Opening URLs (get) in Selenium Python - Practice Problems & Coding Challenges

Challenge - 5 Problems

❓ Predict Output

intermediate

What is the output of this Selenium code snippet?

Consider the following Python Selenium code that opens a URL and prints the current URL.
What will be printed?

Selenium Python

from selenium import webdriver
from selenium.webdriver.chrome.service import Service
from selenium.webdriver.chrome.options import Options

options = Options()
options.add_argument('--headless')
service = Service()
driver = webdriver.Chrome(service=service, options=options)
driver.get('https://example.com')
print(driver.current_url)
driver.quit()

A about:blank

B https://example.com

C https://example.com/

D Raises NoSuchWindowException

💡 Hint

The browser normalizes URLs and often adds a trailing slash for root domains.

When Selenium opens 'https://example.com', the browser adds a trailing slash, so current_url returns 'https://example.com/'.

❓ assertion

intermediate

Which assertion correctly verifies the page title after opening a URL?

You want to check that after opening 'https://example.com', the page title is exactly 'Example Domain'. Which assertion is correct?

Selenium Python

driver.get('https://example.com')
# Which assertion below is correct?

A assert driver.title = 'Example Domain'

B assert driver.title == 'Example Domain'

C assert driver.title != 'Example Domain'

D assert driver.title.contains('Example Domain')

💡 Hint

Use '==' to compare values in Python assertions.

Option B correctly uses '==' to compare the title string. Option B uses assignment (=) which is invalid in assert. Option B asserts the opposite. Option B uses a method that does not exist on string.

❓ locator

advanced

Which locator is best to find the main heading after opening a URL?

After opening 'https://example.com', you want to locate the main heading <h1> element. Which locator is best practice?

Selenium Python

driver.get('https://example.com')
# Choose the best locator to find the main heading

A driver.find_element('tag name', 'h1')

B driver.find_element('css selector', 'div > h1')

C driver.find_element('xpath', '//div/h1')

D driver.find_element('id', 'main-heading')

💡 Hint

Use simple and direct locators when possible.

Option A uses the tag name locator directly for the h1 element, which is simple and reliable here. Option A and C depend on div structure which may change. Option A fails because no element has id 'main-heading'.

🔧 Debug

advanced

Why does this Selenium code raise an error when opening a URL?

Examine the code below. It raises an error when trying to open the URL. What is the cause?

Selenium Python

from selenium import webdriver

driver = webdriver.Chrome()
driver.get('htp://example.com')
driver.quit()

A The URL scheme 'htp' is invalid, causing a WebDriverException

B The Chrome driver is not initialized properly

C driver.quit() is called too early

D driver.get() requires a file path, not a URL

💡 Hint

Check the URL spelling carefully.

The URL scheme 'htp' is a typo and invalid. Selenium raises an error because it cannot navigate to an invalid URL.

❓ framework

expert

In a pytest Selenium test, which fixture setup ensures the browser opens the URL before each test?

You want to write a pytest fixture that opens 'https://example.com' before each test and closes the browser after. Which fixture code is correct?

A

import pytest
from selenium import webdriver

@pytest.fixture
async def driver():
    driver = webdriver.Chrome()
    driver.get('https://example.com')
    yield driver
    driver.quit()

B

import pytest
from selenium import webdriver

@pytest.fixture

def driver():
    driver = webdriver.Chrome()
    yield driver
    driver.quit()

C

import pytest
from selenium import webdriver

@pytest.fixture
async def driver():
    driver = webdriver.Chrome()
    yield driver
    driver.quit()

D

import pytest
from selenium import webdriver

@pytest.fixture

def driver():
    driver = webdriver.Chrome()
    driver.get('https://example.com')
    yield driver
    driver.quit()

💡 Hint

Pytest fixtures are usually synchronous unless using async tests.

Option D correctly defines a synchronous fixture that opens the URL before yielding the driver and quits after. Options B and C use 'async def' which is invalid here. Option D does not open the URL before yielding.

Practice

1. What does the Selenium command driver.get(url) do in a test script?

easy

A. It refreshes the current page.

B. It opens the specified URL in the browser controlled by Selenium.

C. It closes the browser window.

D. It finds an element on the page.

Solution

1. Step 1: Understand the purpose of driver.get(url)

   This command tells Selenium to open a web page at the given URL in the browser it controls.

2. Step 2: Compare with other commands

   Closing the browser is done by driver.quit(), refreshing by driver.refresh(), and finding elements by driver.find_element().

