You switch back by calling driver.switch_to.window(original_handle) where original_handle is the saved handle of the first window.
What exception might occur if you try to interact with elements in a window you haven't switched to?
ATimeoutException
BNoSuchElementException
CValueError
DIndexError
✗ Incorrect
Trying to interact with elements in a non-focused window usually causes a NoSuchElementException.
Why is it useful to store the original window handle before switching?
ATo open a new tab
BTo close the original window automatically
CTo refresh the original window
DTo switch back easily after working with other windows
✗ Incorrect
Storing the original window handle lets you switch back to it later without confusion.
Explain the steps to switch from the original browser window to a newly opened window using Selenium Python.
Think about how you identify and switch to a different window.
You got /4 concepts.
Why must you switch back to the original window after finishing actions on a new window in Selenium tests?
Consider what happens if Selenium tries to find elements in the wrong window.
You got /3 concepts.
Practice
(1/5)
1. What does driver.switch_to.window(window_handle) do in Selenium?
easy
A. It closes the current browser window.
B. It changes control to the browser window identified by window_handle.
C. It refreshes the current browser window.
D. It opens a new browser window.
Solution
Step 1: Understand the method purpose
driver.switch_to.window() is used to change Selenium's focus to a different browser window or tab.
Step 2: Identify the parameter role
The parameter window_handle specifies which window Selenium should control next.
Final Answer:
It changes control to the browser window identified by window_handle. -> Option B
Quick Check:
Switching windows = change control [OK]
Hint: Switch windows by passing the window handle to switch_to.window() [OK]
Common Mistakes:
Thinking it closes or refreshes windows
Confusing switching with opening new windows
Not passing a valid window handle
2. Which of the following is the correct syntax to switch to a new window stored in variable new_window?
easy
A. driver.window_switch(new_window)
B. driver.switch_window(new_window)
C. driver.switchTo().window(new_window)
D. driver.switch_to.window(new_window)
Solution
Step 1: Recall correct Selenium Python syntax
The correct method to switch windows is driver.switch_to.window() in Python Selenium.
Step 2: Match the syntax with the options
driver.switch_to.window(new_window) uses the correct method and parameter. Other options use incorrect method names or Java syntax.
Final Answer:
driver.switch_to.window(new_window) -> Option D
Quick Check:
Python Selenium uses switch_to.window() [OK]
Hint: Use driver.switch_to.window(handle) exactly in Python [OK]
Common Mistakes:
Using Java syntax like switchTo()
Using incorrect method names
Missing the switch_to part
3. What will be the output of the following code snippet?
original = driver.current_window_handle
all_windows = driver.window_handles
for w in all_windows:
if w != original:
driver.switch_to.window(w)
print(driver.title)
break
print(driver.current_window_handle == original)
medium
A. Prints the title of the new window and then prints False
B. Prints the title of the original window and then prints True
C. Throws an error because of wrong window handle usage
D. Prints False twice
Solution
Step 1: Understand window handles and switching
The code saves the original window handle, loops through all windows, and switches to the first window that is not original.
Step 2: Analyze the print statements
Inside the loop, it prints the title of the new window and breaks. After the loop, it compares current window handle with original, which will be False because we switched.
Final Answer:
Prints the title of the new window and then prints False -> Option A
Quick Check:
Switched window title + current handle != original = False [OK]
Hint: Switch changes current handle, so comparison with original is False [OK]
Common Mistakes:
Assuming current window handle is still original after switch
Confusing window_handles list with current_window_handle
Expecting True after switching
4. Identify the error in this code snippet that tries to switch back to the original window:
original = driver.current_window_handle
# code opens new window
new_window = driver.window_handles[1]
driver.switch_to.window(new_window)
# some actions
# switch back
switch_to.window(original)
medium
A. Cannot switch back once switched
B. Using wrong index for new_window
C. Missing 'driver.' before switch_to.window in last line
D. No error, code is correct
Solution
Step 1: Check the last line syntax
The last line calls switch_to.window(original) without the driver. prefix, which causes a NameError.
Step 2: Confirm other parts are correct
Index 1 is valid if two windows exist, switching back is allowed, so no other errors.
Final Answer:
Missing 'driver.' before switch_to.window in last line -> Option C
Quick Check:
Always prefix with driver.switch_to.window() [OK]
Hint: Always use driver.switch_to.window() fully [OK]
Common Mistakes:
Forgetting 'driver.' before switch_to
Assuming switch back is automatic
Using wrong window handle index without checking
5. You have opened multiple tabs during a test. How do you switch back to the original tab after performing actions on others?
hard
A. Store the original window handle before switching, then use driver.switch_to.window(original_handle) to return.
B. Call driver.close() on all other tabs to return automatically.
C. Use driver.switch_to.default_window() to go back to the first tab.
D. Restart the browser to return to the original tab.
Solution
Step 1: Save the original window handle
Before switching tabs, save the current window handle in a variable.
Step 2: Switch back using saved handle
Use driver.switch_to.window(original_handle) to return control to the original tab.
Step 3: Evaluate other options
Closing tabs or restarting browser is inefficient; default_window() does not exist in Selenium Python.
Final Answer:
Store the original window handle before switching, then use driver.switch_to.window(original_handle) to return. -> Option A
Quick Check:
Save handle, then switch back using it [OK]
Hint: Always save original handle to switch back later [OK]
Common Mistakes:
Trying to use non-existent default_window() method
Closing tabs instead of switching
Restarting browser unnecessarily
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