A t-test helps you check if two groups have different average values. It tells you if the difference is real or just by chance.
t-test in R Programming
t.test(x, y = NULL, alternative = c("two.sided", "less", "greater"), paired = FALSE, var.equal = FALSE, mu = 0)
x is the first group of numbers.
y is the second group (optional for one-sample test).
t.test(group1, group2)
t.test(before, after, paired = TRUE)
x is different from 10.t.test(x, mu = 10)This program compares two groups of numbers and prints the p-value. The p-value shows if the difference in averages is likely real.
group1 <- c(5, 6, 7, 8, 9) group2 <- c(7, 8, 9, 10, 11) result <- t.test(group1, group2) print(result$p.value)
A small p-value (usually less than 0.05) means the groups are likely different.
Use paired = TRUE when the same subjects are measured twice.
Set var.equal = TRUE if you believe both groups have the same variance.
A t-test checks if two groups have different averages.
It gives a p-value to help decide if the difference is real.
Use it for comparing groups or before/after measurements.
Practice
What does a t-test primarily compare in two groups?
Solution
Step 1: Understand the purpose of a t-test
A t-test is used to compare the means (averages) of two groups to see if they are different.Step 2: Identify what is compared
The test focuses on the average values, not medians, counts, or variances.Final Answer:
The difference between their averages -> Option BQuick Check:
t-test compares means = A [OK]
- Confusing mean with median
- Thinking it compares counts
- Assuming it compares variances
Which of the following is the correct way to run a t-test in R comparing two numeric vectors x and y?
Solution
Step 1: Recall the correct function name in R
The built-in function for t-test in R ist.test().Step 2: Check the syntax for comparing two vectors
Usingt.test(x, y)compares the two numeric vectors correctly.Final Answer:
t.test(x, y) -> Option CQuick Check:
Correct function is t.test() = A [OK]
- Misspelling the function name
- Using underscores instead of dots
- Confusing function with other test names
What will be the output of this R code snippet?
group1 <- c(5, 7, 8, 6, 9) group2 <- c(10, 12, 11, 13, 14) test <- t.test(group1, group2) round(test$p.value, 3)
Solution
Step 1: Understand the data groups
Group1 has smaller values around 5-9, Group2 has larger values around 10-14, so means differ.Step 2: Interpret the p-value from t.test()
Since the groups differ clearly, the p-value will be very small, close to 0.001 after rounding.Final Answer:
0.001 -> Option AQuick Check:
Distinct groups give low p-value = B [OK]
- Assuming p-value is large for different groups
- Confusing p-value with test statistic
- Ignoring rounding in output
Identify the error in this R code for a t-test:
data1 <- c(4, 5, 6) data2 <- c(7, 8, 9) test <- t.test(data1 + data2)
Solution
Step 1: Check the function call syntax
The t.test() function expects two separate vectors as arguments separated by a comma.Step 2: Identify the mistake in argument passing
The code uses '+' to add vectors instead of separating them with a comma, which is incorrect.Final Answer:
Using '+' instead of ',' to separate vectors -> Option DQuick Check:
Arguments must be comma-separated = D [OK]
- Adding vectors instead of passing separately
- Confusing function arguments syntax
- Thinking t.test needs data frames
You have two groups of exam scores: before and after a training program. Which t-test is best to check if the training improved scores?
Solution
Step 1: Understand the data relationship
Scores are from the same students before and after training, so data are paired.Step 2: Choose the correct t-test type
A paired t-test compares matched pairs to see if scores changed after training.Final Answer:
Paired t-test using t.test(before, after, paired=TRUE) -> Option AQuick Check:
Paired data needs paired=TRUE = C [OK]
- Using two-sample test for paired data
- Using one-sample test incorrectly
- Confusing variance test with t-test
Ready to prove it?
Pass the test and this pattern moves unknown
