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Rustprogramming~30 mins

Arithmetic operators in Rust - Mini Project: Build & Apply

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Arithmetic Operators in Rust
๐Ÿ“– Scenario: You are helping a small shop calculate prices for items bought by customers. You will use arithmetic operators to add, subtract, multiply, and divide numbers.
๐ŸŽฏ Goal: Build a Rust program that uses arithmetic operators to calculate the total price, discount, and final price for a product.
๐Ÿ“‹ What You'll Learn
Create variables with exact values for price and quantity
Create a variable for discount rate
Calculate total price and discount amount using arithmetic operators
Print the final price after discount
๐Ÿ’ก Why This Matters
๐ŸŒ Real World
Calculating prices, discounts, and totals is common in shopping apps and billing systems.
๐Ÿ’ผ Career
Understanding arithmetic operations and data types is essential for software development, especially in finance and retail applications.
Progress0 / 4 steps
1
Create initial variables for price and quantity
Create a variable called price with the value 50.0 and a variable called quantity with the value 3.
Rust
Hint

Use let to create variables. Price is a floating-point number, quantity is an integer.

2
Add a discount rate variable
Add a variable called discount_rate with the value 0.1 to represent a 10% discount.
Rust
Hint

Discount rate is a floating-point number between 0 and 1.

3
Calculate total price and discount amount
Create a variable called total_price that multiplies price and quantity. Then create a variable called discount_amount that multiplies total_price and discount_rate.
Rust
Hint

Multiply price and quantity. Convert quantity to f64 to match price type.

4
Print the final price after discount
Calculate the final price by subtracting discount_amount from total_price and print it using println! with the message: "Final price: {final_price}".
Rust
Hint

Subtract discount_amount from total_price. Use println!("Final price: {}", final_price); to show the result.

Practice

(1/5)
1. Which arithmetic operator in Rust is used to find the remainder of a division?
easy
A. The - operator
B. The / operator
C. The * operator
D. The % operator

Solution

  1. Step 1: Understand the meaning of each operator

    The / operator divides, * multiplies, - subtracts, and % gives the remainder after division.
  2. Step 2: Identify the operator for remainder

    The % operator returns the remainder when one number is divided by another.
  3. Final Answer:

    The % operator -> Option D
  4. Quick Check:

    Remainder operator = % [OK]
Hint: Remainder always uses % in math [OK]
Common Mistakes:
  • Confusing / with %, thinking / gives remainder
  • Using * or - for remainder
  • Mixing up operator symbols
2. Which of the following is the correct way to write multiplication of two variables a and b in Rust?
easy
A. a * b
B. a x b
C. a . b
D. a & b

Solution

  1. Step 1: Recall Rust arithmetic syntax

    Rust uses * for multiplication, not x, ., or &.
  2. Step 2: Confirm correct operator

    The expression a * b correctly multiplies a and b.
  3. Final Answer:

    a * b -> Option A
  4. Quick Check:

    Multiplication operator = * [OK]
Hint: Use * for multiplication in Rust [OK]
Common Mistakes:
  • Using x instead of *
  • Using . or & which are not arithmetic
  • Confusing syntax with other languages
3. What is the output of the following Rust code?
let x = 10;
let y = 3;
let result = x / y;
println!("{}", result);
medium
A. 4
B. 3.3333
C. 3
D. Syntax error

Solution

  1. Step 1: Understand integer division in Rust

    Both x and y are integers, so x / y performs integer division, dropping decimals.
  2. Step 2: Calculate integer division

    10 divided by 3 is 3.3333, but integer division truncates to 3.
  3. Final Answer:

    3 -> Option C
  4. Quick Check:

    Integer division truncates decimals = 3 [OK]
Hint: Integer division drops decimals, use floats for precise result [OK]
Common Mistakes:
  • Expecting decimal result with integer division
  • Confusing integer and float division
  • Assuming syntax error due to println!
4. Identify the error in this Rust code snippet:
let a = 5;
let b = 2;
let c = a / b.0;
println!("{}", c);
medium
A. Variables a and b are not declared
B. Using .0 on integer causes error
C. Missing semicolon after println!
D. Division operator / is invalid

Solution

  1. Step 1: Analyze the expression a / b.0

    The code tries to access .0 on b, which is an integer, not a tuple or struct.
  2. Step 2: Understand why .0 causes error

    Only tuples or structs have fields like .0; integers do not, so this causes a compile error.
  3. Final Answer:

    Using .0 on integer causes error -> Option B
  4. Quick Check:

    Integer has no .0 field = error [OK]
Hint: Only tuples/structs have .0, not integers [OK]
Common Mistakes:
  • Thinking / is invalid operator
  • Missing semicolon causes error
  • Assuming variables are undeclared
5. You want to calculate the average of two integers a and b in Rust and get a float result. Which code snippet correctly does this?
hard
A. let avg = (a + b) as f64 / 2.0;
B. let avg = (a + b) / 2.0;
C. let avg = (a + b) / 2;
D. let avg = (a + b) / 2 as f64;

Solution

  1. Step 1: Understand type conversion for float division

    To get a float result, convert integers to float before division.
  2. Step 2: Check each option for correct syntax and types

    let avg = (a + b) / 2; does integer division, no float result. let avg = (a + b) as f64 / 2.0; converts sum to f64, divides by 2.0 (float), correct. let avg = (a + b) / 2.0; divides integer sum by float 2.0 without conversion, invalid. let avg = (a + b) / 2 as f64; tries to cast 2 to f64 before division (due to `as` precedence), invalid.
  3. Final Answer:

    let avg = (a + b) as f64 / 2.0; -> Option A
  4. Quick Check:

    Convert to float before dividing by float [OK]
Hint: Cast sum to float before dividing by float [OK]
Common Mistakes:
  • Dividing integers by float without cast
  • Casting after division
  • Using integer division expecting float result
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10 questions~5 mineasy hard