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Rubyprogramming~10 mins

Default values for missing keys in Ruby - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to create a hash with a default value of 0.

Ruby
counts = Hash.new([1])
Drag options to blanks, or click blank then click option'
A''
Bfalse
Cnil
D0
Attempts:
3 left
💡 Hint
Common Mistakes
Using nil as default value returns nil for missing keys, not 0.
Using empty string '' sets default to a string, not a number.
2fill in blank
medium

Complete the code to create a hash with a default value of an empty array.

Ruby
groups = Hash.new([1])
Drag options to blanks, or click blank then click option'
A{}
B[]
Cnil
D0
Attempts:
3 left
💡 Hint
Common Mistakes
Using curly braces {} creates an empty hash, not an array.
Using nil means missing keys return nil, not an array.
3fill in blank
hard

Fix the error in the code to correctly set a default value that is a new empty array for each missing key.

Ruby
groups = Hash.new { |hash, key| hash[[1]] = [] }
Drag options to blanks, or click blank then click option'
Akey
Bhash
Cgroups
Dvalue
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'hash' instead of 'key' as the index causes an error.
Using 'value' is incorrect because the block only has hash and key parameters.
4fill in blank
hard

Fill both blanks to create a hash that counts occurrences of words.

Ruby
counts = Hash.new([1])
words.each do |word|
  counts[word] = counts[word] [2] 1
end
Drag options to blanks, or click blank then click option'
A0
B+
C-
D*
Attempts:
3 left
💡 Hint
Common Mistakes
Using '-' subtracts instead of adding.
Using '*' multiplies, which is incorrect for counting.
5fill in blank
hard

Fill all three blanks to create a hash with default value as a new array and add elements to it.

Ruby
groups = Hash.new { |hash, [1]| hash[[2]] = [3] }
groups[:fruits] << 'apple'
Drag options to blanks, or click blank then click option'
Akey
C[]
D{}
Attempts:
3 left
💡 Hint
Common Mistakes
Using '{}' assigns an empty hash instead of an array.
Using different names for the key parameter causes errors.

Practice

(1/5)
1. What does setting a default value for a Ruby hash do when you access a key that does not exist?
h = Hash.new(0)
easy
A. Returns the default value instead of nil for missing keys
B. Raises an error for missing keys
C. Adds the missing key with nil value to the hash
D. Returns nil for missing keys as usual

Solution

  1. Step 1: Understand default value behavior

    When a hash is created with Hash.new(0), it sets 0 as the default value for any missing key.
  2. Step 2: Accessing a missing key

    Accessing a key not present in the hash returns the default value 0 instead of nil.
  3. Final Answer:

    Returns the default value instead of nil for missing keys -> Option A
  4. Quick Check:

    Default value = 0 returned for missing keys [OK]
Hint: Default value replaces nil for missing keys [OK]
Common Mistakes:
  • Thinking missing keys raise errors
  • Assuming missing keys return nil always
  • Believing missing keys get added automatically
2. Which of the following is the correct syntax to create a Ruby hash with a default value of an empty array for missing keys?
easy
A. h = Hash.new { |key| [] }
B. h = Hash.new { [] }
C. h = Hash.new([])
D. h = Hash.new { |hash, key| hash[key] = [] }

Solution

  1. Step 1: Understand default block usage

    Using a block with Hash.new allows dynamic default values. To assign a new array to each missing key, the block must assign it to the hash.
  2. Step 2: Identify correct block syntax

    The block receives hash and key parameters and assigns [] to hash[key]. This ensures each missing key gets its own array.
  3. Final Answer:

    h = Hash.new { |hash, key| hash[key] = [] } -> Option D
  4. Quick Check:

    Block assigns new array to missing keys [OK]
Hint: Use block with two params to assign default arrays [OK]
Common Mistakes:
  • Using Hash.new([]) shares one array for all keys
  • Using block without assigning to hash[key]
  • Using wrong block parameters
3. What is the output of the following Ruby code?
h = Hash.new { |hash, key| hash[key] = [] }
h[:a] << 1
h[:b] << 2
p h
medium
A. {:a=>[1], :b=>[2], :c=>[]}
B. {:a=>[1], :b=>[2], nil=>[]}
C. {:a=>[1], :b=>[2]}
D. {}

Solution

  1. Step 1: Understand default block behavior

    The hash is created with a block that assigns an empty array to missing keys when accessed.
  2. Step 2: Modify arrays for keys :a and :b

    Appending 1 to h[:a] creates :a => [1]. Similarly, appending 2 to h[:b] creates :b => [2].
  3. Step 3: Print the hash

    Only keys :a and :b have values. No other keys exist.
  4. Final Answer:

    {:a=>[1], :b=>[2]} -> Option C
  5. Quick Check:

    Default arrays assigned and modified correctly [OK]
Hint: Default block assigns new array per missing key [OK]
Common Mistakes:
  • Expecting keys not accessed to appear
  • Confusing default value with nil
  • Thinking default array is shared
4. Identify the error in this Ruby code that tries to set a default value of 0 for missing keys:
h = Hash.new
h.default = 0
puts h[:missing]
medium
A. h.default=0 sets default but does not affect missing keys
B. No error; code works and prints 0
C. h.default=0 should be h.default = 0 (space required)
D. Syntax error in setting default value

Solution

  1. Step 1: Check default value assignment

    Using h.default = 0 correctly sets the default value for missing keys after hash creation.
  2. Step 2: Access missing key

    Accessing h[:missing] returns 0 as expected, no error occurs.
  3. Final Answer:

    No error; code works and prints 0 -> Option B
  4. Quick Check:

    Setting default after creation works [OK]
Hint: Use h.default = value to set default after creation [OK]
Common Mistakes:
  • Thinking default= is a syntax error
  • Confusing default= with default_proc
  • Expecting missing keys to raise errors
5. You want a Ruby hash that counts how many times each word appears in an array. Which code correctly uses default values to do this?
words = ['apple', 'banana', 'apple', 'orange', 'banana', 'apple']
counter = ???
words.each { |w| counter[w] += 1 }
puts counter
hard
A. counter = Hash.new(0)
B. counter = Hash.new { |h, k| [] }
C. counter = Hash.new([])
D. counter = {}

Solution

  1. Step 1: Understand counting with default values

    To count words, missing keys must return 0 so counter[w] += 1 works. The += reads the default 0, increments to 1, and assigns back, storing the key.
  2. Step 2: Compare options

    Hash.new(0) returns 0 for missing keys (no store); += 1 stores the result. Perfect for counting.
    Hash.new { |h, k| [] } returns []; [] += 1 TypeError.
    Hash.new([]) returns shared []; TypeError.
    {} returns nil; error.
  3. Final Answer:

    counter = Hash.new(0) -> Option A
  4. Quick Check:

    Hash.new(0) enables counter[w] += 1 [OK]
Hint: Hash.new(0) for numeric counting [OK]
Common Mistakes:
  • Using block or Hash.new([]) returns array; TypeError on += 1
  • Using {} with no default; nil error
  • Wrong block parameters or no assignment
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10 questions~5 mineasy hard