quotes
B. TO_CHAR cannot be used on dates
C. Missing FROM clause
D. TO_CHAR requires three arguments

Solution

  1. Step 1: Check TO_CHAR syntax

    The format string must be enclosed in single quotes, like 'YYYY-MM-DD'.
  2. Step 2: Identify the error in the query

    The query uses YYYY-MM-DD without quotes, causing a syntax error.
  3. Final Answer:

    The date format string is not enclosed in quotes -> Option A
  4. Quick Check:

    Format strings need quotes in TO_CHAR [OK]
Hint: Always quote format strings in TO_CHAR [OK]
Common Mistakes:
  • Forgetting quotes around format strings
  • Thinking TO_CHAR needs more arguments
  • Ignoring syntax errors from missing quotes
5. You want to find the average order amount rounded to 2 decimal places from the orders table. Which query correctly achieves this in Snowflake?
hard
A. SELECT AVG(ROUND(order_amount, 2)) FROM orders;
B. SELECT AVG(CAST(order_amount AS NUMBER(10,2))) FROM orders;
C. SELECT TO_CHAR(AVG(order_amount), '0.00') FROM orders;
D. SELECT ROUND(AVG(order_amount), 2) FROM orders;

Solution

  1. Step 1: Understand rounding average correctly

    Rounding the average after calculating it gives the correct average rounded to 2 decimals.
  2. Step 2: Analyze each option

    SELECT ROUND(AVG(order_amount), 2) FROM orders; rounds the AVG result, which is correct. SELECT AVG(ROUND(order_amount, 2)) FROM orders; rounds each value before averaging, which changes the result. SELECT TO_CHAR(AVG(order_amount), '0.00') FROM orders; converts to string, not numeric. SELECT AVG(CAST(order_amount AS NUMBER(10,2))) FROM orders; casts each value before averaging, which changes the result.
  3. Final Answer:

    SELECT ROUND(AVG(order_amount), 2) FROM orders; -> Option D
  4. Quick Check:

    Round after AVG for correct decimal rounding [OK]
Hint: Round the average, not individual values [OK]
Common Mistakes:
  • Rounding before averaging changes results
  • Using TO_CHAR instead of numeric rounding
  • Casting individuals before averaging changes results