File upload handling in Selenium Python - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to locate the file input element by its ID.

Selenium Python

file_input = driver.find_element(By.[1]("upload"))

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AID

BNAME

CCLASS_NAME

DTAG_NAME

Attempts:

3 left

💡 Hint

Common Mistakes

Using By.NAME or other locators when the element has an ID.

The ID locator is used to find the file input element with ID "upload".

2fill in blank

medium

Complete the code to upload a file by sending the file path to the input element.

Selenium Python

file_input.send_keys([1])

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Aopen('file.txt')

Bdriver.upload("file.txt")

Cupload_file()

D"/path/to/file.txt"

Attempts:

3 left

💡 Hint

Common Mistakes

Trying to open the file or call upload functions instead of sending the path string.

To upload a file, send the file path as a string to the file input element using send_keys.

3fill in blank

hard

Fix the error in the code to correctly wait for the file input element to be visible before uploading.

Selenium Python

wait = WebDriverWait(driver, 10)
file_input = wait.until(EC.[1]((By.ID, "upload")))

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Aelement_to_be_clickable

Bpresence_of_element_located

Cvisibility_of_element_located

Delement_to_be_selected

Attempts:

3 left

💡 Hint

Common Mistakes

Using presence_of_element_located which does not guarantee visibility.

visibility_of_element_located waits until the element is visible on the page, which is needed before sending keys.

4fill in blank

hard

Complete the code to create a dictionary comprehension that maps file names to their upload status if the file size is greater than 0.

Selenium Python

upload_status = {file: file for file in files if os.path.getsize(file) [1] 0}

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A:

B>

C==

D<

Attempts:

3 left

💡 Hint

Common Mistakes

Using == or < instead of > for file size check.

The colon : separates keys and values in the dictionary, and > checks if file size is greater than zero.

5fill in blank

hard

Fill all three blanks to create a test that asserts the upload success message contains the uploaded file name.

Selenium Python

assert [1] in driver.find_element(By.ID, "upload_message").[2].[3]()

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Afile_name

Btext

Clower

Dget_attribute

Attempts:

3 left

💡 Hint

Common Mistakes

Using get_attribute instead of text, or forgetting to lowercase the text.

The test checks if file_name is in the lowercased text content of the upload message element.