[Solved] Given the method below, what will be the output? def repeat(n) if block_given? n.times { |i| yield(i) } else puts "No block given" end end repeat(3) { |num| puts num * 2 } | Ruby

Ruby - Blocks, Procs, and Lambdas

Given the method below, what will be the output?

def repeat(n)
  if block_given?
    n.times { |i| yield(i) }
  else
    puts "No block given"
  end
end

repeat(3) { |num| puts num * 2 }

A0 1 2

B1 2 3

C0 2 4

DNo block given

Step-by-Step Solution

Solution:

Step 1: Analyze the method behavior
The method repeat checks if a block is given. Since a block is passed, it runs n.times and yields the index i to the block.
Step 2: Evaluate the block execution
The block multiplies each yielded number by 2 and prints it. For n=3, i goes 0,1,2, so outputs are 0, 2, 4.
Final Answer:
0 2 4 -> Option C
Quick Check:
Yield with times and block multiplies index = D [OK]

Quick Trick: Yield passes each index to block in times loop [OK]

Common Mistakes:

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