pivot_longer (wide to long) in R Programming - Cheat Sheet & Quick Revision

Recall & Review

beginner

What does the pivot_longer() function do in R?

It transforms data from a wide format (many columns) into a long format (fewer columns, more rows), making it easier to analyze and visualize.

beginner

In pivot_longer(), what do the cols and names_to arguments specify?

cols selects which columns to turn from wide to long. names_to names the new column that will hold the old column names.

intermediate

Why would you use pivot_longer() instead of keeping data wide?

Long format data is easier to work with for many R functions and plotting tools because it standardizes the structure, making grouping and summarizing simpler.

beginner

What happens if you omit the values_to argument in pivot_longer()?

The new column holding the values from the original columns will be named value by default.

intermediate

How can you use pivot_longer() to reshape this data?

  id  Jan  Feb  Mar
1  A   10   20   30
2  B   15   25   35

Use pivot_longer(cols = Jan:Mar, names_to = "month", values_to = "value") to get columns id, month, and value with one row per month per id.

What is the main purpose of pivot_longer() in R?

A Filter rows based on a condition

B Convert wide data to long format

C Convert long data to wide format

D Sort data by column values

pivot_longer() changes wide data (many columns) into long data (fewer columns, more rows).

Which argument in pivot_longer() specifies the new column name for the old column names?

A names_to

B cols

C values_to

D values_drop_na

names_to sets the name of the new column that holds the original column names.

If you want to keep columns id and reshape columns Q1, Q2, Q3, which cols argument would you use?

A cols = id

B cols = NULL

C cols = Q1:Q3

D cols = everything()

cols = Q1:Q3 selects columns Q1 to Q3 to pivot longer.

What default name does pivot_longer() give to the values column if values_to is not set?

A value

B values

C data

D val

The default name for the values column is value.

Which package provides the pivot_longer() function?

A data.table

B dplyr

C ggplot2

D tidyr

pivot_longer() is part of the tidyr package.

Explain in your own words what pivot_longer() does and why it is useful.

Think about changing many columns into fewer columns with more rows.

Describe how you would use pivot_longer() to reshape a dataset with monthly sales columns into a long format with one column for month and one for sales.

Focus on naming the new columns for months and sales values.

Practice

1. What does the pivot_longer() function do in R's tidyverse?

easy

A. It filters rows based on a condition.

B. It creates new columns by splitting existing ones.

C. It transforms wide data into long data by stacking columns into rows.

D. It sorts data by a specific column.

Solution

1. Step 1: Understand the purpose of pivot_longer()

   The function is designed to reshape data from wide format (many columns) to long format (fewer columns, more rows).

2. Step 2: Identify the correct description

   Among the options, only It transforms wide data into long data by stacking columns into rows. correctly describes stacking columns into rows, which is what pivot_longer does.

3. Final Answer:

   It transforms wide data into long data by stacking columns into rows. -> Option C

4. Quick Check:

   pivot_longer = wide to long [OK]

Hint: pivot_longer stacks columns into rows to tidy data [OK]

Common Mistakes:

• Confusing pivot_longer with filtering or sorting functions
• Thinking it splits columns instead of stacking
• Assuming it creates new columns instead of reshaping

2. Which of the following is the correct syntax to pivot columns Jan and Feb into longer format with new columns named Month and Sales?

easy

A. pivot_longer(data, cols = c(Jan, Feb), names_to = "Month", values_to = "Sales")

B. pivot_longer(data, columns = c(Jan, Feb), names = "Month", values = "Sales")

C. pivot_longer(data, cols = c("Jan", "Feb"), names_to = Month, values_to = Sales)

D. pivot_longer(data, cols = Jan, Feb, names_to = "Month", values_to = "Sales")

Solution

1. Step 1: Check argument names and syntax

   The correct argument names are cols, names_to, and values_to. Columns should be passed as symbols or strings inside c().

2. Step 2: Validate each option

   pivot_longer(data, cols = c(Jan, Feb), names_to = "Month", values_to = "Sales") uses correct argument names and syntax with symbols inside c(). pivot_longer(data, columns = c(Jan, Feb), names = "Month", values = "Sales") uses wrong argument names. pivot_longer(data, cols = c("Jan", "Feb"), names_to = Month, values_to = Sales) misses quotes around new column names. pivot_longer(data, cols = Jan, Feb, names_to = "Month", values_to = "Sales") incorrectly separates columns without c().

