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SASSmarkup~5 mins

@return statement in SASS

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Introduction

The @return statement sends a value back from a Sass function. It helps reuse calculations and keep code clean.

When you want to create a reusable color calculation.
When you need to compute a size or spacing value once and use it multiple times.
When you want to write a function that returns a customized CSS value based on inputs.
When you want to keep your styles organized by separating logic into functions.
Syntax
SASS
@function function-name($parameter) {
  @return value;
}

The @return must be inside a @function.

Only one value can be returned at a time.

Examples
This function doubles the input number and returns it.
SASS
@function double($number) {
  @return $number * 2;
}
This function returns a lighter shade of black based on the input.
SASS
@function make-color($shade) {
  @return lighten(#000000, $shade);
}
Sample Program

This Sass code defines a function that multiplies the input size by 1.5 and returns it. Then it uses that function to set padding on a container.

SASS
@function calculate-padding($size) {
  @return $size * 1.5;
}

.container {
  padding: calculate-padding(2rem);
  background-color: #eee;
}
OutputSuccess
Important Notes

Functions with @return help avoid repeating the same math in many places.

If you forget @return, the function will not output a value and may cause errors.

Summary

The @return statement sends a value back from a Sass function.

Use it to create reusable calculations and keep your styles clean.

Always place @return inside a @function.

Practice

(1/5)
1. What does the @return statement do in Sass?
easy
A. It sends a value back from a Sass function.
B. It creates a new CSS rule.
C. It imports another Sass file.
D. It defines a variable.

Solution

  1. Step 1: Understand the purpose of @return

    The @return statement is used inside a Sass function to send a value back to where the function was called.
  2. Step 2: Differentiate from other Sass features

    Other options describe different Sass features: creating CSS rules, importing files, or defining variables, which are not the role of @return.
  3. Final Answer:

    It sends a value back from a Sass function. -> Option A
  4. Quick Check:

    @return sends value back [OK]
Hint: Remember: @return always sends a value back [OK]
Common Mistakes:
  • Thinking @return creates CSS rules
  • Confusing @return with variable declaration
  • Using @return outside a function
2. Which of the following is the correct syntax to return a value from a Sass function named double that doubles a number $n?
easy
A. @function double($n) { @output $n * 2; }
B. @function double($n) { return $n * 2; }
C. @function double($n) { $n * 2; }
D. @function double($n) { @return $n * 2; }

Solution

  1. Step 1: Identify correct Sass function syntax

    In Sass, functions start with @function and use @return to send back a value.
  2. Step 2: Check each option for correct usage

    @function double($n) { @return $n * 2; } uses @return correctly. @function double($n) { return $n * 2; } misses the @ before return. @function double($n) { $n * 2; } lacks any return statement. @function double($n) { @output $n * 2; } uses an invalid @output keyword.
  3. Final Answer:

    @function double($n) { @return $n * 2; } -> Option D
  4. Quick Check:

    Use @return inside @function [OK]
Hint: Always use @return with @function [OK]
Common Mistakes:
  • Omitting the '@' before return
  • Forgetting to include a return statement
  • Using invalid keywords like '@output'
3. What will be the output CSS of the following Sass code?
@function triple($x) {
  @return $x * 3;
}

.box {
  width: triple(10px);
}
medium
A. .box { width: 30px; }
B. .box { width: triple(10px); }
C. .box { width: 10px; }
D. Syntax error

Solution

  1. Step 1: Understand the function behavior

    The function triple multiplies the input by 3 and returns the result.
  2. Step 2: Calculate the returned value

    Calling triple(10px) returns 10px * 3 = 30px. This value is assigned to the width property.
  3. Final Answer:

    .box { width: 30px; } -> Option A
  4. Quick Check:

    Function returns 3 times input [OK]
Hint: Multiply input inside function, output is computed value [OK]
Common Mistakes:
  • Expecting the function name to appear in CSS
  • Ignoring units like px in calculations
  • Assuming no multiplication happens
4. Identify the error in this Sass function:
@function add($a, $b) {
  $sum: $a + $b;
}
medium
A. Cannot use addition inside functions.
B. Incorrect variable declaration syntax.
C. Missing @return statement to send back the result.
D. Function name should start with a dollar sign.

Solution

  1. Step 1: Check function body for return statement

    The function calculates $sum but never returns it. Sass functions must use @return to send a value back.
  2. Step 2: Verify other syntax elements

    Variable declaration and addition are correct. Function names do not start with a dollar sign. Addition is allowed inside functions.
  3. Final Answer:

    Missing @return statement to send back the result. -> Option C
  4. Quick Check:

    Functions need @return [OK]
Hint: Always end functions with @return [OK]
Common Mistakes:
  • Forgetting to return the calculated value
  • Thinking function names need $ prefix
  • Assuming calculations auto-return
5. You want to create a Sass function adjust-color-brightness that takes a color and a percentage, then returns the color lightened or darkened by that percentage. Which of these is the best way to use @return inside this function?
hard
A. @function adjust-color-brightness($color, $percent) { return if($percent > 0, lighten($color, $percent), darken($color, abs($percent))); }
B. @function adjust-color-brightness($color, $percent) { @if $percent > 0 { @return lighten($color, $percent); } @else { @return darken($color, abs($percent)); } }
C. @function adjust-color-brightness($color, $percent) { lighten($color, $percent); darken($color, abs($percent)); }
D. @function adjust-color-brightness($color, $percent) { @return lighten($color, $percent); @return darken($color, abs($percent)); }

Solution

  1. Step 1: Understand conditional return usage

    The function should return either a lightened or darkened color based on the sign of $percent. Using @if with separate @return statements is clear and correct.
  2. Step 2: Evaluate other options

    @function adjust-color-brightness($color, $percent) { return if($percent > 0, lighten($color, $percent), darken($color, abs($percent))); } uses return without @, which is invalid Sass syntax. @function adjust-color-brightness($color, $percent) { lighten($color, $percent); darken($color, abs($percent)); } lacks any @return, so no value is returned. @function adjust-color-brightness($color, $percent) { @return lighten($color, $percent); @return darken($color, abs($percent)); } has two @return statements in sequence, which is invalid because only one @return can be executed.
  3. Final Answer:

    @function adjust-color-brightness($color, $percent) { @if $percent > 0 { @return lighten($color, $percent); } @else { @return darken($color, abs($percent)); } } -> Option B
  4. Quick Check:

    Use conditional @return for multiple outcomes [OK]
Hint: Use one @return per condition inside functions [OK]
Common Mistakes:
  • Placing multiple @return statements without conditions
  • Not returning any value
  • Using function calls without returning them
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