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Peak finding (find_peaks) in SciPy - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to import the peak finding function from scipy.

SciPy
from scipy.signal import [1]
Drag options to blanks, or click blank then click option'
Apeak_find
Bfind_peaks
Cfind_peak
Dpeaks_find
Attempts:
3 left
💡 Hint
Common Mistakes
Using singular 'find_peak' instead of 'find_peaks'.
Mixing up the order of words in the function name.
2fill in blank
medium

Complete the code to find peaks in the data array.

SciPy
peaks, _ = find_peaks([1])
Drag options to blanks, or click blank then click option'
Adata
Bsignal
Carray
Dpeaks
Attempts:
3 left
💡 Hint
Common Mistakes
Passing the wrong variable name to find_peaks.
Using the output variable as input.
3fill in blank
hard

Fix the error in the code to find peaks with a minimum height of 5.

SciPy
peaks, _ = find_peaks(data, height=[1])
Drag options to blanks, or click blank then click option'
A{'min': 5}
Bmin=5
Cheight=5
D5
Attempts:
3 left
💡 Hint
Common Mistakes
Passing a dictionary instead of a number to height.
Using keyword-like strings such as 'min=5' or 'height=5'.
4fill in blank
hard

Fill both blanks to create a dictionary of peak heights and filter peaks taller than 3.

SciPy
peak_heights = {peak: [1] for peak in peaks if [2] > 3}
Drag options to blanks, or click blank then click option'
Adata[peak]
Bpeak
Attempts:
3 left
💡 Hint
Common Mistakes
Using the peak index instead of the data value for height.
Comparing the peak index to 3 instead of the height.
5fill in blank
hard

Fill all three blanks to create a dictionary of peaks with heights above 4 and return their indices.

SciPy
result = [1](peak: [2] for peak in peaks if [3] > 4)
Drag options to blanks, or click blank then click option'
Adict
Bdata[peak]
Dlist
Attempts:
3 left
💡 Hint
Common Mistakes
Using list instead of dict.
Using peak index instead of height for filtering.

Practice

(1/5)
1. What does the find_peaks function in scipy do?
easy
A. It finds local maxima (peaks) in a 1D array of data.
B. It sorts the data in ascending order.
C. It calculates the average value of the data.
D. It removes all negative values from the data.

Solution

  1. Step 1: Understand the purpose of find_peaks

    The function is designed to identify points in data where values are higher than their neighbors, called peaks.
  2. Step 2: Compare options with function behavior

    Only It finds local maxima (peaks) in a 1D array of data. correctly describes this behavior; others describe unrelated operations.
  3. Final Answer:

    It finds local maxima (peaks) in a 1D array of data. -> Option A
  4. Quick Check:

    find_peaks locates peaks = D [OK]
Hint: Remember: find_peaks finds highs, not sorting or averaging [OK]
Common Mistakes:
  • Confusing peak finding with sorting data
  • Thinking it calculates statistics like mean
  • Assuming it filters values instead of locating peaks
2. Which of the following is the correct way to import and use find_peaks from scipy.signal?
easy
A. import find_peaks from scipy.signal peaks = find_peaks(data)
B. from scipy.signal import find_peaks peaks = find_peaks(data)
C. from scipy import find_peaks peaks = find_peaks(data)
D. import scipy.signal.find_peaks peaks = find_peaks(data)

Solution

  1. Step 1: Recall correct import syntax in Python

    Python uses 'from module import function' to import specific functions.
  2. Step 2: Match syntax with options

    from scipy.signal import find_peaks peaks = find_peaks(data) uses correct syntax. Options A, C, and D have invalid import statements.
  3. Final Answer:

    from scipy.signal import find_peaks\npeaks = find_peaks(data) -> Option B
  4. Quick Check:

    Correct import syntax = B [OK]
Hint: Use 'from module import function' for specific imports [OK]
Common Mistakes:
  • Using 'import function from module' which is invalid
  • Trying to import from wrong module path
  • Using dot notation in import statement incorrectly
3. Given the code below, what will be the output of peaks?
import numpy as np
from scipy.signal import find_peaks

data = np.array([0, 2, 1, 3, 0, 1, 2, 1])
peaks, _ = find_peaks(data, height=2)
print(peaks)
medium
A. [3]
B. [1 3]
C. [1 3 6]
D. [2 5]

