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Rubyprogramming~10 mins

Why methods always return a value in Ruby - Test Your Understanding

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to return the sum of two numbers.

Ruby
def add(a, b)
  a [1] b
end
Drag options to blanks, or click blank then click option'
A+
B-
C*
D/
Attempts:
3 left
💡 Hint
Common Mistakes
Using subtraction or multiplication instead of addition.
2fill in blank
medium

Complete the method to return the last word of a sentence.

Ruby
def last_word(sentence)
  words = sentence.split(' ')
  words.[1]
end
Drag options to blanks, or click blank then click option'
Apop
Bfirst
Cshift
Dlast
Attempts:
3 left
💡 Hint
Common Mistakes
Using first or shift which return the first element.
3fill in blank
hard

Fix the error in the method so it returns the square of a number.

Ruby
def square(num)
  num [1] num
end
Drag options to blanks, or click blank then click option'
A/
B-
C*
D+
Attempts:
3 left
💡 Hint
Common Mistakes
Using addition or subtraction instead of multiplication.
4fill in blank
hard

Fill the blank to create a method that returns true if a number is even.

Ruby
def even?(num)
  num.[1]
end
Drag options to blanks, or click blank then click option'
Aeven?
B0
C1
Dodd?
Attempts:
3 left
💡 Hint
Common Mistakes
Using odd? instead of even?.
5fill in blank
hard

Fill all three blanks to create a method that returns a hash of word lengths for words longer than 3 letters.

Ruby
def word_lengths(words)
  lengths = {}
  words.each do |word|
    if word.length [3] 3
      lengths[[1]] = [2]
    end
  end
  lengths
end
Drag options to blanks, or click blank then click option'
Aword
Bword.length
C>
D<
Attempts:
3 left
💡 Hint
Common Mistakes
Using less than instead of greater than for filtering.

Practice

(1/5)
1. Why do Ruby methods always return a value even if there is no explicit return statement?
easy
A. Because Ruby methods must always have a return statement.
B. Because Ruby methods return the first line's value automatically.
C. Because Ruby methods return nil by default if no value is given.
D. Because Ruby automatically returns the value of the last executed line in the method.

Solution

  1. Step 1: Understand Ruby method return behavior

    Ruby methods do not require an explicit return statement to send back a value.
  2. Step 2: Identify what value is returned

    The value of the last executed line inside the method is automatically returned.
  3. Final Answer:

    Because Ruby automatically returns the value of the last executed line in the method. -> Option D
  4. Quick Check:

    Last line value returned [OK]
Hint: Remember: last line in method is returned automatically [OK]
Common Mistakes:
  • Thinking a return statement is always needed
  • Believing methods return nil if no return is used
  • Assuming the first line's value is returned
2. Which of the following is the correct way to define a Ruby method that returns the sum of two numbers without using an explicit return?
easy
A. def add(a, b) return a + b end
B. def add(a, b) a + b end
C. def add(a, b) puts a + b end
D. def add(a, b) a + b; nil end

Solution

  1. Step 1: Check method syntax without explicit return

    def add(a, b) a + b end defines a method where the last line is a + b, which will be returned automatically.
  2. Step 2: Compare other options

    def add(a, b) return a + b end uses explicit return (also correct but not asked). def add(a, b) puts a + b end prints the sum but returns nil. def add(a, b) a + b; nil end returns nil explicitly.
  3. Final Answer:

    def add(a, b) a + b end -> Option B
  4. Quick Check:

    Last line expression returned [OK]
Hint: Last expression in method is returned without return keyword [OK]
Common Mistakes:
  • Using puts instead of returning value
  • Adding explicit nil at the end
  • Confusing printing with returning
3. What will be the output of the following Ruby code?
def greet(name)
  "Hello, #{name}!"
  42
end

puts greet("Alice")
medium
A. "Hello, Alice!"
B. nil
C. 42
D. SyntaxError

Solution

  1. Step 1: Analyze method body lines

    The method has two lines: first creates a string but does not return it explicitly; second line is the number 42.
  2. Step 2: Identify returned value

    Ruby returns the last evaluated expression, which is 42.
  3. Final Answer:

    42 -> Option C
  4. Quick Check:

    Last line value returned = 42 [OK]
Hint: Method returns last line value, not earlier lines [OK]
Common Mistakes:
  • Assuming first string line is returned
  • Confusing puts output with return value
  • Expecting nil because no explicit return
4. The following Ruby method is intended to return the string "Done", but it returns nil instead. What is the error?
def finish
  puts "Done"
end

result = finish
puts result.inspect
medium
A. The method uses puts which returns nil, so method returns nil.
B. The method is missing an explicit return statement.
C. The method should use print instead of puts.
D. The method name is reserved and cannot be used.

Solution

  1. Step 1: Understand what puts returns

    puts prints to screen but returns nil.
  2. Step 2: Identify method return value

    Since puts "Done" is the last line, method returns nil.
  3. Final Answer:

    The method uses puts which returns nil, so method returns nil. -> Option A
  4. Quick Check:

    puts returns nil [OK]
Hint: puts returns nil, so method returns nil if last line is puts [OK]
Common Mistakes:
  • Thinking puts returns the printed string
  • Believing explicit return is always needed
  • Confusing print and puts behavior
5. You want a Ruby method to return the first non-nil value from two expressions. Which method definition correctly uses Ruby's automatic return to achieve this?
def first_non_nil(a, b)
  # fill in
end
hard
A. def first_non_nil(a, b) a || b end
B. def first_non_nil(a, b) return a if a return b end
C. def first_non_nil(a, b) puts a || b end
D. def first_non_nil(a, b) a b end

Solution

  1. Step 1: Understand the goal

    We want the method to return the first non-nil value between a and b.
  2. Step 2: Check each option's return value

    def first_non_nil(a, b) a || b end returns a || b which evaluates to first non-nil value automatically. def first_non_nil(a, b) return a if a return b end uses explicit returns but is longer. def first_non_nil(a, b) puts a || b end prints but returns nil. def first_non_nil(a, b) a b end returns b always because last line is b.
  3. Final Answer:

    def first_non_nil(a, b) a || b end -> Option A
  4. Quick Check:

    Last expression returns first non-nil [OK]
Hint: Use last line expression to return desired value without return [OK]
Common Mistakes:
  • Using puts instead of returning value
  • Writing multiple return statements unnecessarily
  • Returning wrong line's value
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