Opening URLs (get) in Selenium Python - Cheat Sheet & Quick Revision

Recall & Review

beginner

What does the get() method do in Selenium WebDriver?

The get() method opens a specified URL in the browser controlled by Selenium WebDriver.

beginner

How do you open the URL https://example.com using Selenium in Python?

Use driver.get('https://example.com') where driver is your WebDriver instance.

intermediate

Why is it important to wait after opening a URL with get() before interacting with page elements?

Because the page needs time to load fully. Waiting ensures elements are present and interactable, preventing errors.

intermediate

What happens if you call get() with an invalid URL?

The browser tries to open it but may show an error page. Selenium does not throw an exception for invalid URLs by default.

beginner

Can you use get() to navigate to a new page after the browser is already open?

Yes, calling get() again will navigate the browser to the new URL, replacing the current page.

What is the correct way to open a URL using Selenium WebDriver in Python?

A driver.get('https://example.com')

B driver.open('https://example.com')

C driver.navigate('https://example.com')

D driver.load('https://example.com')

The get() method is used to open URLs in Selenium WebDriver.

What does Selenium do if you call get() with a URL that does not exist?

A Throws an exception immediately

B Retries loading the URL automatically

C Closes the browser

D Opens the browser and shows an error page

Selenium opens the browser and the browser shows an error page if the URL is invalid; Selenium itself does not throw an error.

Which of these is a good practice after calling get() before interacting with page elements?

A Close the browser

B Immediately click elements without waiting

C Wait for the page to load or elements to appear

D Refresh the page twice

Waiting ensures the page and elements are fully loaded to avoid errors.

Can you use get() multiple times in the same test script?

A No, only once per browser session

B Yes, to navigate to different URLs

C Only if you restart the browser

D Only for URLs on the same domain

get() can be called multiple times to open different URLs during a test.

What type of argument does get() accept?

A A string representing the URL

B An integer representing timeout

C A boolean to refresh page

D A list of URLs

get() requires a string URL to open in the browser.

Explain how to open a webpage using Selenium WebDriver in Python and why waiting after opening is important.

Think about what happens after you open a website in a real browser.

Describe what happens if you use get() with an invalid URL in Selenium.

Consider how a normal browser behaves with a wrong address.

Practice

1. What does the Selenium command driver.get(url) do in a test script?

easy

A. It refreshes the current page.

B. It opens the specified URL in the browser controlled by Selenium.

C. It closes the browser window.

D. It finds an element on the page.

Solution

1. Step 1: Understand the purpose of driver.get(url)

   This command tells Selenium to open a web page at the given URL in the browser it controls.

2. Step 2: Compare with other commands

   Closing the browser is done by driver.quit(), refreshing by driver.refresh(), and finding elements by driver.find_element().

3. Final Answer:

   It opens the specified URL in the browser controlled by Selenium. -> Option B

4. Quick Check:

   driver.get(url) opens URL [OK]

Hint: Remember: get() means open URL in browser [OK]

Common Mistakes:

• Confusing get() with close() or quit()
• Thinking get() refreshes the page
• Assuming get() finds elements

2. Which of the following is the correct syntax to open the URL "https://example.com" using Selenium WebDriver in Python?

easy

A. driver.open("https://example.com")

B. driver.navigate("https://example.com")

C. driver.get("https://example.com")

D. driver.load_url("https://example.com")

Solution

1. Step 1: Recall the correct method to open a URL

   The Selenium WebDriver method to open a URL is get(), used as driver.get(url).

2. Step 2: Check the syntax of each option

   Only driver.get("https://example.com") uses the correct method name and syntax. The others use invalid method names.

3. Final Answer:

   driver.get("https://example.com") -> Option C

4. Quick Check:

   Correct method is get() [OK]

Hint: Use driver.get() to open URLs, not open() or navigate() [OK]

Common Mistakes:

• Using driver.open() instead of driver.get()
• Forgetting to put URL in quotes
• Using incorrect method names

3. What will happen when the following Selenium Python code runs?

from selenium import webdriver

driver = webdriver.Chrome()
driver.get("https://www.google.com")
print(driver.title)
driver.quit()

medium

A. It opens Google homepage, prints the page title, then closes the browser.

B. It throws a syntax error because of missing parentheses.

C. It opens the browser but does not navigate to any page.

D. It opens Google homepage but does not close the browser.

Solution

1. Step 1: Analyze the code step-by-step

   The code creates a Chrome browser instance, opens Google's homepage with get(), prints the page title, then closes the browser with quit().

2. Step 2: Check for errors or missing parts

   All syntax is correct, and the browser is properly closed at the end.

3. Final Answer:

   It opens Google homepage, prints the page title, then closes the browser. -> Option A

4. Quick Check:

   driver.get() opens URL, driver.quit() closes browser [OK]

Hint: driver.get() opens URL; driver.quit() closes browser [OK]

Common Mistakes:

• Forgetting to call driver.quit() to close browser
• Assuming print(driver.title) prints URL
• Confusing syntax errors with correct code

4. Identify the error in this Selenium Python code snippet:

from selenium import webdriver

driver = webdriver.Firefox()
driver.get("www.example.com")
driver.quit()

medium

A. The get() method requires two arguments.

B. webdriver.Firefox() is not a valid WebDriver.

C. driver.quit() should be called before driver.get().

D. The URL is missing the protocol (http:// or https://).

Solution

1. Step 1: Check the URL format in driver.get()

   The URL "www.example.com" lacks the protocol prefix like "http://" or "https://", which is required for Selenium to open it correctly.

2. Step 2: Verify other parts of the code

   webdriver.Firefox() is valid, driver.quit() is correctly placed after get(), and get() takes only one argument.

3. Final Answer:

   The URL is missing the protocol (http:// or https://). -> Option D

4. Quick Check:

   URL must include protocol [OK]

Hint: Always include http:// or https:// in URLs [OK]

Common Mistakes:

• Omitting protocol in URL
• Calling quit() before get()
• Thinking get() needs multiple arguments

5. You want to write a Selenium test that opens two URLs one after another in the same browser session. Which code snippet correctly does this?

hard

A. driver.get("https://first.com")
driver.get("https://second.com")
driver.quit()

B. driver.get("https://first.com")
driver.quit()
driver.get("https://second.com")

C. driver.open("https://first.com")
driver.get("https://second.com")
driver.quit()

D. driver.navigate("https://first.com")
driver.navigate("https://second.com")
driver.quit()

Solution

1. Step 1: Understand how to open multiple URLs in one session

   Calling driver.get() multiple times in a row opens each URL sequentially in the same browser window.

2. Step 2: Check each option for correctness

   driver.get("https://first.com") driver.get("https://second.com") driver.quit() correctly calls get() twice before quitting. driver.get("https://first.com") driver.quit() driver.get("https://second.com") quits before second get(), which closes browser early. Options A and C use invalid methods.

3. Final Answer:

   driver.get("https://first.com") driver.get("https://second.com") driver.quit() -> Option A

4. Quick Check:

   Multiple get() calls open URLs sequentially [OK]

Hint: Use multiple driver.get() calls before driver.quit() [OK]

Common Mistakes:

• Calling driver.quit() before opening all URLs
• Using invalid methods like open() or navigate()
• Assuming get() opens new tabs automatically