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R Programmingprogramming~30 mins

Parameterized reports in R Programming - Mini Project: Build & Apply

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Parameterized Reports in R
📖 Scenario: You work in a small bookstore. You want to create a report that shows sales data for a specific month. Instead of making a new report every time, you will make a parameterized report that can show data for any month you choose.
🎯 Goal: Build a simple R script that uses a parameter (month) to filter sales data and then prints the total sales for that month.
📋 What You'll Learn
Create a data frame called sales_data with columns month and sales and exact values.
Create a variable called selected_month to hold the month to filter.
Use a filter to select rows from sales_data where month matches selected_month.
Calculate the total sales for the selected month and store it in total_sales.
Print the total sales with a clear message.
💡 Why This Matters
🌍 Real World
Stores and businesses often need reports filtered by dates or categories. Parameterized reports save time and avoid repeating work.
💼 Career
Data analysts and business intelligence professionals use parameterized reports to quickly generate insights for different time periods or segments.
Progress0 / 4 steps
1
Create the sales data frame
Create a data frame called sales_data with two columns: month and sales. Use these exact values: months are "January", "February", "March", "April", and sales are 150, 200, 170, 220 respectively.
R Programming
Hint

Use data.frame() with two vectors named month and sales.

2
Set the selected month parameter
Create a variable called selected_month and set it to the string "March".
R Programming
Hint

Assign the string "March" to selected_month.

3
Filter data and calculate total sales
Create a variable called filtered_data that contains only rows from sales_data where month equals selected_month. Then create a variable called total_sales that sums the sales column of filtered_data.
R Programming
Hint

Use sales_data[sales_data$month == selected_month, ] to filter rows and sum() to add sales.

4
Print the total sales
Write a print() statement that outputs the text: Total sales in March: 170 using the variable total_sales and selected_month.
R Programming
Hint

Use paste() inside print() to combine text and variables.

Practice

(1/5)
1. What is the main purpose of using parameterized reports in R Markdown?
easy
A. To speed up the knitting process
B. To customize report content without changing the code
C. To automatically generate plots
D. To create interactive dashboards

Solution

  1. Step 1: Understand parameterized reports concept

    Parameterized reports allow passing different inputs to the same report code.
  2. Step 2: Identify the main benefit

    This lets you customize the report output without editing the code itself.
  3. Final Answer:

    To customize report content without changing the code -> Option B
  4. Quick Check:

    Parameterized reports = customize content without code change [OK]
Hint: Think: change inputs, not code, to customize reports [OK]
Common Mistakes:
  • Confusing parameterized reports with speeding up knitting
  • Thinking it automatically creates plots
  • Mixing with dashboard creation
2. Which YAML header syntax correctly defines a parameter named year with default value 2023?
easy
A. params: year: "2023"
B. parameters: year = 2023
C. parameters: year: 2023
D. params: year: 2023

Solution

  1. Step 1: Recall YAML parameter syntax in R Markdown

    Parameters are defined under params: with key-value pairs.
  2. Step 2: Check correct key and value format

    params: year: 2023 uses params: and year: 2023 correctly without quotes needed for numbers.
  3. Final Answer:

    params: year: 2023 -> Option D
  4. Quick Check:

    YAML params use 'params:' and colon syntax [OK]
Hint: Use 'params:' and colon, no equals sign in YAML [OK]
Common Mistakes:
  • Using 'parameters:' instead of 'params:'
  • Using equals sign '=' instead of colon ':'
  • Putting numbers in quotes unnecessarily
3. Given this R Markdown snippet, what will be the output when params$region is set to "West"?
```{r}
if (params$region == "West") {
  print("Sales are high in the West")
} else {
  print("Sales data not available")
}
```
medium
A. [1] "Sales are high in the West"
B. [1] "Sales data not available"
C. Error: object 'params' not found
D. [1] "Sales are high in the East"

Solution

  1. Step 1: Check the condition with given parameter

    The condition checks if params$region equals "West". It is set to "West".
  2. Step 2: Determine which print statement runs

    Since condition is true, it prints "Sales are high in the West".
  3. Final Answer:

    [1] "Sales are high in the West" -> Option A
  4. Quick Check:

    params$region == "West" -> print message for West [OK]
Hint: Match param value exactly to choose output branch [OK]
Common Mistakes:
  • Confusing the else branch output
  • Assuming params is undefined causing error
  • Mixing region names in output
4. Identify the error in this R Markdown YAML header for parameterized report:
---
title: "Sales Report"
params:
  month = "January"
output: html_document
---
medium
A. Incorrect output format specified
B. Missing quotes around 'January'
C. Using '=' instead of ':' to assign parameter value
D. Missing 'params' section

Solution

  1. Step 1: Review YAML parameter syntax

    Parameters use colon ':' to assign values, not equals '='.
  2. Step 2: Identify the syntax error

    Here, month = "January" uses '=' which is invalid YAML syntax.
  3. Final Answer:

    Using '=' instead of ':' to assign parameter value -> Option C
  4. Quick Check:

    YAML params need ':' not '=' [OK]
Hint: YAML uses colon ':' for key-value pairs, never '=' [OK]
Common Mistakes:
  • Using '=' instead of ':' in YAML
  • Thinking quotes are mandatory for strings
  • Confusing output format with params syntax
5. You want to create a parameterized report that filters a dataset by category and year. Which approach correctly uses parameters in the R code chunk to filter df?
hard
A. filtered_df <- subset(df, category == params$category & year == params$year)
B. filtered_df <- df[df$category = params$category & df$year = params$year, ]
C. filtered_df <- filter(df, category = params$category, year = params$year)
D. filtered_df <- df[category == params$category & year == params$year]

Solution

  1. Step 1: Understand filtering syntax in R

    The subset() function uses logical conditions with '==' to filter rows.
  2. Step 2: Check parameter usage in filtering

    filtered_df <- subset(df, category == params$category & year == params$year) correctly uses params$category and params$year with '==' inside subset().
  3. Final Answer:

    filtered_df <- subset(df, category == params$category & year == params$year) -> Option A
  4. Quick Check:

    Use '==' for comparison and subset() for filtering [OK]
Hint: Use subset() with '==' and params$ for filtering [OK]
Common Mistakes:
  • Using '=' instead of '==' for comparison
  • Incorrect subsetting syntax without dataframe reference
  • Confusing filter() syntax without library
Recommended

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10 questions~5 mineasy hard