Find element by XPath in Selenium Python - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to find an element by XPath using Selenium.

Selenium Python

element = driver.find_element_by_[1]("//button[@id='submit']")

Drag options to blanks, or click blank then click option'

Axpath

Bid

Ccss_selector

Dname

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'id' or 'name' instead of 'xpath' when the locator is an XPath expression.

Misspelling the method name.

The method find_element_by_xpath is used to locate elements using XPath expressions.

2fill in blank

medium

Complete the code to find an element by XPath that contains specific text.

Selenium Python

element = driver.find_element_by_xpath("//div[contains(text(), '[1]')]")

Drag options to blanks, or click blank then click option'

ACancel

BClick me

CSubmit

DHome

Attempts:

3 left

💡 Hint

Common Mistakes

Using incorrect text that does not exist in the element.

Forgetting to put the text inside quotes.

The XPath expression uses contains(text(), 'Submit') to find a div element containing the text 'Submit'.

3fill in blank

hard

Fix the error in the code to correctly find an element by XPath.

Selenium Python

element = driver.find_element_by_xpath("//input[@type='[1]']")

Drag options to blanks, or click blank then click option'

Asubmit

Bbutton

Ccheckbox

Dtext

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'button' instead of 'submit' for the type attribute.

Using 'text' which selects text input fields, not submit buttons.

The correct XPath attribute value for a submit button input is type='submit'.

4fill in blank

hard

Fill both blanks to create a dictionary comprehension that maps element texts to their XPath using Selenium.

Selenium Python

elements = driver.find_elements_by_xpath("//a")
links = {el.text: el.get_attribute([1]) for el in elements if el.text [2] ''}

Drag options to blanks, or click blank then click option'

A"href"

B!=

C==

D"src"

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'src' attribute which is for images, not links.

Using '==' instead of '!=' which would select empty text elements.

The attribute to get the link URL is 'href'. The condition el.text != '' filters out elements without visible text.

5fill in blank

hard

Fill all three blanks to create a dictionary comprehension that maps uppercase element texts to their href attribute if href contains 'example'.

Selenium Python

elements = driver.find_elements_by_xpath("//a")
filtered_links = {el.text[1](): el.get_attribute([2]) for el in elements if el.get_attribute([3]) and 'example' in el.get_attribute('href')}

Drag options to blanks, or click blank then click option'

A.upper

B"href"

D.lower

Attempts:

3 left

💡 Hint

Common Mistakes

Using '.lower()' instead of '.upper()' when uppercase is required.

Checking a wrong attribute name in the condition.

The .upper() method converts text to uppercase. The attribute to get is 'href'. The condition checks if 'href' attribute exists before filtering.

Practice

1. What does the following Selenium Python code do?
driver.find_element(By.XPATH, "//button[@id='submit']")

easy

A. Finds the button element by its class name 'submit'

B. Finds all button elements with id 'submit' on the page

C. Clicks the button with id 'submit'

D. Finds the first button element with id 'submit' on the page

Solution

1. Step 1: Understand the method used

   The method find_element returns the first matching element found by the locator.

2. Step 2: Analyze the XPath expression

   The XPath //button[@id='submit'] selects button elements with attribute id='submit'.

3. Final Answer:

   Finds the first button element with id 'submit' on the page -> Option D

4. Quick Check:

   find_element + XPath with id attribute = first matching element [OK]

Hint: find_element finds only the first matching element [OK]

Common Mistakes:

• Confusing find_element with find_elements
• Thinking XPath finds by class instead of id
• Assuming it clicks the element automatically

2. Which of the following is the correct syntax to find an element by XPath in Selenium Python?

easy

A. driver.find_element(By.XPATH, "//div[@class='header']")

B. driver.find_element_by_xpath("//div[@class='header']")

C. driver.find_element(By.CSS_SELECTOR, "//div[@class='header']")

D. driver.find_element(By.ID, "//div[@class='header']")

Solution

1. Step 1: Recall the modern Selenium syntax

   Since Selenium 4, the recommended way is driver.find_element(By.XPATH, xpath_string).

2. Step 2: Check each option

   driver.find_element(By.XPATH, "//div[@class='header']") uses the correct syntax. driver.find_element_by_xpath("//div[@class='header']") is deprecated. Options C and D use wrong locator types for XPath.

3. Final Answer:

   driver.find_element(By.XPATH, "//div[@class='header']") -> Option A

4. Quick Check:

   Use By.XPATH with find_element [OK]

Hint: Use By.XPATH with find_element, not deprecated methods [OK]

Common Mistakes:

• Using deprecated find_element_by_xpath method
• Mixing locator types like CSS_SELECTOR with XPath
• Passing XPath as ID locator

3. What will be the output of this code snippet if the page contains exactly one <input name='search'> element?

element = driver.find_element(By.XPATH, "//input[@name='search']")
print(element.tag_name)

medium

A. input

B. search

C. NoSuchElementException

D. button

Solution

1. Step 1: Understand what find_element returns

   It returns the first matching WebElement for the XPath.

2. Step 2: Check the tag_name property

   The element found is an input tag, so element.tag_name returns "input".

3. Final Answer:

   input -> Option A

4. Quick Check:

   XPath finds input element, tag_name returns 'input' [OK]

Hint: tag_name returns the HTML tag of the found element [OK]

Common Mistakes:

• Confusing attribute value with tag name
• Expecting exception when element exists
• Assuming tag_name returns attribute value

4. What is wrong with this code snippet?

element = driver.find_element(By.XPATH, "//div[@class='content']")
print(element.text)

Assume the page has multiple <div class='content'> elements.

medium

A. It will raise NoSuchElementException

B. It only finds the first matching element, ignoring others

C. XPath syntax is incorrect

D. element.text will return None

Solution

1. Step 1: Understand find_element behavior

   find_element returns only the first matching element, even if multiple exist.

2. Step 2: Analyze the impact

   If multiple div.content exist, only the first is found and printed, others ignored.

3. Final Answer:

   It only finds the first matching element, ignoring others -> Option B

4. Quick Check:

   find_element returns first match only [OK]

Hint: Use find_elements to get all matches, find_element gets first only [OK]

Common Mistakes:

• Expecting find_element to return all matches
• Thinking XPath syntax is wrong
• Assuming element.text returns None if multiple elements exist

5. You want to find a button element with text exactly 'Submit' using XPath in Selenium Python. Which XPath expression is correct to use with driver.find_element(By.XPATH, xpath)?

hard

A. //button[text()!='Submit']

B. //button[contains(text(), 'Submit')]

C. //button[text()='Submit']

D. //button[@text='Submit']

Solution

1. Step 1: Understand XPath text() function

   XPath text()='Submit' matches elements whose text content is exactly 'Submit'.

2. Step 2: Evaluate each option

   //button[text()='Submit'] matches exact text. //button[contains(text(), 'Submit')] matches partial text (not exact). //button[@text='Submit'] is invalid because text is not an attribute. //button[text()!='Submit'] matches elements whose text is not 'Submit'.

3. Final Answer:

   //button[text()='Submit'] -> Option C

4. Quick Check:

   Use text()='value' for exact text match in XPath [OK]

Hint: Use text()='value' for exact text match in XPath [OK]

Common Mistakes:

• Using @text instead of text() function
• Using contains() when exact match needed
• Using != in XPath for positive match