Simple alert acceptance in Selenium Python - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to accept a simple alert popup.

Selenium Python

alert = driver.switch_to.alert
alert.[1]()

Drag options to blanks, or click blank then click option'

Adismiss

Bsend_keys

Ctext

Daccept

Attempts:

3 left

💡 Hint

Common Mistakes

Using dismiss() instead of accept() will cancel the alert.

Trying to send keys to a simple alert causes an error.

The accept() method clicks the OK button on the alert popup.

2fill in blank

medium

Complete the code to switch to the alert before accepting it.

Selenium Python

driver.[1].alert.accept()

Drag options to blanks, or click blank then click option'

Afind_element

Bswitch_to

Cexecute_script

Dget

Attempts:

3 left

💡 Hint

Common Mistakes

Using find_element tries to find a page element, not an alert.

execute_script runs JavaScript but does not switch focus.

The switch_to property allows switching the driver's focus to the alert popup.

3fill in blank

hard

Fix the error in the code to accept the alert correctly.

Selenium Python

alert = driver.switch_to.[1]
alert.accept()

Drag options to blanks, or click blank then click option'

Aalert

Balert()

Calerts

Dswitch

Attempts:

3 left

💡 Hint

Common Mistakes

Adding parentheses after alert causes a TypeError.

Using 'alerts' or 'switch' are invalid attributes.

The alert is a property, not a method, so no parentheses are needed.

4fill in blank

hard

Fill both blanks to switch to the alert and get its text.

Selenium Python

alert = driver.[1].[2]
text = alert.text

Drag options to blanks, or click blank then click option'

Aswitch_to

Bfind_element

Calert

Dalerts

Attempts:

3 left

💡 Hint

Common Mistakes

Using find_element instead of switch_to.

Using 'alerts' instead of 'alert'.

You switch to the alert using switch_to and access the alert with alert.

5fill in blank

hard

Fill all three blanks to switch to the alert, get its text, and accept it.

Selenium Python

alert = driver.[1].[2]
message = alert.[3]
alert.accept()

Drag options to blanks, or click blank then click option'

Aswitch_to

Btext

Calert

Ddismiss

Attempts:

3 left

💡 Hint

Common Mistakes

Using dismiss() instead of accept() to close the alert.

Trying to call text() as a method instead of accessing it as a property.

Switch to the alert, access the alert property, then get its text using text.

Practice

1. What does the driver.switch_to.alert.accept() command do in Selenium Python?

easy

A. It closes the browser window.

B. It refreshes the current page.

C. It clicks the OK button on a simple alert popup.

D. It sends text input to the alert popup.

Solution

1. Step 1: Understand alert handling in Selenium

   The driver.switch_to.alert accesses the alert popup currently shown by the browser.

2. Step 2: Accepting the alert

   The accept() method clicks the OK button on the alert, closing it.

3. Final Answer:

   It clicks the OK button on a simple alert popup. -> Option C

4. Quick Check:

   accept() = clicks OK [OK]

Hint: accept() always clicks OK on alert popups [OK]

Common Mistakes:

• Confusing accept() with dismiss() which clicks Cancel
• Trying to send keys with accept()
• Assuming accept() closes the browser

2. Which of the following is the correct syntax to accept a simple alert in Selenium Python?

easy

A. driver.alert.accept()

B. driver.switch_to.alert.accept()

C. driver.switch_to_alert.accept()

D. driver.switchTo().alert().accept()

Solution

1. Step 1: Recall correct Selenium Python syntax

   The correct way to switch to alert is driver.switch_to.alert.

2. Step 2: Confirm method chaining

   Calling accept() on the alert object accepts the alert.

3. Final Answer:

   driver.switch_to.alert.accept() -> Option B

4. Quick Check:

   Correct syntax = driver.switch_to.alert.accept() [OK]

Hint: Use driver.switch_to.alert.accept() to accept alerts [OK]

Common Mistakes:

• Using Java-style syntax like switchTo()
• Missing the switch_to part
• Using underscores incorrectly in method names

3. What will happen when the following code runs if a simple alert is present?

driver.switch_to.alert.accept()
print("Alert accepted")

medium

A. The alert is accepted but nothing is printed.

B. The alert is ignored and 'Alert accepted' is printed.

C. An exception is thrown because alert is not handled.

D. The alert is accepted and 'Alert accepted' is printed.

Solution

1. Step 1: Accept the alert

   The accept() method clicks OK on the alert, closing it.

2. Step 2: Print confirmation

   After alert is accepted, the print statement runs and outputs the message.

3. Final Answer:

   The alert is accepted and 'Alert accepted' is printed. -> Option D

4. Quick Check:

   alert.accept() then print = alert accepted message [OK]

Hint: accept() closes alert, next lines run normally [OK]

Common Mistakes:

• Thinking alert is ignored without accept()
• Expecting print before alert is accepted
• Assuming exception if alert is present

4. Identify the error in this code snippet for accepting an alert:

alert = driver.switch_to.alert
alert.accept

medium

A. Missing parentheses after accept method call.

B. Incorrect alert switching syntax.

C. alert variable name is reserved.

D. accept() should be called on driver, not alert.

Solution

1. Step 1: Check method call syntax

   The accept method must be called with parentheses accept() to execute.

2. Step 2: Identify missing parentheses

   Without parentheses, alert.accept is just a reference, not a call, so alert is not accepted.

3. Final Answer:

   Missing parentheses after accept method call. -> Option A

4. Quick Check:

   Method calls need () to run [OK]

Hint: Always add () to call methods like accept() [OK]

Common Mistakes:

• Forgetting parentheses on method calls
• Using wrong variable names
• Calling accept() on driver instead of alert

5. You want to accept a simple alert only if it is present, without causing an error if no alert shows. Which code snippet correctly does this?

hard

A. try:
driver.switch_to.alert.accept()
except:
pass

B. if driver.switch_to.alert:
driver.switch_to.alert.accept()

C. driver.switch_to.alert.accept() if alert else None

D. driver.switch_to.alert.accept()

Solution

1. Step 1: Understand alert presence check

   Selenium throws an exception if alert is not present, so we must catch it.

2. Step 2: Use try-except to accept alert safely

   Wrapping accept() in try-except avoids errors if alert is missing.

3. Final Answer:

   try: driver.switch_to.alert.accept() except: pass -> Option A

4. Quick Check:

   Use try-except to handle optional alerts [OK]

Hint: Wrap alert accept in try-except to avoid errors [OK]

Common Mistakes:

• Checking alert presence with if directly
• Calling accept() without error handling
• Using undefined alert variable