[Solved] Given this code, what will be the output?def test_lambda l = ->(x) { return x * 2 } l.call(5) return 10 end puts test_lambda | Ruby

Ruby - Blocks, Procs, and Lambdas

Given this code, what will be the output?

def test_lambda
  l = ->(x) { return x * 2 }
  l.call(5)
  return 10
end
puts test_lambda

ANothing printed

B10

CError: unexpected return

D5

Step-by-Step Solution

Solution:

Step 1: Understand return behavior inside lambda
Return inside a lambda returns from the lambda itself, not from the enclosing method.
Step 2: Trace method execution
l.call(5) returns 10 but method continues and returns 10 explicitly at the end.
Final Answer:
10 -> Option B
Quick Check:
Lambda return exits lambda only = 10 [OK]

Quick Trick: Return in lambda exits lambda, not method [OK]

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