Map function usage in React - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to render a list of names using map.

React

const names = ['Anna', 'Bob', 'Cara'];
return (
  <ul>
    {names.[1](name => <li key={name}>{name}</li>)}
  </ul>
);

Drag options to blanks, or click blank then click option'

AforEach

Bmap

Cfilter

Dreduce

Attempts:

3 left

💡 Hint

Common Mistakes

Using forEach instead of map, which does not return a new array.

The map function transforms each item in the array into a React element to render.

2fill in blank

medium

Complete the code to add a unique key to each list item when mapping.

React

const items = ['apple', 'banana', 'cherry'];
return (
  <ul>
    {items.map(item => <li [1]={item}>{item}</li>)}
  </ul>
);

Drag options to blanks, or click blank then click option'

Akey

Bindex

Cid

Dname

Attempts:

3 left

💡 Hint

Common Mistakes

Using id or index as prop names instead of key.

React requires a key prop on list items to help identify elements uniquely.

3fill in blank

hard

Fix the error in the map callback parameter to correctly access the index.

React

const numbers = [1, 2, 3];
return (
  <ul>
    {numbers.map((num, [1]) => <li key={num}>{num} - [1]</li>)}
  </ul>
);

Drag options to blanks, or click blank then click option'

AnumIndex

Bidx

Ci

Dindex

Attempts:

3 left

💡 Hint

Common Mistakes

Using a different parameter name but referencing 'index' inside JSX.

The second parameter in the map callback is conventionally named index to access the current item's position.

4fill in blank

hard

Fill both blanks to create a map that filters and transforms items.

React

const fruits = ['apple', 'banana', 'cherry', 'date'];
const filtered = fruits
  .filter(fruit => fruit.length > [1])
  .map(fruit => fruit.[2]());

Drag options to blanks, or click blank then click option'

A5

BtoUpperCase

CtoLowerCase

D3

Attempts:

3 left

💡 Hint

Common Mistakes

Using a wrong number for length or wrong string method.

We filter fruits with length greater than 5, then convert each to uppercase.

5fill in blank

hard

Fill all three blanks to create a dictionary from an array using map and reduce.

React

const data = ['a', 'bb', 'ccc'];
const result = data.reduce((acc, [1]) => {
  acc[[2]] = [3];
  return acc;
}, {});

Drag options to blanks, or click blank then click option'

Aitem

Bitem.length

Dindex

Attempts:

3 left

💡 Hint

Common Mistakes

Mixing up keys and values or using wrong variable names.

We use reduce to build an object where keys are the items and values are their lengths.

Practice

1. What is the main purpose of using the map function in React when rendering lists?

easy

A. To mutate the original array directly

B. To remove duplicate elements from the array

C. To sort the array elements alphabetically

D. To transform an array into a list of React elements

Solution

1. Step 1: Understand what map does in JavaScript

   The map function creates a new array by applying a function to each element of the original array without changing it.

2. Step 2: Apply this to React rendering

   In React, map is used to convert each item in an array into a React element, which can then be rendered as a list.

3. Final Answer:

   To transform an array into a list of React elements -> Option D

4. Quick Check:

   map creates React elements from arrays = B [OK]

Hint: Remember: map creates new arrays, perfect for rendering lists [OK]

Common Mistakes:

• Thinking map changes the original array
• Confusing map with sorting or filtering
• Not realizing map returns a new array

2. Which of the following is the correct syntax to use map inside a React component to render a list of names stored in const names = ['Anna', 'Bob', 'Cara']?

easy

A. {names.map(name => <li key={name}>{name}</li>)}

B. {names.map(name => <li>name</li>)}

C. {names.forEach(name => <li key={name}>{name}</li>)}

D. {names.map(name => <li>{name}</li> key={name})}

Solution

1. Step 1: Check the correct use of map and JSX

   Using map with an arrow function returning JSX elements is correct. The element must have a unique key prop inside the returned JSX.

2. Step 2: Identify the correct syntax

   {names.map(name => <li key={name}>{name}</li>)} correctly uses map, returns a list item with curly braces around name, and includes a unique key prop.

