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Given:

hard📝 Application Q8 of 15
SciPy - Sparse Matrices (scipy.sparse)
Given:
data = [11, 22, 33, 44]
row = [0, 2, 2, 3]
col = [1, 0, 2, 3]
Which code snippet correctly creates a COO matrix and converts it to a dense numpy array?
Amatrix = coo_matrix((data, (row, col)), shape=(4, 4)); dense = matrix.toarray()
Bmatrix = coo_matrix(data, row, col); dense = matrix.todense()
Cmatrix = coo_matrix((row, col, data)); dense = matrix.toarray()
Dmatrix = coo_matrix((data, (row, col))); dense = matrix.to_list()
Step-by-Step Solution
Solution:
  1. Step 1: Correct COO matrix creation

    coo_matrix() requires a tuple (data, (row, col)) and optionally a shape.
  2. Step 2: Convert to dense array

    Use .toarray() method to get a dense numpy ndarray.
  3. Final Answer:

    matrix = coo_matrix((data, (row, col)), shape=(4, 4)); dense = matrix.toarray() -> Option A
  4. Quick Check:

    Use coo_matrix((data,(row,col))) and .toarray() [OK]
Quick Trick: Use coo_matrix((data,(row,col))) and .toarray() [OK]
Common Mistakes:
MISTAKES
  • Passing arguments incorrectly to coo_matrix
  • Using .todense() instead of .toarray()
  • Calling non-existent methods like to_list()

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