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FLATTEN for nested data in Snowflake - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to flatten the nested array column named 'items'.

Snowflake
SELECT value FROM orders, LATERAL FLATTEN(input => [1]);
Drag options to blanks, or click blank then click option'
Aorders.items
Borders
Citems
Dorders.value
Attempts:
3 left
💡 Hint
Common Mistakes
Using the table name without the column.
Using just the column name without the table alias.
Using a non-array column as input.
2fill in blank
medium

Complete the code to extract the 'name' field from each element after flattening.

Snowflake
SELECT f.value:[1] AS item_name FROM orders, LATERAL FLATTEN(input => orders.items) f;
Drag options to blanks, or click blank then click option'
Aid
Bname
Cvalue
Dprice
Attempts:
3 left
💡 Hint
Common Mistakes
Using the wrong field name.
Omitting the colon before the field name.
Using 'value' instead of the actual field.
3fill in blank
hard

Fix the error in the code to correctly flatten the nested array 'products' in the 'sales' table.

Snowflake
SELECT s.id, f.value FROM sales s, LATERAL FLATTEN(input => s.[1]) f;
Drag options to blanks, or click blank then click option'
Aitems
Bproduct
Cproduct_list
Dproducts
Attempts:
3 left
💡 Hint
Common Mistakes
Using singular instead of plural column name.
Using a non-existent column.
Misspelling the column name.
4fill in blank
hard

Fill both blanks to flatten the 'details' array and extract the 'price' field.

Snowflake
SELECT f.value:[1] AS price FROM invoices, LATERAL FLATTEN(input => invoices.[2]) f;
Drag options to blanks, or click blank then click option'
Aprice
Bdetails
Camount
Ditems
Attempts:
3 left
💡 Hint
Common Mistakes
Mixing up the nested array column and the field name.
Using incorrect JSON path syntax.
Using wrong column names.
5fill in blank
hard

Fill all three blanks to flatten the 'attributes' array, extract 'color', and filter where 'size' is 'M'.

Snowflake
SELECT f.value:[1] AS color FROM products p, LATERAL FLATTEN(input => p.[2]) f WHERE f.value:[3] = 'M';
Drag options to blanks, or click blank then click option'
Acolor
Battributes
Csize
Ddetails
Attempts:
3 left
💡 Hint
Common Mistakes
Using wrong nested array name.
Confusing 'color' and 'size' fields.
Incorrect JSON path syntax.

Practice

(1/5)
1. What does the FLATTEN function do in Snowflake when working with nested data?
easy
A. It encrypts nested data for security.
B. It compresses data to save storage space.
C. It converts nested arrays or objects into simple rows.
D. It creates a backup of nested data.

Solution

  1. Step 1: Understand the purpose of FLATTEN

    FLATTEN is designed to take nested arrays or objects and turn them into individual rows so they are easier to query.
  2. Step 2: Compare options to FLATTEN's function

    Options A, B, and D describe encryption, compression, and backup, which are unrelated to FLATTEN's role.
  3. Final Answer:

    It converts nested arrays or objects into simple rows. -> Option C
  4. Quick Check:

    FLATTEN = convert nested data to rows [OK]
Hint: FLATTEN breaks nested data into rows for easy reading [OK]
Common Mistakes:
  • Thinking FLATTEN compresses or encrypts data
  • Confusing FLATTEN with backup or storage functions
  • Assuming FLATTEN changes data format instead of structure
2. Which of the following is the correct syntax to use FLATTEN on a JSON column named data in Snowflake?
easy
A. SELECT FLATTEN(data) FROM table;
B. SELECT * FROM FLATTEN(input => data);
C. SELECT FLATTEN(input = data) FROM table;
D. SELECT * FROM table, LATERAL FLATTEN(input => data);

Solution

  1. Step 1: Recall FLATTEN usage in FROM clause

    FLATTEN is used as a table function in the FROM clause with LATERAL to expand nested data.
  2. Step 2: Analyze each option's syntax

    SELECT * FROM table, LATERAL FLATTEN(input => data); correctly uses FROM table, LATERAL FLATTEN(input => data). Options A and C misuse FLATTEN as a scalar function. SELECT * FROM FLATTEN(input => data); misses the table reference.
  3. Final Answer:

