What will be the shape of U, s, and VT after running the following code?

medium📝 Predict Output Q4 of 15

SciPy - Linear Algebra (scipy.linalg)

import numpy as np
from scipy.linalg import svd
A = np.array([[1, 2], [3, 4], [5, 6]])
U, s, VT = svd(A, full_matrices=False)
print(U.shape, s.shape, VT.shape)

A(3, 2), (2,), (2, 2)

B(3, 3), (3,), (3, 2)

C(3, 2), (3,), (2, 2)

D(2, 2), (2,), (2, 3)

Step-by-Step Solution

Solution:

Step 1: Understand input matrix shape
Matrix A is 3 rows by 2 columns (3x2).
Step 2: Apply svd with full_matrices=False
U shape is (3, 2), s is length 2, VT is (2, 2).
Final Answer:
(3, 2), (2,), (2, 2) -> Option A
Quick Check:
Shapes = (3,2), (2,), (2,2) [OK]

Quick Trick: full_matrices=False makes U shape (m, n) for m>n [OK]

Common Mistakes:

MISTAKES

Assuming full U shape (3,3)
Confusing s length with rows
Mixing VT shape with U shape

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What will be the shape of U, s, and VT after running the following code?

Step 1: Understand input matrix shape

Step 2: Apply svd with full_matrices=False

Final Answer:

Quick Check:

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