If expression in Rust - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to print "Positive" if the number is greater than zero.

Rust

let number = 5;
if number [1] 0 {
    println!("Positive");
}

Drag options to blanks, or click blank then click option'

A<

B!=

C==

D>

Attempts:

3 left

💡 Hint

Common Mistakes

Using '<' instead of '>' will check for negative numbers.

Using '==' checks for equality, not greater than.

The condition number > 0 checks if the number is positive.

2fill in blank

medium

Complete the code to assign the string "even" or "odd" based on the number.

Rust

let number = 4;
let result = if number % 2 [1] 0 { "even" } else { "odd" };

Drag options to blanks, or click blank then click option'

A==

B!=

C>

D<

Attempts:

3 left

💡 Hint

Common Mistakes

Using '!=' will assign 'even' to odd numbers.

Using '>' or '<' does not correctly check for evenness.

The expression number % 2 == 0 checks if the number is even.

3fill in blank

hard

Fix the error in the if expression to correctly assign the maximum of two numbers.

Rust

let a = 10;
let b = 20;
let max = if a [1] b { b } else { a };

Drag options to blanks, or click blank then click option'

A<

B>

C==

D!=

Attempts:

3 left

💡 Hint

Common Mistakes

Using '>' will assign a as max incorrectly.

Using '==' or '!=' does not find the maximum.

The condition a < b means if a is less than b, then b is the max.

4fill in blank

hard

Fill in the blank to create a dictionary with word lengths for words longer than 3 letters.

Rust

let words = ["cat", "house", "dog", "elephant"];
let lengths = words.iter()
    .filter(|&word| word.len() [1] 3)
    .map(|word| (word, word.len()))
    .collect::<std::collections::HashMap<_, _>>();

Drag options to blanks, or click blank then click option'

A!=

B>

C==

D<

Attempts:

3 left

💡 Hint

Common Mistakes

Using '<' will select shorter words.

Using '==' will select only words of length 3.

The word.len() > 3 filters words longer than 3 letters.

5fill in blank

hard

Fill the blanks to create a HashMap of uppercase words and their lengths for words longer than 4 letters.

Rust

let words = ["apple", "bat", "carrot", "dog"];
let result = words.iter()
    .filter(|&word| word.len() [1] 4)
    .map(|word| (word.[2](), word.len()))
    .collect::<std::collections::HashMap<_, _>>();

Drag options to blanks, or click blank then click option'

A<

B>

Cto_uppercase

Dto_lowercase

Attempts:

3 left

💡 Hint

Common Mistakes

Using '<' will select shorter words.

Using 'to_lowercase' will convert words to lowercase instead of uppercase.

The filter selects words longer than 4 letters, then maps each word to its uppercase form and length.