    SELECT * FROM table, LATERAL FLATTEN(input => data); -> Option D
  4. Quick Check:

    FLATTEN used with LATERAL in FROM clause [OK]
Hint: Use FLATTEN with LATERAL in FROM clause for nested data [OK]
Common Mistakes:
  • Using FLATTEN as a scalar function in SELECT
  • Omitting LATERAL keyword
  • Not specifying input parameter correctly
3. Given the JSON column data with value '{"items": ["apple", "banana", "cherry"]}', what will the query below return?
SELECT f.value FROM table, LATERAL FLATTEN(input => data:items) f;
medium
A. Rows with values: apple, banana, cherry
B. A single row with the entire array as a string
C. An error because data:items is invalid syntax
D. Rows with keys and values of the JSON object

Solution

  1. Step 1: Understand FLATTEN on JSON array

    FLATTEN(input => data:items) expands the array under 'items' into multiple rows, each with one element.
  2. Step 2: Analyze the query output

    The query selects f.value, which will be each element: 'apple', 'banana', 'cherry' as separate rows.
  3. Final Answer:

    Rows with values: apple, banana, cherry -> Option A
  4. Quick Check:

    FLATTEN on array returns each element as a row [OK]
Hint: FLATTEN on JSON array returns each element as a separate row [OK]
Common Mistakes:
  • Expecting a single row with the whole array
  • Confusing keys with values in FLATTEN output
  • Misreading JSON path syntax
4. You wrote this query to flatten nested JSON data:
SELECT f.value FROM table, FLATTEN(input => data:items) f;

But it returns an error. What is the likely cause?
medium
A. Missing LATERAL keyword before FLATTEN
B. Incorrect JSON path syntax in input
C. FLATTEN cannot be used on JSON arrays
D. SELECT statement missing WHERE clause

Solution

  1. Step 1: Identify FLATTEN usage requirements

    FLATTEN is a table function that requires LATERAL when used with another table to expand nested data.
  2. Step 2: Check query syntax

    The query misses the LATERAL keyword before FLATTEN, causing a syntax error.
  3. Final Answer:

    Missing LATERAL keyword before FLATTEN -> Option A
  4. Quick Check:

    FLATTEN needs LATERAL in FROM clause [OK]
Hint: Always add LATERAL before FLATTEN in FROM clause [OK]
Common Mistakes:
  • Forgetting LATERAL keyword
  • Assuming FLATTEN works without LATERAL
  • Blaming JSON path syntax instead of syntax structure
5. You have a table with a column orders storing nested JSON arrays of items per order. You want to list each item with its order ID. Which query correctly uses FLATTEN to achieve this?
hard
A. SELECT order_id, FLATTEN(orders) FROM orders_table;
B. SELECT order_id, f.value FROM orders_table, LATERAL FLATTEN(input => orders) f;
C. SELECT order_id, f.value FROM orders_table JOIN FLATTEN(input => orders) f ON TRUE;
D. SELECT order_id, f.value FROM orders_table, FLATTEN(orders) f;

Solution

  1. Step 1: Understand how to join FLATTEN with table

    FLATTEN must be used with LATERAL in the FROM clause to expand nested arrays per row.
  2. Step 2: Evaluate each option's correctness

    SELECT order_id, f.value FROM orders_table, LATERAL FLATTEN(input => orders) f; correctly uses FROM orders_table, LATERAL FLATTEN(input => orders) f, selecting order_id and each item value. Options A and D misuse FLATTEN syntax. SELECT order_id, f.value FROM orders_table JOIN FLATTEN(input => orders) f ON TRUE; uses JOIN incorrectly without LATERAL.
  3. Final Answer:

    SELECT order_id, f.value FROM orders_table, LATERAL FLATTEN(input => orders) f; -> Option B
  4. Quick Check:

    Use LATERAL FLATTEN with table to list nested items [OK]
Hint: Use LATERAL FLATTEN(input => column) to expand nested arrays per row [OK]
Common Mistakes:
  • Using FLATTEN without LATERAL
  • Trying to JOIN FLATTEN without LATERAL
  • Incorrect FLATTEN syntax in SELECT clause