3. Final Answer:

   pivot_longer(data, cols = c(Jan, Feb), names_to = "Month", values_to = "Sales") -> Option A

4. Quick Check:

   Correct args: cols, names_to, values_to [OK]

Hint: Use cols = c(), names_to and values_to with quotes [OK]

Common Mistakes:

• Using wrong argument names like columns or names
• Forgetting quotes around new column names
• Not wrapping columns in c()

3. Given this data frame in R:

df <- data.frame(ID = 1:2, Jan = c(10, 20), Feb = c(15, 25))

What is the output of:

pivot_longer(df, cols = c(Jan, Feb), names_to = "Month", values_to = "Value")

medium

A. A data frame with columns ID, Month, and Value, where Jan and Feb values are stacked under Value.

B. A data frame with columns ID, Jan, Feb unchanged.

C. An error because cols argument is missing quotes.

D. A data frame with columns ID, Month, Value but values are all NA.

Solution

1. Step 1: Understand pivot_longer behavior on df

   The function stacks the Jan and Feb columns into two rows per ID, creating Month and Value columns.

2. Step 2: Predict the output structure

   The output will have 4 rows (2 IDs x 2 months) and columns: ID, Month (Jan or Feb), and Value (corresponding numbers).

3. Final Answer:

   A data frame with columns ID, Month, and Value, where Jan and Feb values are stacked under Value. -> Option A

4. Quick Check:

   pivot_longer stacks columns into rows [OK]

Hint: pivot_longer stacks selected columns into new key-value columns [OK]

Common Mistakes:

• Expecting original wide format unchanged
• Thinking it causes errors without quotes on cols
• Assuming values become NA

4. What is wrong with this code?

pivot_longer(df, cols = Jan, Feb, names_to = "Month", values_to = "Value")

medium

A. The function pivot_longer does not exist.

B. The cols argument should be a vector using c(), not separate arguments.

C. The values_to argument is missing.

D. The names_to argument should not be in quotes.

Solution

1. Step 1: Check the cols argument format

   The cols argument must be a vector of columns, written as cols = c(Jan, Feb). Passing them separately is invalid syntax.

2. Step 2: Verify other arguments

   names_to and values_to are correctly used with quotes. The function exists in the tidyverse package.

3. Final Answer:

   The cols argument should be a vector using c(), not separate arguments. -> Option B

4. Quick Check:

   cols = c(...) required [OK]

Hint: Wrap multiple columns in c() inside cols argument [OK]

Common Mistakes:

• Passing multiple columns without c()
• Removing quotes from names_to or values_to
• Assuming pivot_longer is not available

5. You have a data frame:

df <- data.frame(ID = 1:2, Q1_2019 = c(5, 6), Q2_2019 = c(7, 8), Q1_2020 = c(9, 10))

You want to pivot it longer so that the quarter and year are separate columns named Quarter and Year, and the values go into Score. Which code achieves this?

hard

A. pivot_longer(df, cols = c(Q1_2019, Q2_2019, Q1_2020), names_to = c("Quarter", "Year"), values_to = "Score")

B. pivot_longer(df, cols = c(Q1_2019, Q2_2019, Q1_2020), names_to = "Quarter_Year", values_to = "Score")

C. pivot_longer(df, cols = c(Q1_2019, Q2_2019, Q1_2020), names_to = c("Year", "Quarter"), names_sep = "_", values_to = "Score")

D. pivot_longer(df, cols = starts_with("Q"), names_to = c("Quarter", "Year"), names_sep = "_", values_to = "Score")

Solution

1. Step 1: Identify columns to pivot

   All columns starting with "Q" represent quarters and years, so starts_with("Q") selects them.

2. Step 2: Separate names into Quarter and Year

   Using names_to = c("Quarter", "Year") with names_sep = "_" splits the column names at underscore into two new columns.

3. Step 3: Assign values to Score

   The values_to = "Score" argument names the new value column.

4. Final Answer:

   pivot_longer(df, cols = starts_with("Q"), names_to = c("Quarter", "Year"), names_sep = "_", values_to = "Score") -> Option D

5. Quick Check:

   Use names_sep to split names_to vector [OK]

Hint: Use names_to vector and names_sep to split column names [OK]

Common Mistakes:

• Not using names_sep to split names into multiple columns
• Swapping order of Quarter and Year in names_to
• Not selecting all relevant columns with starts_with