[Solved] What is the output of this code?from scipy.stats import poisson rv = poisson(mu=3) prob = rv.pmf(2) print(round(prob, 3)) | SciPy

SciPy - Statistical Functions (scipy.stats) Basics

What is the output of this code?

from scipy.stats import poisson
rv = poisson(mu=3)
prob = rv.pmf(2)
print(round(prob, 3))

A0.2240

B0.224

C0.149

D0.050

Step-by-Step Solution

Solution:

Step 1: Understand the pmf function with mu=3 and k=2
The pmf gives the probability of exactly k=2 events when the average rate mu=3.
Step 2: Calculate the Poisson pmf for k=2, mu=3
Using formula: P(k=2) = (3^2 * e^-3) / 2! ≈ 0.224
Final Answer:
0.224 -> Option B
Quick Check:
Poisson pmf(2,3) ≈ 0.224 [OK]

Quick Trick: Use pmf(k) with mu to get exact event probability [OK]

Common Mistakes:

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