When you use numerical integration to calculate the integral of a function f(x) over an interval, what does the result represent?
Think about what integration means in terms of geometry.
Numerical integration approximates the definite integral, which geometrically represents the area under the curve of the function between two points.
What is the output of the following Python code using scipy.integrate.quad?
from scipy.integrate import quad
def f(x):
return 2 * x
result, error = quad(f, 0, 3)
print(f"{round(result, 2):.2f}")Calculate the integral of 2x from 0 to 3 by hand.
The integral of 2x from 0 to 3 is x^2 evaluated from 0 to 3, which is 9.
What is the numerical integration result of sin(x) from 0 to π using scipy.integrate.quad?
from scipy.integrate import quad
import numpy as np
result, error = quad(np.sin, 0, np.pi)
print(f"{round(result, 4):.4f}")Recall the integral of sine over one half period.
The integral of sin(x) from 0 to π is 2, representing the area under the sine curve in that interval.
Which plot correctly shows the area computed by numerical integration of f(x) = x^2 from 0 to 2?
import numpy as np import matplotlib.pyplot as plt from scipy.integrate import quad x = np.linspace(0, 2, 100) f = lambda x: x**2 plt.plot(x, f(x), label='f(x) = x^2') plt.fill_between(x, 0, f(x), color='skyblue', alpha=0.5) plt.title('Area under f(x) from 0 to 2') plt.xlabel('x') plt.ylabel('f(x)') plt.legend() plt.show()
Numerical integration area is the region under the curve between the limits.
The correct visualization shows the area under the curve between 0 and 2, which numerical integration calculates.
What error will the following code produce?
from scipy.integrate import quad
def f(x):
return x / 0
result, error = quad(f, 1, 2)
print(result)Look at the function f(x) and what happens when dividing by zero.
The function attempts to divide by zero, which raises a ZeroDivisionError before integration starts.