Simpson's rule (simpson) in SciPy - Practice Problems & Coding Challenges

Challenge - 5 Problems

❓ Predict Output

intermediate

Output of Simpson's rule integration with simple function

What is the output of this code that uses Simpson's rule to integrate f(x) = x^2 from 0 to 2 with 5 points?

SciPy

import numpy as np
from scipy.integrate import simpson
x = np.linspace(0, 2, 5)
y = x**2
result = simpson(y, x)
print(round(result, 4))

A 2.6668

B 2.6667

C 2.6665

D 2.6666

💡 Hint

Recall the exact integral of x^2 from 0 to 2 is 8/3 ≈ 2.6667. Simpson's rule should approximate closely.

Simpson's rule approximates the integral of x^2 from 0 to 2 as about 2.6667, which matches the exact value 8/3.

❓ data_output

intermediate

Number of intervals used in Simpson's rule with uneven spacing

Given unevenly spaced points x and function values y, how many intervals does scipy.integrate.simpson use internally for integration?

SciPy

import numpy as np
from scipy.integrate import simpson
x = np.array([0, 1, 1.5, 2.5, 3])
y = np.sin(x)
result = simpson(y, x)
intervals = len(x) - 1
print(intervals)

A 5

B 3

C 4

D 2

💡 Hint

Intervals are the spaces between points, so count points minus one.

Simpson's rule uses intervals between points, so with 5 points, there are 4 intervals.

🔧 Debug

advanced

Identify the error in Simpson's rule usage

What error does this code raise when trying to integrate y = x^3 over 0 to 3 with 4 points using simpson?

SciPy

import numpy as np
from scipy.integrate import simpson
x = np.linspace(0, 3, 4)
y = x**3
result = simpson(y, x)
print(result)

A IndexError: index out of range

B TypeError: unsupported operand type(s) for ** or pow()

C No error, outputs 20.25

D ValueError: Simpson's rule requires an odd number of samples.

💡 Hint

Simpson's rule needs an odd number of points to work correctly.

Simpson's rule in scipy requires an odd number of samples; 4 points is even, so it raises a ValueError.

🚀 Application

advanced

Choosing the correct Simpson's rule call for equally spaced data

You have y values of a function sampled at equal intervals of 0.1 seconds. Which simpson call correctly computes the integral over time?

A simpson(y, dx=0.1)

B simpson(y, x=np.arange(len(y))*0.1)

C simpson(y)

D simpson(y, dx=1)

💡 Hint

When spacing is uniform, use dx parameter for efficiency.

Using dx=0.1 tells simpson the spacing between points, which is correct for equally spaced data.

🧠 Conceptual

expert

Why does Simpson's rule require an odd number of points?

Why must the number of sample points be odd when using Simpson's rule for numerical integration?

A Because Simpson's rule fits parabolas over pairs of intervals, needing an odd number of points.

B Because the function must be sampled at prime number points only.

C Because the algorithm uses trapezoids which require odd points.

D Because the integral is only defined for odd number of points.

💡 Hint

Think about how parabolas are fit between points.

Simpson's rule approximates the function by fitting parabolas over pairs of intervals, which requires an odd number of points.

Practice

1. What is the main purpose of Simpson's rule in data science?

easy

A. To find the maximum value in a dataset

B. To estimate the area under a curve using parabolas

C. To sort data points in ascending order

D. To calculate the mean of a list of numbers

Solution

1. Step 1: Understand the goal of Simpson's rule

   Simpson's rule is a numerical method used to estimate the area under a curve by approximating the curve with parabolas between points.

2. Step 2: Compare options with this goal

   Only To estimate the area under a curve using parabolas describes this purpose correctly. Other options describe unrelated tasks.

3. Final Answer:

   To estimate the area under a curve using parabolas -> Option B

4. Quick Check:

   Simpson's rule = area estimation [OK]

Hint: Simpson's rule estimates area under curves using parabolas [OK]

Common Mistakes:

• Confusing Simpson's rule with sorting or averaging
• Thinking it finds max or min values
• Assuming it requires a formula for the curve

2. Which of the following is the correct way to import the Simpson's rule function from scipy for numerical integration?

easy

A. from scipy.integrate import simpson

B. import scipy.simpson

C. from scipy import simpson

D. import simpson from scipy.integrate

Solution

1. Step 1: Recall the correct import syntax for functions in scipy

   Functions like simpson are in the integrate module, so the correct import is from scipy.integrate import simpson.

