Bird
Raised Fist0
Selenium Javatesting~10 mins

Element dimensions and location in Selenium Java - Interactive Code Practice

Choose your learning style10 modes available
Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to get the width of a web element.

Selenium Java
int width = element.getSize().[1]();
Drag options to blanks, or click blank then click option'
AgetLocation
BgetWidth
CgetHeight
DgetDimension
Attempts:
3 left
💡 Hint
Common Mistakes
Using getHeight() instead of getWidth()
Using getLocation() which returns position, not size
2fill in blank
medium

Complete the code to get the Y coordinate of a web element's location.

Selenium Java
int yPosition = element.getLocation().[1]();
Drag options to blanks, or click blank then click option'
AgetY
BgetX
CgetWidth
DgetHeight
Attempts:
3 left
💡 Hint
Common Mistakes
Using getX() which returns horizontal position
Using getWidth() which returns size, not position
3fill in blank
hard

Fix the error in the code to get the element's height.

Selenium Java
int height = element.getSize().[1]();
Drag options to blanks, or click blank then click option'
AgetHeight
BgetWidth
CgetLocation
DgetPosition
Attempts:
3 left
💡 Hint
Common Mistakes
Using getWidth() instead of getHeight()
Using getLocation() which returns position, not size
4fill in blank
hard

Fill both blanks to get the X and Y coordinates of an element's location.

Selenium Java
Point location = element.getLocation();
int x = location.[1]();
int y = location.[2]();
Drag options to blanks, or click blank then click option'
AgetX
BgetY
CgetHeight
DgetWidth
Attempts:
3 left
💡 Hint
Common Mistakes
Swapping getX() and getY()
Using getWidth() or getHeight() which return size, not position
5fill in blank
hard

Fill all three blanks to get the width, height, and Y coordinate of an element.

Selenium Java
Dimension size = element.getSize();
int width = size.[1]();
int height = size.[2]();
int y = element.getLocation().[3]();
Drag options to blanks, or click blank then click option'
AgetX
BgetHeight
CgetY
DgetWidth
Attempts:
3 left
💡 Hint
Common Mistakes
Mixing up width and height methods
Using getX() instead of getY() for vertical position

Practice

(1/5)
1. Which Selenium WebDriver method is used to get the position of a web element on the page?
easy
A. getAttribute()
B. getSize()
C. getText()
D. getLocation()

Solution

  1. Step 1: Understand the purpose of getLocation()

    This method returns the coordinates (x, y) of the element on the page.
  2. Step 2: Compare with other methods

    getSize() returns width and height, getText() returns visible text, and getAttribute() returns attribute values.
  3. Final Answer:

    getLocation() -> Option D
  4. Quick Check:

    Position = getLocation() [OK]
Hint: Position = getLocation(), size = getSize() [OK]
Common Mistakes:
  • Confusing getLocation() with getSize()
  • Using getText() to find position
  • Expecting getAttribute() to return coordinates
2. Which of the following is the correct Java syntax to get the width of a WebElement named element?
easy
A. int width = element.getLocation().getX();
B. int width = element.getSize().getHeight();
C. int width = element.getSize().getWidth();
D. int width = element.getLocation().getY();

Solution

  1. Step 1: Identify method to get size

    getSize() returns a Dimension object with width and height.
  2. Step 2: Get width from Dimension

    Use getWidth() on the Dimension object to get the width.
  3. Final Answer:

    int width = element.getSize().getWidth(); -> Option C
  4. Quick Check:

    Width = getSize().getWidth() [OK]
Hint: Width is from getSize().getWidth(), not getLocation() [OK]
Common Mistakes:
  • Using getLocation() to get width
  • Mixing width and height methods
  • Calling getHeight() when width is needed
3. Given the following code snippet, what will be printed if the element's location is (50, 100) and size is width=200, height=150?
Point location = element.getLocation();
Dimension size = element.getSize();
System.out.println("X: " + location.getX() + ", Y: " + location.getY());
System.out.println("Width: " + size.getWidth() + ", Height: " + size.getHeight());
medium
A. X: 50, Y: 100 Width: 200, Height: 150
B. X: 100, Y: 50 Width: 150, Height: 200
C. X: 0, Y: 0 Width: 200, Height: 150
D. X: 50, Y: 100 Width: 150, Height: 200

Solution

  1. Step 1: Understand getLocation() output

    It returns a Point with x=50 and y=100 as given.
  2. Step 2: Understand getSize() output

    It returns Dimension with width=200 and height=150 as given.
  3. Final Answer:

    X: 50, Y: 100 Width: 200, Height: 150 -> Option A
  4. Quick Check:

    Location and size match output [OK]
Hint: Print location x,y then size width,height directly [OK]
Common Mistakes:
  • Swapping x and y values
  • Swapping width and height values
  • Assuming default (0,0) location
4. Identify the error in the following code snippet that tries to get the height of a WebElement named element:
int height = element.getLocation().getHeight();
medium
A. getLocation() does not have getHeight() method
B. getHeight() should be getWidth()
C. element should be cast to Dimension first
D. No error, code is correct

Solution

  1. Step 1: Check getLocation() return type

    It returns a Point object which has getX() and getY(), but no getHeight().
  2. Step 2: Correct method to get height

    Height is obtained from element.getSize().getHeight(), not from getLocation().
  3. Final Answer:

    getLocation() does not have getHeight() method -> Option A
  4. Quick Check:

    Height = getSize().getHeight() [OK]
Hint: Height comes from getSize(), not getLocation() [OK]
Common Mistakes:
  • Calling getHeight() on Point object
  • Confusing getWidth() and getHeight()
  • Assuming getLocation() returns size info
5. You want to verify that a button is fully visible on the page by checking its location and size. The viewport width is 1024 and height is 768. Which condition correctly checks that the button is fully inside the viewport using Selenium Java methods on button element?
hard
A. button.getLocation().getX() < 0 || button.getLocation().getY() < 0
B. button.getLocation().getX() >= 0 && button.getLocation().getY() >= 0 && button.getLocation().getX() + button.getSize().getWidth() <= 1024 && button.getLocation().getY() + button.getSize().getHeight() <= 768
C. button.getSize().getWidth() > 1024 && button.getSize().getHeight() > 768
D. button.getSize().getWidth() == 0 || button.getSize().getHeight() == 0

Solution

  1. Step 1: Check button's top-left corner inside viewport

    Ensure X and Y coordinates are >= 0.
  2. Step 2: Check button's bottom-right corner inside viewport

    Sum of X + width must be <= viewport width (1024), and Y + height <= viewport height (768).
  3. Final Answer:

    button.getLocation().getX() >= 0 && button.getLocation().getY() >= 0 && button.getLocation().getX() + button.getSize().getWidth() <= 1024 && button.getLocation().getY() + button.getSize().getHeight() <= 768 -> Option B
  4. Quick Check:

    Check corners inside viewport using location + size [OK]
Hint: Check top-left ≥0 and bottom-right ≤ viewport size [OK]
Common Mistakes:
  • Checking only size without location
  • Using OR instead of AND in conditions
  • Ignoring viewport boundaries
Recommended

Ready to prove it?

Pass the test and this pattern moves unknown strong while earning +1 Grip toward your certificate.

10 questions~5 mineasy hard