Each for iteration in Ruby - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to print each number in the array.

Ruby

numbers = [1, 2, 3]
numbers.[1] do |num|
  puts num
end

Drag options to blanks, or click blank then click option'

Areduce

Beach

Cmap

Dselect

Attempts:

3 left

💡 Hint

Common Mistakes

Using map instead of each when you only want to print values.

Using select which filters elements instead of iterating all.

The each method iterates over each element in the array and executes the block for each element.

2fill in blank

medium

Complete the code to print each word in uppercase.

Ruby

words = ['cat', 'dog', 'bird']
words.[1] do |word|
  puts word.upcase
end

Drag options to blanks, or click blank then click option'

Amap

Bselect

Creduce

Deach

Attempts:

3 left

💡 Hint

Common Mistakes

Using map which returns a new array instead of just printing.

Using select which filters elements.

The each method is used to perform an action on each element without changing the original array.

3fill in blank

hard

Fix the error in the code to correctly iterate over the hash and print keys and values.

Ruby

person = {name: 'Alice', age: 30}
person.[1] do |key, value|
  puts "#{key}: #{value}"
end

Drag options to blanks, or click blank then click option'

Aselect

Bmap

Ceach

Dreduce

Attempts:

3 left

💡 Hint

Common Mistakes

Using map which returns a new array instead of just iterating.

Using select which filters elements.

The each method correctly iterates over key-value pairs in a hash.

4fill in blank

hard

Fill both blanks to create a hash with words as keys and their lengths as values.

Ruby

words = ['apple', 'banana', 'cherry']
lengths = words.map { |word| [[1], [2]] }.to_h

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Aword

Blen(word)

Cword.length

Dword.size

Attempts:

3 left

💡 Hint

Common Mistakes

Using Python's len() function instead of Ruby's length method.

Using word.size as key instead of value.

In Ruby, word.length returns the length of the string word. Use word as key and word.length as value.

5fill in blank

hard

Fill all three blanks to create a hash with uppercase words as keys and their lengths as values, only for words longer than 5 letters.

Ruby

words = ['apple', 'banana', 'cherry', 'date']
lengths = words.select { |word| word.length [3] 5 }.map { |word| [[1], [2]] }.to_h

Drag options to blanks, or click blank then click option'

Aword.upcase

Bword.length

C>

Dword.size

Attempts:

3 left

💡 Hint

Common Mistakes

Using Python syntax like len(word) instead of Ruby methods.

Using < instead of > in the condition.

The key is the uppercase version of the word using word.upcase. The value is the length of the word with word.length. The condition filters words longer than 5 letters using >.