Solution:Step 1: Trace normal and exception flow__enter__ prints 'Log start'. Inside block, 'Running' prints, then division by zero raises exception.Step 2: __exit__ handles exception__exit__ detects exception, prints error message, then prints 'Log end'.Final Answer:Log start Running Error: divisio

[Solved] Consider this code:class Logger: def __enter__(self): print('Log start') return self def __exit__(self, exc_type, exc_val, exc_tb): if exc_type: print(f'Error:... | Python

Python - Context Managers

Consider this code:

class Logger:
    def __enter__(self):
        print('Log start')
        return self
    def __exit__(self, exc_type, exc_val, exc_tb):
        if exc_type:
            print(f'Error: {exc_val}')
        print('Log end')

with Logger() as log:
    print('Running')
    1 / 0

What will be printed before the program stops?

ALog start Error: division by zero Running Log end

BLog start Running Error: division by zero Log end

CRunning Log start Error: division by zero Log end

DLog start Running Log end

Step-by-Step Solution

Solution:

Step 1: Trace normal and exception flow
__enter__ prints 'Log start'. Inside block, 'Running' prints, then division by zero raises exception.
Step 2: __exit__ handles exception
__exit__ detects exception, prints error message, then prints 'Log end'.
Final Answer:
Log start Running Error: division by zero Log end -> Option B
Quick Check:
__exit__ runs even on exceptions [OK]

Quick Trick: __exit__ runs on exceptions and can handle them [OK]

Common Mistakes:

MISTAKES

Assuming __exit__ does not run on error
Mixing print order

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More Python Quizzes

Consider this code:

Step 1: Trace normal and exception flow

Step 2: exit handles exception

Final Answer:

Quick Check:

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