Logical operators in Rust - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to check if both conditions are true.

Rust

let a = true;
let b = false;
let result = a [1] b;
println!("{}", result);

Drag options to blanks, or click blank then click option'

A&&

B|

C||

D&

Attempts:

3 left

💡 Hint

Common Mistakes

Using || instead of && will return true if either is true.

The && operator returns true only if both a and b are true.

2fill in blank

medium

Complete the code to check if either condition is true.

Rust

let x = false;
let y = true;
let result = x [1] y;
println!("{}", result);

Drag options to blanks, or click blank then click option'

A&

B&&

C||

D|

Attempts:

3 left

💡 Hint

Common Mistakes

Using && instead of || will require both to be true.

The || operator returns true if at least one of x or y is true.

3fill in blank

hard

Fix the error in the code to correctly negate the boolean value.

Rust

let flag = true;
let negated = [1]flag;
println!("{}", negated);

Drag options to blanks, or click blank then click option'

Aneg

B!

Cnot

D~

Attempts:

3 left

💡 Hint

Common Mistakes

Using ~ or not which are not valid boolean negation in Rust.

The ! operator negates a boolean value in Rust.

4fill in blank

hard

Fill both blanks to create a condition that is true only if a is true and b is false.

Rust

let a = true;
let b = false;
if a [1] [2] b {
    println!("Condition met");
}

Drag options to blanks, or click blank then click option'

A&&

B||

C!

D==

Attempts:

3 left

💡 Hint

Common Mistakes

Using || instead of && will allow b to be true.

The condition uses && to require both parts true, and ! to negate b.

5fill in blank

hard

Fill all three blanks to create a condition that is true if either x is false or y is true and z is true.

Rust

let x = true;
let y = false;
let z = false;
if [1] x [2] y [3] z {
    println!("Complex condition met");
}

Drag options to blanks, or click blank then click option'

A!

B||

C&&

D==

Attempts:

3 left

💡 Hint

Common Mistakes

Mixing up operator precedence or forgetting to negate x.

The condition reads: if !x || y && z, which means true if x is false or both y and z are true.