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Analyze the following Selenium Java code snippet:

medium📝 Debug Q6 of 15
Selenium Java - Page Object Model
Analyze the following Selenium Java code snippet:
driver.get("https://example.com/dashboard");
driver.findElement(By.linkText("Profile")).click();
String currentUrl = driver.getCurrentUrl();
System.out.println(currentUrl);

What is the main issue with this code when testing multi-page navigation?
AUsing linkText locator is incorrect for navigation
BIt does not wait for the new page to load before getting the URL
Cdriver.getCurrentUrl() returns the previous page URL
Ddriver.findElement should be called after getCurrentUrl()
Step-by-Step Solution
Solution:
  1. Step 1: Initial navigation

    The driver opens the dashboard page.
  2. Step 2: Click on Profile link

    The click triggers navigation to the profile page.
  3. Step 3: Immediately get current URL

    Without waiting, getCurrentUrl() may capture the old URL if the new page hasn't loaded yet.
  4. Final Answer:

    It does not wait for the new page to load before getting the URL -> Option B
  5. Quick Check:

    Always wait for page load before URL check [OK]
Quick Trick: Wait for page load before checking URL [OK]
Common Mistakes:
  • Assuming immediate URL reflects new page
  • Incorrect locator usage (linkText is valid here)
  • Calling getCurrentUrl() before navigation

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