Built-in list functions in SASS - Cheat Sheet & Quick Revision

Recall & Review

beginner

What does the length() function do in Sass lists?

It returns the number of items in a list. For example, length(1 2 3) returns 3.

beginner

How do you get the first item of a list in Sass?

Use the nth() function with index 1. For example, nth(10 20 30, 1) returns 10.

intermediate

What does the join() function do in Sass?

It combines two lists into one. For example, join(1 2, 3 4) returns 1 2 3 4.

intermediate

Explain the difference between append() and join() in Sass lists.

append() adds a single item to the end of a list, while join() combines two lists into one longer list.

beginner

How can you check if a list is empty in Sass?

Use length() and check if it returns 0. For example, length(()) == 0 means the list is empty.

What does length(10 20 30) return in Sass?

A 30

B 3

C 10

D Error

length() returns the number of items in the list, which is 3 here.

Which function gets the second item from a list in Sass?

A append()

B length()

C join()

D nth()

nth() returns the item at the given index.

What does join(1 2, 3 4) produce?

A Error

B 1 2

C 1 2 3 4

D 3 4

join() combines two lists into one.

How do you add a single item to the end of a list in Sass?

A append()

B join()

C length()

D nth()

append() adds one item to the end of a list.

What does length(()) return?

A 0

B 1

C Error

D null

An empty list has length 0.

Describe how to get the third item from a Sass list and how to find out how many items it has.

Think about how you count items and pick one by position.

Explain the difference between append() and join() when working with Sass lists.

One adds a single item, the other merges lists.

Practice

1. What does the Sass function length() do when used on a list?

easy

A. Returns the number of items in the list

B. Returns the first item of the list

C. Adds a new item to the list

D. Joins two lists into one

Solution

1. Step 1: Understand the purpose of length()

   The length() function counts how many items are inside a list.

2. Step 2: Compare with other functions

   Functions like nth() get an item, append() adds items, and join() combines lists, so they do different things.

3. Final Answer:

   Returns the number of items in the list -> Option A

4. Quick Check:

   length() = count items [OK]

Hint: Remember length() counts items, not returns values [OK]

Common Mistakes:

• Confusing length() with nth()
• Thinking length() adds items
• Mixing length() with join()

2. Which of the following is the correct syntax to get the 3rd item from a list named $colors in Sass?

easy

A. get($colors, 3)

B. item($colors, 3)

C. nth($colors, 3)

D. $colors[3]

Solution

1. Step 1: Recall the function to access list items

   In Sass, nth() is used to get the item at a specific position in a list.

2. Step 2: Check syntax correctness

   The syntax is nth($list, index). Other options like get() or bracket notation are invalid in Sass.

3. Final Answer:

   nth($colors, 3) -> Option C

4. Quick Check:

   nth() = get item by position [OK]

Hint: Use nth(list, index) to get list items [OK]

Common Mistakes:

• Using bracket notation like arrays
• Using non-existent functions like get()
• Mixing up argument order

3. What will be the output of this Sass code?

$list1: 10px 20px 30px;
$list2: 40px 50px;
$result: join($list1, $list2);

What is the value of $result?

medium

A. 10px 20px 30px, 40px 50px

B. 40px 50px 10px 20px 30px

C. 10px 20px 30px 40px 50px

D. Error: join() requires three arguments

Solution

1. Step 1: Understand join() function behavior

   The join() function combines two lists into one list separated by a comma by default.

2. Step 2: Apply join() to given lists

   Joining $list1 and $list2 results in a list: 10px 20px 30px, 40px 50px (comma-separated).

3. Final Answer:

   10px 20px 30px, 40px 50px -> Option A

4. Quick Check:

   join() merges lists with comma separator by default [OK]

Hint: join() sticks lists together with comma separator by default [OK]

Common Mistakes:

• Thinking join() concatenates without separator
• Reversing list order
• Assuming join() needs three arguments

4. Identify the error in this Sass code snippet:

$my-list: 1 2 3;
$new-list: append($my-list, 4, comma);

medium

A. append() cannot add numbers to lists

B. The append() function requires the separator to be 'space' or 'comma' as a string, not a bare word

C. The list $my-list must be declared with parentheses

D. append() needs three arguments but only two are given

Solution

1. Step 1: Check append() function syntax

   The third argument for append() must be a string: either 'space' or 'comma'.

2. Step 2: Identify the error in the code

   The code uses comma without quotes, which is invalid syntax in Sass.

3. Final Answer:

   The append() function requires the separator to be 'space' or 'comma' as a string, not a bare word -> Option B

4. Quick Check:

   Separator must be a quoted string [OK]

Hint: Always quote 'space' or 'comma' in append() separator [OK]

Common Mistakes:

• Forgetting quotes around separator
• Thinking append() only takes two arguments
• Assuming lists need parentheses

5. Given two lists:

$listA: red green blue;
$listB: yellow orange;

You want to create a new list that contains all items from $listA followed by $listB, separated by spaces, and then add black at the end. Which Sass code correctly does this?

hard

A. $combined: join($listA, $listB, 'space') append(black);

B. $combined: join(append($listA, black, 'space'), $listB, 'comma');

C. $combined: append($listA, join($listB, black, 'space'), 'space');

D. $combined: append(join($listA, $listB, 'space'), black, 'space');

Solution

1. Step 1: Join $listA and $listB with space separator

   Use join($listA, $listB, 'space') to combine both lists with spaces.

2. Step 2: Append 'black' to the joined list with space separator

   Use append(..., black, 'space') to add 'black' at the end, keeping space separation.

3. Step 3: Verify other options

   $combined: join(append($listA, black, 'space'), $listB, 'comma'); uses comma separator incorrectly; $combined: append($listA, join($listB, black, 'space'), 'space'); nests join inside append wrongly; $combined: join($listA, $listB, 'space') append(black); syntax is invalid.

4. Final Answer:

   $combined: append(join($listA, $listB, 'space'), black, 'space'); -> Option D

5. Quick Check:

   join() then append() with 'space' separator [OK]

Hint: Join lists first, then append new item with same separator [OK]

Common Mistakes:

• Mixing comma and space separators
• Appending before joining lists
• Incorrect function chaining syntax