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SciPydata~20 mins

Romberg integration in SciPy - Practice Problems & Coding Challenges

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Challenge - 5 Problems
🎖️
Romberg Integration Master
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Predict Output
intermediate
2:00remaining
Output of Romberg integration for a simple function
What is the output of the following code that uses Romberg integration to calculate the integral of f(x) = x^2 from 0 to 1?
SciPy
from scipy.integrate import romberg

f = lambda x: x**2
result = romberg(f, 0, 1, divmax=5)
print(round(result, 5))
A0.33333
B0.50000
C0.25000
D1.00000
Attempts:
2 left
💡 Hint
Recall the integral of x^2 from 0 to 1 is 1/3.
data_output
intermediate
2:00remaining
Number of iterations in Romberg integration
How many iterations does Romberg integration perform with divmax=3 when integrating f(x) = sin(x) from 0 to pi?
SciPy
from scipy.integrate import romberg
import numpy as np

f = np.sin
result = romberg(f, 0, np.pi, divmax=3, show=True)
A3
B4
C2
D5
Attempts:
2 left
💡 Hint
Romberg integration performs divmax+1 iterations.
🔧 Debug
advanced
2:00remaining
Identify the error in Romberg integration usage
What error will this code raise when trying to compute the integral of f(x) = 1/x from 0 to 1 using Romberg integration?
SciPy
from scipy.integrate import romberg

f = lambda x: 1/x
result = romberg(f, 0, 1)
ATypeError
BValueError
CNo error, returns a float
DZeroDivisionError
Attempts:
2 left
💡 Hint
Check the function behavior at the lower limit 0.
🧠 Conceptual
advanced
2:00remaining
Understanding Romberg integration accuracy
Which statement best describes why Romberg integration is more accurate than the trapezoidal rule alone?
AIt applies Simpson's rule repeatedly for better accuracy.
BIt uses Monte Carlo sampling to reduce error.
CIt uses Richardson extrapolation to improve trapezoidal estimates.
DIt increases the number of trapezoids without combining results.
Attempts:
2 left
💡 Hint
Romberg integration builds on trapezoidal rule results.
🚀 Application
expert
3:00remaining
Using Romberg integration for a complex function
You want to compute the integral of f(x) = exp(-x^2) from -2 to 2 using Romberg integration. Which code snippet correctly computes this and rounds the result to 6 decimals?
A
from scipy.integrate import romberg
import numpy as np
f = lambda x: np.exp(-x**2)
result = romberg(f, -2, 2)
print(round(result, 6))
B
from scipy.integrate import romberg
import math
f = lambda x: math.exp(-x**2)
result = romberg(f, 0, 2)
print(round(result, 6))
C
from scipy.integrate import romberg
import numpy as np
f = lambda x: np.exp(-x**2)
result = romberg(f, 0, 2)
print(round(result, 6))
D
from scipy.integrate import romberg
import math
f = lambda x: math.exp(-x**2)
result = romberg(f, -2, 2)
print(round(result, 6))
Attempts:
2 left
💡 Hint
Use numpy for vectorized math and correct integration limits.