Array methods (length, include?, flatten) in Ruby - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to get the number of elements in the array.

Ruby

numbers = [1, 2, 3, 4, 5]
count = numbers.[1]
puts count

Drag options to blanks, or click blank then click option'

Atotal

Bsize

Ccount

Dlength

Attempts:

3 left

💡 Hint

Common Mistakes

Using a method that does not exist like 'total'.

Confusing 'length' with 'include?'.

The length method returns the number of elements in an array.

2fill in blank

medium

Complete the code to check if the array contains the number 3.

Ruby

numbers = [1, 2, 3, 4, 5]
has_three = numbers.[1](3)
puts has_three

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Ahas?

Binclude?

Ccontains?

Dexists?

Attempts:

3 left

💡 Hint

Common Mistakes

Using methods that do not exist like 'contains?'.

Forgetting the question mark at the end of 'include?'.

The include? method checks if an array has a specific element and returns true or false.

3fill in blank

hard

Fix the error in the code to flatten the nested array into a single array.

Ruby

nested = [[1, 2], [3, 4], [5]]
flat = nested.[1]
puts flat.inspect

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Aflatten

Bflatten!

Cflat!

Dflat

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'flatten!' which modifies the original array instead of returning a new one.

Using non-existent methods like 'flat' or 'flat!'.

The flatten method returns a new array that is a one-dimensional flattening of the original nested array.

4fill in blank

hard

Fill both blanks to create a hash with words as keys and their lengths as values, only for words longer than 3 letters.

Ruby

words = ["apple", "cat", "banana", "dog"]
lengths = words.each_with_object({}) do |word, h|
  if word.[1] [2] 3
    h[word] = word.[1]
  end
end
puts lengths

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A.length

B>

Clength

D<

Attempts:

3 left

💡 Hint

Common Mistakes

Using '.length' which causes a syntax error (double dot).

Using '<' instead of '>' for the condition.

Use length to get the word length and > to check if it is greater than 3.

5fill in blank

hard

Fill all three blanks to create a hash with uppercase words as keys and their lengths as values, only for words longer than 3 letters.

Ruby

words = ["apple", "cat", "banana", "dog"]
lengths = words.each_with_object({}) do |word, h|
  if word.[2] [3] 3
    h[word[1]] = word.[2]
  end
end
puts lengths

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A.upcase

Blength

C>

Dcapitalize

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'capitalize' instead of 'upcase' for uppercase keys.

Using '<' instead of '>' in the condition.

Use .upcase to make keys uppercase, length to get word length, and > to filter words longer than 3 letters.