Array comparison and set operations in Ruby - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to check if two arrays are equal.

Ruby

arr1 = [1, 2, 3]
arr2 = [1, 2, 3]
puts arr1 [1] arr2

Drag options to blanks, or click blank then click option'

A==

B!=

C===

Dequal?

Attempts:

3 left

💡 Hint

Common Mistakes

Using equal? which checks object identity, not content equality.

Using != which checks inequality.

In Ruby, == checks if two arrays have the same elements in the same order.

2fill in blank

medium

Complete the code to find the intersection of two arrays.

Ruby

arr1 = [1, 2, 3, 4]
arr2 = [3, 4, 5, 6]
common = arr1 [1] arr2
puts common.inspect

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A&

B-

C|

D^

Attempts:

3 left

💡 Hint

Common Mistakes

Using | which returns union, not intersection.

Using - which returns difference.

The & operator returns elements common to both arrays (intersection).

3fill in blank

hard

Fix the error in the code to get the union of two arrays.

Ruby

arr1 = [1, 2]
arr2 = [2, 3]
union = arr1 [1] arr2
puts union.inspect

Drag options to blanks, or click blank then click option'

A+

B|

C&

D-

Attempts:

3 left

💡 Hint

Common Mistakes

Using + which concatenates but does not remove duplicates.

Using & which returns intersection.

The | operator returns the union of two arrays without duplicates.

4fill in blank

hard

Fill both blanks to create a hash with array elements as keys and their lengths as values, only for words longer than 3 letters.

Ruby

words = ["cat", "lion", "tiger", "dog"]
lengths = {word[1] for word in words if word[2] 3}
puts lengths.inspect

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A => word.length

B >

C <

D ==

Attempts:

3 left

💡 Hint

Common Mistakes

Using < or == which filter wrong words.

Forgetting the hash rocket => in the hash comprehension.

The code creates a hash where keys are words and values are their lengths, filtering words longer than 3 letters.

5fill in blank

hard

Fill all three blanks to create a hash with uppercase words as keys, their lengths as values, only for words longer than 3 letters.

Ruby

words = ["apple", "bat", "carrot", "dog"]
result = {word[1]: [2] for word in words if word.length [3] 3}
puts result.inspect

Drag options to blanks, or click blank then click option'

A.upcase()

Blen(word)

C>

Dword.length

Attempts:

3 left

💡 Hint

Common Mistakes

Using len(word) which is Python syntax, not Ruby.

Using wrong comparison operators.

The code creates a hash with uppercase words as keys and their lengths as values, filtering words longer than 3 letters.