[Solved] What will be the output of this Ruby code? arr1 = [4, 5, 6] arr2 = ['x', 'y'] result = arr1.zip(arr2) puts result.inspect | Ruby

Ruby - Enumerable and Collection Processing

What will be the output of this Ruby code?

arr1 = [4, 5, 6]
arr2 = ['x', 'y']
result = arr1.zip(arr2)
puts result.inspect

A[[4, "x"], [5, "y"], [6, nil]]

B[[4, "x"], [5, "y"]]

C[[4, 5, 6], ["x", "y"]]

DError due to different array sizes

Step-by-Step Solution

Solution:

Step 1: Understand zip with unequal lengths
If arrays differ in length, zip fills missing elements with nil.
Step 2: Apply to given arrays
Third element of arr1 has no pair, so paired with nil.
Final Answer:
[[4, "x"], [5, "y"], [6, nil]] -> Option A
Quick Check:
Check for nil in last pair [OK]

Quick Trick: Missing pairs become nil in zipped arrays [OK]

Common Mistakes:

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