SciPy - Sparse Matrices (scipy.sparse)
Why does the memory saving of sparse matrices depend on the sparsity pattern, not just the number of zeros?
Why does the memory saving of sparse matrices depend on the sparsity pattern, not just the number of zeros?
hard📝 Conceptual Q10 of 15
Step-by-Step Solution
Solution:
Step 1: Understand sparse matrix storage
Sparse matrices store non-zero values and their row/column indices, so index storage depends on pattern.Step 2: Analyze impact of sparsity pattern
If non-zero elements are clustered, indices can be stored more efficiently; if scattered, index storage grows.Final Answer:
Because storage also includes indices of non-zero elements -> Option AQuick Check:
Memory depends on values + indices stored [OK]
Quick Trick: Sparse memory depends on non-zero values and their indices [OK]
Common Mistakes:
MISTAKES- Ignoring index storage cost
- Assuming zeros are compressed differently
- Believing zeros are stored internally
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