Accessing elements (indexing, first, last) in Ruby - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to get the first element of the array.

Ruby

arr = [10, 20, 30]
first_element = arr.[1]

Drag options to blanks, or click blank then click option'

Apop

Blast

Cfirst

Dshift

Attempts:

3 left

💡 Hint

Common Mistakes

Using last instead of first.

Using pop which removes the last element.

The first method returns the first element of the array.

2fill in blank

medium

Complete the code to get the last element of the array.

Ruby

numbers = [5, 15, 25, 35]
last_num = numbers.[1]

Drag options to blanks, or click blank then click option'

Afirst

Bpop

Cshift

Dlast

Attempts:

3 left

💡 Hint

Common Mistakes

Using pop which removes the last element instead of just accessing it.

Using first which returns the first element.

The last method returns the last element of the array without removing it.

3fill in blank

hard

Fix the error in the code to access the second element of the array.

Ruby

items = ['apple', 'banana', 'cherry']
second_item = items[[1]]

Drag options to blanks, or click blank then click option'

A1

B2

C0

D-1

Attempts:

3 left

💡 Hint

Common Mistakes

Using 2 which is the third element.

Using 0 which is the first element.

Array indexing starts at 0, so the second element is at index 1.

4fill in blank

hard

Fill both blanks to create a hash with words as keys and their lengths as values, only for words longer than 3 letters.

Ruby

words = ['cat', 'lion', 'tiger', 'dog']
lengths = {word => word.[1] for word in words if word.length [2] 3}

Drag options to blanks, or click blank then click option'

Alength

Bsize

C>

D<

Attempts:

3 left

💡 Hint

Common Mistakes

Using size which also works but is less common here.

Using < which filters shorter words.

Use length to get the word length and > to check if it's longer than 3.

5fill in blank

hard

Fill all three blanks to create a hash with uppercase words as keys, their original words as values, only if the word length is greater than 3.

Ruby

words = ['ant', 'bear', 'cat', 'dog']
result = {word.[1] => word.[2] for word in words if word.length [3] 3}

Drag options to blanks, or click blank then click option'

Aupcase

Bto_s

C>

Dlength

Attempts:

3 left

💡 Hint

Common Mistakes

Using length as a key method instead of upcase.

Using < instead of > in the condition.

upcase converts the word to uppercase for the key, to_s ensures the value is a string, and > checks length greater than 3.