Loop execution flow in Rust - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to print numbers from 1 to 5 using a loop.

Rust

for i in 1..=[1] {
    println!("{}", i);
}

Drag options to blanks, or click blank then click option'

A10

B6

C0

D5

Attempts:

3 left

💡 Hint

Common Mistakes

Using 6 will print numbers up to 6, which is one more than needed.

Using 0 will cause the loop to not run as expected.

The range 1..=5 includes numbers from 1 to 5, so the loop prints 1 to 5.

2fill in blank

medium

Complete the code to skip printing the number 3 inside the loop.

Rust

for i in 1..=5 {
    if i == [1] {
        continue;
    }
    println!("{}", i);
}

Drag options to blanks, or click blank then click option'

A2

B4

C3

D5

Attempts:

3 left

💡 Hint

Common Mistakes

Using a number other than 3 will skip the wrong iteration.

Forgetting to use continue will print all numbers.

The continue statement skips the current loop iteration when i equals 3, so 3 is not printed.

3fill in blank

hard

Fix the error in the loop to stop printing numbers when i equals 4.

Rust

for i in 1..=5 {
    if i == [1] {
        break;
    }
    println!("{}", i);
}

Drag options to blanks, or click blank then click option'

A4

B5

C6

D3

Attempts:

3 left

💡 Hint

Common Mistakes

Using 5 will print 4 before stopping, which is not desired.

Using 3 will stop too early.

The break statement stops the loop when i equals 4, so numbers 1 to 3 are printed.

4fill in blank

hard

Fill both blanks to create a loop that prints only even numbers from 1 to 10.

Rust

for i in 1..=[1] {
    if i % 2 [2] 0 {
        println!("{}", i);
    }
}

Drag options to blanks, or click blank then click option'

A10

B==

C!=

D5

Attempts:

3 left

💡 Hint

Common Mistakes

Using '!=' will print odd numbers instead.

Using 5 as upper limit will miss numbers 6 to 10.

The loop runs from 1 to 10. The condition i % 2 == 0 checks if i is even, so only even numbers are printed.

5fill in blank

hard

Fill all three blanks to create a loop that collects numbers greater than 3 into a vector.

Rust

let mut result = Vec::new();
for num in 1..=[1] {
    if num [2] [3] {
        result.push(num);
    }
}
println!("{:?}", result);

Drag options to blanks, or click blank then click option'

A5

B>

C3

D==

Attempts:

3 left

💡 Hint

Common Mistakes

Using '==' instead of '>' will only select number 3, not greater numbers.

Using 3 as upper limit will miss number 4 and 5.

The loop runs from 1 to 5. The condition num > 3 selects numbers greater than 3, which are pushed into the vector. The output will be [4, 5].