3. Final Answer:

   {names.map(name => <li key={name}>{name}</li>)} -> Option A

4. Quick Check:

   map + JSX + key prop = A [OK]

Hint: Always add a unique key prop inside map JSX elements [OK]

Common Mistakes:

• Using forEach instead of map
• Missing curly braces around variables in JSX
• Placing key prop outside the JSX element

3. What will be the output of this React code snippet?

const numbers = [1, 2, 3];
const listItems = numbers.map(n => <li key={n}>Number: {n * 2}</li>);
return <ul>{listItems}</ul>;

medium

A. Number: 2Number: 4Number: 6

B. SyntaxError due to missing parentheses

C. Number: n * 2Number: n * 2Number: n * 2

D. Number: 1Number: 2Number: 3

Solution

1. Step 1: Understand the map transformation

   Each number in the array is multiplied by 2 inside the JSX expression: {n * 2}.

2. Step 2: Predict the rendered list items

   The list items will show "Number: 2", "Number: 4", and "Number: 6" respectively.

3. Final Answer:

   <ul><li>Number: 2</li><li>Number: 4</li><li>Number: 6</li></ul> -> Option A

4. Quick Check:

   n * 2 applied in map = D [OK]

Hint: Check the expression inside map carefully for output values [OK]

Common Mistakes:

• Assuming original numbers are shown without multiplication
• Confusing JSX expression syntax
• Thinking map returns strings instead of elements

4. Identify the error in this React code using map:

const items = ['a', 'b', 'c'];
return <ul>{items.map(item => <li>{item}</li>)};

medium

A. map function cannot be used inside JSX

B. Missing unique key prop on <li> elements

C. Incorrect use of curly braces around item

D. Array items must be numbers, not strings

Solution

1. Step 1: Check JSX inside map

   The map function returns
2. elements but none have a key prop, which React requires for lists.

3. Step 2: Confirm other syntax is correct

   Curly braces around item are correct, map is valid inside JSX, and array can contain strings.

4. Final Answer:

   Missing unique key prop on <li> elements -> Option B

5. Quick Check:

   React needs keys in lists = C [OK]

Hint: Always add key prop to elements inside map [OK]

Common Mistakes:

• Ignoring missing key warnings
• Thinking keys are optional
• Confusing key prop placement

5. Given this nested array of user objects:

const users = [
  { id: 1, name: 'Alice', hobbies: ['Reading', 'Hiking'] },
  { id: 2, name: 'Bob', hobbies: ['Cooking'] }
];

// Which code correctly renders a list of users with their hobbies?

hard

A. {users.map(user => <div key={user.id}><h3>{user.name}</h3><ul>{user.hobbies.map(hobby => <li key={user.id}>{hobby}</li>)}

B. {users.map(user => <div><h3>{user.name}</h3><ul>{user.hobbies.map(hobby => <li>{hobby}</li>)}

C. {users.map(user => <div key={user.id}><h3>{user.name}</h3><ul>{user.hobbies.map(hobby => <li key={hobby}>{hobby}</li>)}

D. {users.map(user => <div key={user.name}><h3>{user.name}</h3><ul>{user.hobbies.map(hobby => <li key={user.id}>{hobby}</li>)}

Solution

1. Step 1: Check keys on outer and inner lists

   The outer div uses user.id as key, which is unique. The inner li uses hobby as key, which is unique per hobby.

2. Step 2: Verify correct JSX structure and keys

   {users.map(user => <div key={user.id}><h3>{user.name}</h3><ul>{user.hobbies.map(hobby => <li key={hobby}>{hobby}</li>)} correctly nests the hobbies list inside each user and assigns proper keys. Other options miss keys or reuse keys incorrectly.

3. Final Answer:

   {users.map(user => <div key={user.id}><h3>{user.name}</h3><ul>{user.hobbies.map(hobby => <li key={hobby}>{hobby}</li>)} -> Option C

4. Quick Check:

   Unique keys on nested lists = A [OK]

Hint: Use unique keys for both outer and inner mapped elements [OK]

Common Mistakes:

• Reusing same key for multiple elements
• Missing key on inner map elements
• Using non-unique keys like user name or id incorrectly