UnivariateSpline in SciPy - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to import the UnivariateSpline class from scipy.interpolate.

SciPy

from scipy.interpolate import [1]

spline = UnivariateSpline(x, y)

Drag options to blanks, or click blank then click option'

AUnivariateSpline

Binterp1d

Csplrep

Dsplev

Attempts:

3 left

💡 Hint

Common Mistakes

Importing the wrong function like interp1d which is for linear interpolation.

Using splrep or splev which are lower-level spline functions.

The UnivariateSpline class is imported from scipy.interpolate to create spline fits.

2fill in blank

medium

Complete the code to create a UnivariateSpline object with data arrays x and y.

SciPy

spline = UnivariateSpline([1], y)

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At

Bx

Cz

Dy

Attempts:

3 left

💡 Hint

Common Mistakes

Passing y as the first argument instead of x.

Using undefined variables like z or t.

The first argument to UnivariateSpline is the x-coordinates of the data points.

3fill in blank

hard

Fix the error in the code to evaluate the spline at new points x_new.

SciPy

y_new = spline([1])

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Ax_new

Bx

Cy

Dnew_x

Attempts:

3 left

💡 Hint

Common Mistakes

Passing the original x array instead of the new points.

Using undefined variable names like new_x without defining them.

To evaluate the spline, pass the new x-coordinates array x_new to the spline object.

4fill in blank

hard

Fill both blanks to create a UnivariateSpline with smoothing factor s=1 and evaluate it at x_new.

SciPy

spline = UnivariateSpline(x, y, [1]=[2])
y_new = spline(x_new)

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As

B1

Csmooth

D0

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'smooth' instead of 's' as the parameter name.

Setting smoothing to 0 which fits the spline exactly through points.

The smoothing factor is set with the parameter s. Here, s=1 controls the smoothness of the spline.

5fill in blank

hard

Fill all three blanks to create a dictionary mapping words to their lengths for words longer than 3 characters that contain the letter 'a'.

SciPy

lengths = {word: [1] for word in words if len(word) [2] 3 and 'a' [3] word}

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Alen(word)

B>

Ccontains

Din

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'contains' which is not a Python operator.

Reversing the 'in' operator like word in 'a'.

This dictionary comprehension maps each word to its length if the word is longer than 3 characters and contains the letter 'a'. The correct syntax to check if 'a' is in the word is 'a' in word.