SciPy - Sparse Matrices (scipy.sparse)
Given a sparse matrix in CSR format, how can you efficiently extract a specific row as a dense array?
Given a sparse matrix in CSR format, how can you efficiently extract a specific row as a dense array?
hard📝 Application Q9 of 15
Step-by-Step Solution
Solution:
Step 1: Extract row using getrow()
The .getrow() method returns the specified row as a sparse matrix.Step 2: Convert extracted row to dense
Convert this sparse row to dense using .toarray() or .todense() for efficient extraction.Final Answer:
Use the .getrow() method and then convert to dense -> Option CQuick Check:
Extract row efficiently = getrow + to dense [OK]
Quick Trick: Use getrow() then convert to dense for single row extraction [OK]
Common Mistakes:
MISTAKES- Converting entire matrix to dense unnecessarily
- Using toarray() on the whole matrix before slicing
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