Element dimensions and location in Selenium Java - Test Execution Trace

Test Overview

This test opens a webpage, locates a button element, and verifies its size and position on the page.

Test Code - JUnit with Selenium WebDriver

Selenium Java

import org.openqa.selenium.By;
import org.openqa.selenium.Dimension;
import org.openqa.selenium.Point;
import org.openqa.selenium.WebDriver;
import org.openqa.selenium.WebElement;
import org.openqa.selenium.chrome.ChromeDriver;
import org.junit.jupiter.api.AfterEach;
import org.junit.jupiter.api.BeforeEach;
import org.junit.jupiter.api.Test;
import static org.junit.jupiter.api.Assertions.*;

public class ElementDimensionsLocationTest {
    private WebDriver driver;

    @BeforeEach
    public void setUp() {
        // Set the path to chromedriver executable if necessary
        // System.setProperty("webdriver.chrome.driver", "path/to/chromedriver");
        driver = new ChromeDriver();
    }

    @AfterEach
    public void tearDown() {
        if (driver != null) {
            driver.quit();
        }
    }

    @Test
    public void testButtonDimensionsAndLocation() {
        driver.get("https://example.com");
        WebElement button = driver.findElement(By.id("submit-button"));

        Dimension size = button.getSize();
        Point location = button.getLocation();

        assertEquals(100, size.getWidth(), "Button width should be 100 pixels");
        assertEquals(50, size.getHeight(), "Button height should be 50 pixels");
        assertTrue(location.getX() >= 0, "Button X coordinate should be non-negative");
        assertTrue(location.getY() >= 0, "Button Y coordinate should be non-negative");
    }
}

Execution Trace - 6 Steps

Step	Action	System State	Assertion	Result
1	Test starts and Chrome browser opens	Chrome browser window is open and ready	—	PASS
2	Navigates to https://example.com	Page loads with visible elements including a button with id 'submit-button'	—	PASS
3	Finds element by id 'submit-button'	Button element is located on the page	—	PASS
4	Gets size of the button element	Size object with width and height retrieved	Button width equals 100 pixels and height equals 50 pixels	PASS
5	Gets location of the button element	Location object with X and Y coordinates retrieved	Button X and Y coordinates are non-negative	PASS
6	Assertions verify size and location values	Test verifies expected dimensions and location	All assertions pass confirming correct size and location	PASS

Failure Scenario

Failing Condition: Button element not found or size/location values differ from expected

Execution Trace Quiz - 3 Questions

What does the test verify about the button element?

A Its text content only

B Its color and font style

C Its width, height, and position on the page

D Its visibility only

Key Result

Always verify both size and position of UI elements to ensure they appear correctly on the page as expected.

Practice

1. Which Selenium WebDriver method is used to get the position of a web element on the page?

easy

A. getAttribute()

B. getSize()

C. getText()

D. getLocation()

Solution

1. Step 1: Understand the purpose of getLocation()

   This method returns the coordinates (x, y) of the element on the page.

2. Step 2: Compare with other methods

   getSize() returns width and height, getText() returns visible text, and getAttribute() returns attribute values.

3. Final Answer:

   getLocation() -> Option D

4. Quick Check:

   Position = getLocation() [OK]

Hint: Position = getLocation(), size = getSize() [OK]

Common Mistakes:

• Confusing getLocation() with getSize()
• Using getText() to find position
• Expecting getAttribute() to return coordinates

2. Which of the following is the correct Java syntax to get the width of a WebElement named element?

easy

A. int width = element.getLocation().getX();

B. int width = element.getSize().getHeight();

C. int width = element.getSize().getWidth();

D. int width = element.getLocation().getY();

Solution

1. Step 1: Identify method to get size

   getSize() returns a Dimension object with width and height.

2. Step 2: Get width from Dimension

   Use getWidth() on the Dimension object to get the width.

3. Final Answer:

   int width = element.getSize().getWidth(); -> Option C

4. Quick Check:

   Width = getSize().getWidth() [OK]

Hint: Width is from getSize().getWidth(), not getLocation() [OK]

Common Mistakes:

• Using getLocation() to get width
• Mixing width and height methods
• Calling getHeight() when width is needed

3. Given the following code snippet, what will be printed if the element's location is (50, 100) and size is width=200, height=150?

Point location = element.getLocation();
Dimension size = element.getSize();
System.out.println("X: " + location.getX() + ", Y: " + location.getY());
System.out.println("Width: " + size.getWidth() + ", Height: " + size.getHeight());

medium

A. X: 50, Y: 100
Width: 200, Height: 150

B. X: 100, Y: 50
Width: 150, Height: 200

C. X: 0, Y: 0
Width: 200, Height: 150

D. X: 50, Y: 100
Width: 150, Height: 200

Solution

1. Step 1: Understand getLocation() output

   It returns a Point with x=50 and y=100 as given.

2. Step 2: Understand getSize() output

   It returns Dimension with width=200 and height=150 as given.

3. Final Answer:

   X: 50, Y: 100 Width: 200, Height: 150 -> Option A

4. Quick Check:

   Location and size match output [OK]

Hint: Print location x,y then size width,height directly [OK]

Common Mistakes:

• Swapping x and y values
• Swapping width and height values
• Assuming default (0,0) location

4. Identify the error in the following code snippet that tries to get the height of a WebElement named element:

int height = element.getLocation().getHeight();

medium

A. getLocation() does not have getHeight() method

B. getHeight() should be getWidth()

C. element should be cast to Dimension first

D. No error, code is correct

Solution

1. Step 1: Check getLocation() return type

   It returns a Point object which has getX() and getY(), but no getHeight().

2. Step 2: Correct method to get height

   Height is obtained from element.getSize().getHeight(), not from getLocation().

3. Final Answer:

   getLocation() does not have getHeight() method -> Option A

4. Quick Check:

   Height = getSize().getHeight() [OK]

Hint: Height comes from getSize(), not getLocation() [OK]

Common Mistakes:

• Calling getHeight() on Point object
• Confusing getWidth() and getHeight()
• Assuming getLocation() returns size info

5. You want to verify that a button is fully visible on the page by checking its location and size. The viewport width is 1024 and height is 768. Which condition correctly checks that the button is fully inside the viewport using Selenium Java methods on button element?

hard

A. button.getLocation().getX() < 0 || button.getLocation().getY() < 0

B. button.getLocation().getX() >= 0 && button.getLocation().getY() >= 0 && button.getLocation().getX() + button.getSize().getWidth() <= 1024 && button.getLocation().getY() + button.getSize().getHeight() <= 768

C. button.getSize().getWidth() > 1024 && button.getSize().getHeight() > 768

D. button.getSize().getWidth() == 0 || button.getSize().getHeight() == 0

Solution

1. Step 1: Check button's top-left corner inside viewport

   Ensure X and Y coordinates are >= 0.

2. Step 2: Check button's bottom-right corner inside viewport

   Sum of X + width must be <= viewport width (1024), and Y + height <= viewport height (768).

3. Final Answer:

   button.getLocation().getX() >= 0 && button.getLocation().getY() >= 0 && button.getLocation().getX() + button.getSize().getWidth() <= 1024 && button.getLocation().getY() + button.getSize().getHeight() <= 768 -> Option B

4. Quick Check:

   Check corners inside viewport using location + size [OK]

Hint: Check top-left ≥0 and bottom-right ≤ viewport size [OK]

Common Mistakes:

• Checking only size without location
• Using OR instead of AND in conditions
• Ignoring viewport boundaries