This calls the parent add method with specific arguments and then doubles the result.
Ruby
class Parent
def add(a, b)
a + b
endendclass Child < Parent
def add(a, b)
result = super(a, b)
result * 2endendputs Child.new.add(3, 4)
Sample Program
The Dog class calls the speak method from Animal using super, then adds its own message.
Ruby
class Animal
def speak(sound)
puts"Animal says: #{sound}"endendclass Dog < Animal
def speak(sound)
superputs"Dog wags tail."endend
Dog.new.speak("Woof")
OutputSuccess
Important Notes
If the parent method does not exist, calling super will cause an error.
Using super helps keep code DRY (Don't Repeat Yourself).
Summary
super calls the parent class's method from a child class.
Without parentheses, super passes all current arguments to the parent method.
With empty parentheses super(), it calls the parent method with no arguments.
Practice
(1/5)
1. What does the super keyword do in Ruby?
easy
A. Creates a new instance of the parent class
B. Overrides the parent class's method permanently
C. Calls the parent class's method with the same name
D. Deletes the parent class's method
Solution
Step 1: Understand the role of super
The super keyword is used inside a child class method to call the method with the same name from its parent class. It does not create, override, or delete methods but simply calls the parent method to reuse or extend its behavior.
Final Answer:
Calls the parent class's method with the same name -> Option C
Quick Check:
super calls parent method [OK]
Hint: Remember: super calls parent method with same name [OK]
Common Mistakes:
Thinking super creates or deletes methods
Confusing super with instance creation
Assuming super overrides methods permanently
2. Which of the following is the correct syntax to call the parent method with no arguments using super?
easy
A. super()
B. super[]
C. super
D. super{}
Solution
Step 1: Understand super with parentheses
Using super() calls the parent method explicitly with no arguments, ignoring any current method arguments. Only super() uses parentheses correctly to pass no arguments; other forms are invalid syntax.
Final Answer:
super() -> Option A
Quick Check:
super() means no arguments [OK]
Hint: Use parentheses to call parent with no args: super() [OK]
Common Mistakes:
Using super without parentheses to mean no arguments
Using brackets or braces instead of parentheses
Confusing super() with super without parentheses
3. What will be the output of this Ruby code?
class Parent
def greet(name)
"Hello, #{name} from Parent"
end
end
class Child < Parent
def greet(name)
super + " and Child"
end
end
puts Child.new.greet("Alice")
medium
A. Hello, Alice from Parent and Child
B. Hello, Alice from Child
C. Hello, from Parent and Child
D. Error: wrong number of arguments
Solution
Step 1: Trace the method call in Child#greet
The Child's greet method calls super without parentheses, so it passes the argument "Alice" to Parent#greet. Parent#greet returns "Hello, Alice from Parent". Child appends " and Child" to this string.
Final Answer:
Hello, Alice from Parent and Child -> Option A
Quick Check:
super passes args, output combines strings [OK]
Hint: super without () passes all args automatically [OK]
Common Mistakes:
Assuming super passes no arguments by default
Expecting an error due to argument mismatch
Ignoring the appended string in Child method
4. Identify the error in this Ruby code:
class Parent
def initialize(age)
@age = age
end
end
class Child < Parent
def initialize
super
@name = "Child"
end
end
Child.new
medium
A. NameError for @name variable
B. No error, code runs fine
C. SyntaxError due to missing parentheses
D. ArgumentError: wrong number of arguments for super
Solution
Step 1: Check Parent initialize method
Parent's initialize requires one argument age. Child's initialize calls super without arguments, so it tries to call Parent's initialize with zero arguments, causing an ArgumentError.
Final Answer:
ArgumentError: wrong number of arguments for super -> Option D
Quick Check:
super must match parent args or use super() [OK]
Hint: super without args passes current args; mismatch causes error [OK]
Thinking missing parentheses cause syntax error here
5. Given this code, what will Child.new.greet output?
class Parent
def greet(name = "Guest")
"Hello, #{name} from Parent"
end
end
class Child < Parent
def greet(name = nil)
if name
super(name.upcase)
else
super()
end
end
end
puts Child.new.greet
puts Child.new.greet("alice")
hard
A. Hello, from Parent
Hello, alice from Parent
B. Hello, Guest from Parent
Hello, ALICE from Parent
C. Hello, Guest from Parent
Hello, alice from Parent
D. Error due to wrong arguments in super calls
Solution
Step 1: Analyze Child#greet with no argument
When called without argument, name is nil, so super() calls Parent#greet with no arguments, using default "Guest". When called with "alice", name.upcase is "ALICE" passed to super(name.upcase), so Parent#greet returns "Hello, ALICE from Parent".
Final Answer:
Hello, Guest from Parent
Hello, ALICE from Parent -> Option B
Quick Check:
super() calls parent with defaults; super(args) passes modified args [OK]
Hint: Use super() for no args, super(args) to pass specific args [OK]
Common Mistakes:
Assuming super() passes current args
Ignoring default parameter in Parent#greet
Not uppercasing the argument before passing
Recommended
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