2. Step 2: Check each option

   from scipy.integrate import simpson matches the correct syntax. Options A, B, and D are incorrect. import simpson from scipy.integrate uses wrong import order.

3. Final Answer:

   from scipy.integrate import simpson -> Option A

4. Quick Check:

   Correct import = from scipy.integrate import simpson [OK]

Hint: Import simpson from scipy.integrate module [OK]

Common Mistakes:

• Trying to import simpson directly from scipy
• Using wrong import syntax order
• Assuming simpson is a standalone package

3. What is the output of the following code?

from scipy.integrate import simpson
import numpy as np
x = np.array([0, 1, 2, 3, 4])
y = np.array([0, 1, 4, 9, 16])
result = simpson(y, x)
print(round(result, 2))

medium

A. 22.67

B. 18.00

C. 20.00

D. 21.33

Solution

1. Step 1: Understand the data points and function

   x values are [0,1,2,3,4], y values are squares of x: [0,1,4,9,16]. Simpson's rule estimates the integral of y with respect to x.

2. Step 2: Calculate the integral using simpson

   Using scipy's simpson function on these points gives exactly 21.3333. Rounded to two decimals, it is 21.33.

3. Final Answer:

   21.33 -> Option D

4. Quick Check:

   Simpson integral ≈ 21.33 [OK]

Hint: Use simpson(y, x) and round result for quick check [OK]

Common Mistakes:

• Forgetting to provide x values to simpson
• Rounding incorrectly or too early
• Confusing simpson with trapezoidal rule

4. Identify the error in this code snippet using Simpson's rule:

from scipy.integrate import simpson
import numpy as np
x = np.array([0, 1, 2, 3])
y = np.array([1, 4, 9])
result = simpson(y, x)
print(result)

medium

A. x and y arrays have different lengths

B. simpson function is not imported correctly

C. x array must be sorted in descending order

D. y array contains non-numeric values

Solution

1. Step 1: Check array lengths

   x has 4 elements, y has 3 elements. Simpson's rule requires x and y to have the same length.

2. Step 2: Verify other options

   Import is correct, x order is fine, y contains numeric values. So only length mismatch is the error.

3. Final Answer:

   x and y arrays have different lengths -> Option A

4. Quick Check:

   Length mismatch error = x and y arrays have different lengths [OK]

Hint: Check x and y array lengths match before integration [OK]

Common Mistakes:

• Ignoring length mismatch causing runtime error
• Assuming simpson auto-corrects array sizes
• Thinking x must be descending

5. You have noisy sensor data sampled unevenly over time:

time = [0, 0.5, 1.5, 2.2, 3.8]
values = [2, 3, 5, 4, 6]

How can you use Simpson's rule to estimate the total area under the sensor curve? Choose the best approach.

hard

A. Interpolate values to evenly spaced points, then use simpson without x

B. Use simpson(values) without x, ignoring time points

C. Use simpson(values, time) directly to integrate over uneven intervals

D. Sum values and multiply by average time interval

Solution

1. Step 1: Understand uneven sampling

   Time points are unevenly spaced, so integration must consider x values explicitly.

2. Step 2: Apply simpson with x values

   Passing values and time arrays to simpson allows correct numerical integration over uneven intervals.

3. Step 3: Evaluate other options

   Interpolating or ignoring x loses accuracy; summing values times average interval is a rough estimate, not Simpson's rule.

4. Final Answer:

   Use simpson(values, time) directly to integrate over uneven intervals -> Option C

5. Quick Check:

   Simpson with x for uneven data = Use simpson(values, time) directly to integrate over uneven intervals [OK]

Hint: Always provide x for unevenly spaced data in simpson [OK]

Common Mistakes:

• Ignoring uneven spacing and skipping x parameter
• Using interpolation unnecessarily
• Using simple sum times average interval instead of integration