3. Final Answer:

   It opens the specified URL in the browser controlled by Selenium. -> Option B

4. Quick Check:

   driver.get(url) opens URL [OK]

Hint: Remember: get() means open URL in browser [OK]

Common Mistakes:

• Confusing get() with close() or quit()
• Thinking get() refreshes the page
• Assuming get() finds elements

2. Which of the following is the correct syntax to open the URL "https://example.com" using Selenium WebDriver in Python?

easy

A. driver.open("https://example.com")

B. driver.navigate("https://example.com")

C. driver.get("https://example.com")

D. driver.load_url("https://example.com")

Solution

1. Step 1: Recall the correct method to open a URL

   The Selenium WebDriver method to open a URL is get(), used as driver.get(url).

2. Step 2: Check the syntax of each option

   Only driver.get("https://example.com") uses the correct method name and syntax. The others use invalid method names.

3. Final Answer:

   driver.get("https://example.com") -> Option C

4. Quick Check:

   Correct method is get() [OK]

Hint: Use driver.get() to open URLs, not open() or navigate() [OK]

Common Mistakes:

• Using driver.open() instead of driver.get()
• Forgetting to put URL in quotes
• Using incorrect method names

3. What will happen when the following Selenium Python code runs?

from selenium import webdriver

driver = webdriver.Chrome()
driver.get("https://www.google.com")
print(driver.title)
driver.quit()

medium

A. It opens Google homepage, prints the page title, then closes the browser.

B. It throws a syntax error because of missing parentheses.

C. It opens the browser but does not navigate to any page.

D. It opens Google homepage but does not close the browser.

Solution

1. Step 1: Analyze the code step-by-step

   The code creates a Chrome browser instance, opens Google's homepage with get(), prints the page title, then closes the browser with quit().

2. Step 2: Check for errors or missing parts

   All syntax is correct, and the browser is properly closed at the end.

3. Final Answer:

   It opens Google homepage, prints the page title, then closes the browser. -> Option A

4. Quick Check:

   driver.get() opens URL, driver.quit() closes browser [OK]

Hint: driver.get() opens URL; driver.quit() closes browser [OK]

Common Mistakes:

• Forgetting to call driver.quit() to close browser
• Assuming print(driver.title) prints URL
• Confusing syntax errors with correct code

4. Identify the error in this Selenium Python code snippet:

from selenium import webdriver

driver = webdriver.Firefox()
driver.get("www.example.com")
driver.quit()

medium

A. The get() method requires two arguments.

B. webdriver.Firefox() is not a valid WebDriver.

C. driver.quit() should be called before driver.get().

D. The URL is missing the protocol (http:// or https://).

Solution

1. Step 1: Check the URL format in driver.get()

   The URL "www.example.com" lacks the protocol prefix like "http://" or "https://", which is required for Selenium to open it correctly.

2. Step 2: Verify other parts of the code

   webdriver.Firefox() is valid, driver.quit() is correctly placed after get(), and get() takes only one argument.

3. Final Answer:

   The URL is missing the protocol (http:// or https://). -> Option D

4. Quick Check:

   URL must include protocol [OK]

Hint: Always include http:// or https:// in URLs [OK]

Common Mistakes:

• Omitting protocol in URL
• Calling quit() before get()
• Thinking get() needs multiple arguments

5. You want to write a Selenium test that opens two URLs one after another in the same browser session. Which code snippet correctly does this?

hard

A. driver.get("https://first.com")
driver.get("https://second.com")
driver.quit()

B. driver.get("https://first.com")
driver.quit()
driver.get("https://second.com")

C. driver.open("https://first.com")
driver.get("https://second.com")
driver.quit()

D. driver.navigate("https://first.com")
driver.navigate("https://second.com")
driver.quit()

Solution

1. Step 1: Understand how to open multiple URLs in one session

   Calling driver.get() multiple times in a row opens each URL sequentially in the same browser window.

2. Step 2: Check each option for correctness

   driver.get("https://first.com") driver.get("https://second.com") driver.quit() correctly calls get() twice before quitting. driver.get("https://first.com") driver.quit() driver.get("https://second.com") quits before second get(), which closes browser early. Options A and C use invalid methods.

3. Final Answer:

   driver.get("https://first.com") driver.get("https://second.com") driver.quit() -> Option A

4. Quick Check:

   Multiple get() calls open URLs sequentially [OK]

Hint: Use multiple driver.get() calls before driver.quit() [OK]

Common Mistakes:

• Calling driver.quit() before opening all URLs
• Using invalid methods like open() or navigate()
• Assuming get() opens new tabs automatically