Assignment operators in Rust - Mini Project: Build & Apply

Assignment operators

📖 Scenario: You are managing a small shop's inventory. You want to update the stock counts quickly using assignment operators.

🎯 Goal: Learn how to use assignment operators like +=, -=, *=, and /= in Rust to update variables efficiently.

📋 What You'll Learn

Create variables with initial stock counts

Create a variable for the number of items sold

Use assignment operators to update stock counts

Print the final stock counts

💡 Why This Matters

🌍 Real World

Assignment operators help update values quickly in programs like inventory management, budgeting apps, or games.

💼 Career

Understanding assignment operators is essential for writing clean and efficient code in any programming job.

1

Create initial stock variables

Create three variables called apples, bananas, and oranges with values 50, 30, and 20 respectively.

Rust

# Your code here

Hint

Use let mut to create variables that can change later.

2

Create a variable for sold items

Create a variable called sold and set it to 5 to represent items sold.

Rust

let mut apples = 50;
let mut bananas = 30;
let mut oranges = 20;
# Your code here

Hint

This variable does not need to change, so no mut needed.

3

Update stock using assignment operators

Use assignment operators to subtract sold from apples and bananas, and multiply oranges by 2.

Rust

let mut apples = 50;
let mut bananas = 30;
let mut oranges = 20;
let sold = 5;
# Your code here

Hint

Use -= to subtract and *= to multiply and assign.

4

Print the final stock counts

Print the values of apples, bananas, and oranges using println! with the format: "Apples: {}", "Bananas: {}", and "Oranges: {}".

Rust

let mut apples = 50;
let mut bananas = 30;
let mut oranges = 20;
let sold = 5;
apples -= sold;
bananas -= sold;
oranges *= 2;
# Your code here

Hint

Use println!("Text: {}", variable); to print variables with text.

Practice

1. What does the Rust assignment operator += do?

easy

A. Subtracts the right value from the left variable and stores the result in the variable

B. Adds the right value to the left variable and stores the result in the variable

C. Multiplies the right value with the left variable and stores the result in the variable

D. Divides the left variable by the right value and stores the result in the variable

Solution

1. Step 1: Understand the += operator

   The += operator adds the right-hand side value to the left-hand side variable.

2. Step 2: Effect on the variable

   The result of the addition is stored back into the same variable, updating its value.

3. Final Answer:

   Adds the right value to the left variable and stores the result in the variable -> Option B

4. Quick Check:

   += means add and assign [OK]

Hint: Think: add then store back in the same variable [OK]

Common Mistakes:

• Confusing += with subtraction or multiplication
• Forgetting that the variable must be mutable
• Thinking it creates a new variable instead of updating

2. Which of the following is the correct way to use the *= operator in Rust?

easy

A. let x = 5; x *= 2;

B. let mut x = 5; *= x 2;

C. let x = 5; mut x *= 2;

D. let mut x = 5; x *= 2;

Solution

1. Step 1: Check variable mutability

   In Rust, to change a variable's value, it must be declared with mut. So let mut x = 5; is correct.

2. Step 2: Correct operator usage

   The operator *= is used as x *= 2; to multiply and assign.

3. Final Answer:

   let mut x = 5; x *= 2; -> Option D

4. Quick Check:

   Mutable variable + operator syntax = correct [OK]

Hint: Declare variable mutable before using assignment operators [OK]

Common Mistakes:

• Not declaring variable as mutable
• Placing mut in wrong position
• Incorrect operator syntax like *= x 2

3. What is the output of the following Rust code?

let mut a = 10;
a += 5;
a *= 2;
println!("{}", a);

medium

A. 30

B. 25

C. 20

D. 15

Solution

1. Step 1: Perform a += 5;

   Starting with a = 10, adding 5 gives a = 15.

2. Step 2: Perform a *= 2;

   Multiplying 15 by 2 updates a = 30.

3. Final Answer:

   30 -> Option A

4. Quick Check:

   10 + 5 = 15; 15 * 2 = 30 [OK]

Hint: Calculate step-by-step updates to variable [OK]

Common Mistakes:

• Adding and multiplying in wrong order
• Forgetting variable is mutable
• Misreading operator effects

4. Identify the error in this Rust code snippet:

let x = 8;
x -= 3;
println!("{}", x);

medium

A. The println! macro is used incorrectly

B. The operator -= is not valid in Rust

C. Variable x is not mutable but is modified

D. Missing semicolon after println!

Solution

1. Step 1: Check variable mutability

   The variable x is declared without mut, so it is immutable.

2. Step 2: Check assignment operator usage

   The operator -= tries to subtract and assign a new value to x, which is not allowed for immutable variables.

3. Final Answer:

   Variable x is not mutable but is modified -> Option C

4. Quick Check:

   Immutable variable cannot be changed [OK]

Hint: Mutable variables needed for assignment operators [OK]

Common Mistakes:

• Assuming all variables are mutable by default
• Thinking operator syntax is wrong
• Ignoring Rust's immutability rules

5. Given the code below, what is the final value of result?

let mut result = 50;
let change = 7;
result %= change;
result += 3;
result *= 4;

hard

A. 16

B. 12

C. 28

D. 14

Solution

1. Step 1: Calculate result %= change;

   50 % 7 equals 1 because 7 * 7 = 49 and remainder is 1, so result = 1.

2. Step 2: Calculate result += 3;

   Add 3 to 1 gives result = 4.

3. Step 3: Calculate result *= 4;

   Multiply 4 by 4 gives result = 16.

4. Final Answer:

   16 -> Option A

5. Quick Check:

   50 % 7 = 1; 1 + 3 = 4; 4 * 4 = 16 [OK]

Hint: Apply each operator stepwise carefully [OK]

Common Mistakes:

• Miscomputing modulus operation
• Skipping steps or doing operations out of order
• Choosing wrong multiplication result