Solution

  1. Step 1: Identify peaks in the data array

    Data values: [0, 2, 1, 3, 0, 1, 2, 1]. Peaks are points higher than neighbors: indices 1 (2), 3 (3), and 6 (2).
  2. Step 2: Apply height=2 filter

    Peaks with height >= 2 are kept. Index 1 (2 >= 2), 3 (3 >= 2), 6 (2 >= 2), so indices 1, 3, 6 remain.
  3. Final Answer:

    [1 3 6] -> Option C
  4. Quick Check:

    Peaks with height >= 2 = [1 3 6] [OK]
Hint: Check peak values against height filter carefully [OK]
Common Mistakes:
  • Thinking height filter requires strictly greater than threshold (it's >=)
  • Misidentifying peak positions
  • Ignoring the height parameter
4. The following code is intended to find peaks at least 3 units apart, but it returns more peaks than expected. What is the error?
import numpy as np
from scipy.signal import find_peaks

data = np.array([1, 3, 2, 4, 3, 5, 2])
peaks = find_peaks(data, 3)
print(peaks)
medium
A. The distance parameter is not applied because it should be passed as a keyword argument.
B. The distance parameter is applied correctly; the issue is with the data array.
C. The code is missing parentheses around the print argument.
D. The find_peaks function does not support the distance parameter.

Solution

  1. Step 1: Check how distance parameter is passed

    In find_peaks, distance must be passed as a keyword argument, e.g., distance=3.
  2. Step 2: Analyze the code

    The code passes 3 positionally after data, which sets height=3 instead of distance=3. Thus distance is not applied, returning all local peaks [1,3,5] instead of filtered [1,5].
  3. Step 3: Verify output type

    find_peaks returns a tuple (indices, properties). Printing peaks directly prints the tuple, which may confuse.
  4. Final Answer:

    The distance parameter is not applied because it should be passed as a keyword argument. -> Option A
  5. Quick Check:

    distance must be keyword argument = C [OK]
Hint: Always pass distance as keyword argument: distance=number [OK]
Common Mistakes:
  • Passing distance as positional argument
  • Expecting find_peaks to return only indices
  • Misunderstanding output format of find_peaks
5. You have noisy sensor data and want to find peaks that are at least 5 units high and at least 10 samples apart. Which find_peaks call correctly applies these conditions?
import numpy as np
from scipy.signal import find_peaks

sensor_data = np.random.rand(100) * 10

# Which call is correct?
hard
A. peaks = find_peaks(sensor_data, height=(5, None), distance=10)
B. peaks = find_peaks(sensor_data, height=5, distance=10)
C. peaks, _ = find_peaks(sensor_data, min_height=5, min_distance=10)
D. peaks, _ = find_peaks(sensor_data, height=5, distance=10)

Solution

  1. Step 1: Understand parameter usage in find_peaks

    Height is specified with 'height=5' to find peaks at least 5 units high. Distance is specified with 'distance=10' to ensure peaks are at least 10 samples apart.
  2. Step 2: Evaluate each option

    peaks, _ = find_peaks(sensor_data, height=5, distance=10) correctly uses height and distance parameters and unpacks the tuple output. peaks = find_peaks(sensor_data, height=5, distance=10) misses unpacking. peaks, _ = find_peaks(sensor_data, min_height=5, min_distance=10) uses invalid parameter names. peaks = find_peaks(sensor_data, height=(5, None), distance=10) uses a tuple for height which is valid but unnecessary here.
  3. Final Answer:

    peaks, _ = find_peaks(sensor_data, height=5, distance=10) -> Option D
  4. Quick Check:

    Use height and distance keywords, unpack output = A [OK]
Hint: Use height= and distance= with unpacking for correct results [OK]
Common Mistakes:
  • Using wrong parameter names like min_height
  • Not unpacking the tuple returned by find_peaks
  • Passing height as a tuple unnecessarily
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