Minimizing scalar functions (minimize_scalar) in SciPy

Introduction

We use minimize_scalar to find the smallest value of a simple function. It helps us solve problems where we want to reduce cost, error, or any number to its lowest point.

Finding the best price to sell a product to maximize profit.

Minimizing the error in a simple prediction model.

Finding the shortest distance in a simple path problem.

Optimizing a single variable like time or temperature for best results.

Syntax

SciPy

from scipy.optimize import minimize_scalar

result = minimize_scalar(function, bounds=(lower, upper), method='bounded')

The function is what you want to minimize. It must take one number and return one number.

The bounds set the search limits. Use method='bounded' to respect these limits.

Examples

Minimize a simple parabola without bounds.

SciPy

from scipy.optimize import minimize_scalar

def f(x):
    return (x - 3) ** 2

result = minimize_scalar(f)

Minimize the same function but only between 0 and 5.

SciPy

from scipy.optimize import minimize_scalar

def f(x):
    return (x - 3) ** 2

result = minimize_scalar(f, bounds=(0, 5), method='bounded')

Sample Program

This code finds the minimum of the function (x-2)^2 + 1. It prints the smallest value and where it happens.

SciPy

from scipy.optimize import minimize_scalar

def cost(x):
    return (x - 2) ** 2 + 1

result = minimize_scalar(cost)
print(f"Minimum value: {result.fun}")
print(f"At x = {result.x}")

Important Notes

The function should be smooth and have one clear minimum for best results.

If you know the range where the minimum is, use bounds and method='bounded' for faster and safer search.

The result object has useful info like result.x (location) and result.fun (minimum value).

Summary

minimize_scalar helps find the lowest point of a simple function with one variable.

You can run it with or without limits on the variable.

It returns the minimum value and where it happens.

Practice

1. What does the minimize_scalar function in scipy do?

easy

A. Integrates a function over a range

B. Finds the maximum value of a function with multiple variables

C. Calculates the derivative of a function

D. Finds the minimum value of a function with one variable

Solution

1. Step 1: Understand the purpose of minimize_scalar

   The function is designed to find the lowest point (minimum) of a scalar function with one variable.

2. Step 2: Compare options to the function's purpose

   Only Finds the minimum value of a function with one variable correctly describes this purpose; others describe different tasks.

3. Final Answer:

   Finds the minimum value of a function with one variable -> Option D

4. Quick Check:

   minimize_scalar finds minimum [OK]

Hint: Remember: minimize_scalar finds lowest point of one-variable function [OK]

Common Mistakes:

• Confusing minimize_scalar with maximization functions
• Thinking it works for multi-variable functions
• Mixing it up with derivative or integration functions

2. Which of the following is the correct way to import minimize_scalar from scipy.optimize?

easy

A. from scipy.optimize import minimize_scalar

B. import minimize_scalar from scipy.optimize

C. from scipy import minimize_scalar

D. import scipy.optimize.minimize_scalar

Solution

1. Step 1: Recall Python import syntax

   To import a specific function, use 'from module import function'.

2. Step 2: Match syntax to options

   from scipy.optimize import minimize_scalar matches correct syntax: 'from scipy.optimize import minimize_scalar'. Others are invalid Python syntax.

3. Final Answer:

   from scipy.optimize import minimize_scalar -> Option A

4. Quick Check:

   Correct import syntax = from scipy.optimize import minimize_scalar [OK]

Hint: Use 'from module import function' to import specific functions [OK]

Common Mistakes:

• Using 'import function from module' which is invalid
• Trying to import directly from 'scipy' without submodule
• Using dot notation in import statement incorrectly

3. What is the output of this code?

from scipy.optimize import minimize_scalar

result = minimize_scalar(lambda x: (x - 3)**2)
print(round(result.x, 2))

medium

A. 3.00

B. 0.00

C. -3.00

D. None

Solution

1. Step 1: Understand the function minimized

   The function is (x - 3)^2, which has its minimum at x = 3.

2. Step 2: Check the minimize_scalar result

   The optimizer finds x close to 3; rounding to 2 decimals gives 3.00.

3. Final Answer:

   3.00 -> Option A

4. Quick Check:

   Minimum of (x-3)^2 is at 3 [OK]

Hint: Minimum of (x - a)^2 is at x = a [OK]

Common Mistakes:

• Confusing minimum location with function value
• Not rounding result.x before printing
• Assuming minimum at zero without checking function

4. Identify the error in this code snippet:

from scipy.optimize import minimize_scalar

def f(x):
    return x**2

result = minimize_scalar(f, bounds=(1, 2))
print(result.x)

medium

A. minimize_scalar does not accept bounds argument

B. Function f should return negative values

C. Missing method='bounded' for bounded minimization

D. Bounds should be a list, not a tuple

Solution

1. Step 1: Check usage of bounds in minimize_scalar

   When using bounds, method='bounded' must be specified explicitly.

2. Step 2: Identify missing method argument

   The code misses method='bounded', so it will ignore bounds or error.

3. Final Answer:

   Missing method='bounded' for bounded minimization -> Option C

4. Quick Check:

   Bounds require method='bounded' [OK]

Hint: Use method='bounded' when specifying bounds [OK]

Common Mistakes:

• Forgetting method='bounded' with bounds
• Assuming bounds work without method argument
• Incorrect bounds format (tuple is correct though)

5. You want to find the minimum of f(x) = (x-1)^2 + 2 but only for x between 0 and 2. Which code correctly finds this minimum using minimize_scalar?

hard

A. minimize_scalar(lambda x: (x-1)**2 + 2, bounds=(0, 2))

B. minimize_scalar(lambda x: (x-1)**2 + 2, bounds=(0, 2), method='bounded')

C. minimize_scalar(lambda x: (x-1)**2 + 2, method='bounded')

D. minimize_scalar(lambda x: (x-1)**2 + 2, method='brent')

Solution

1. Step 1: Understand bounded minimization requirements

   To limit search to [0, 2], bounds must be set and method='bounded' used.

2. Step 2: Evaluate options for correct usage

   Only minimize_scalar(lambda x: (x-1)**2 + 2, bounds=(0, 2), method='bounded') uses both bounds and method='bounded' correctly.

3. Final Answer:

   minimize_scalar(lambda x: (x-1)**2 + 2, bounds=(0, 2), method='bounded') -> Option B

4. Quick Check:

   Bounds + method='bounded' needed for limited range [OK]

Hint: Use bounds with method='bounded' to limit search range [OK]

Common Mistakes:

• Omitting method='bounded' when using bounds
• Using method='brent' which ignores bounds
• Not specifying bounds when needed