[Solved] Consider this polymorphic function:def combine(a, b): if isinstance(a, dict) and isinstance(b, dict): return {**a, **b} elif isinstance(a, list) and isinstance(b, list): return a + b else:... | Python

Python - Polymorphism and Dynamic Behavior

Consider this polymorphic function:

def combine(a, b):
    if isinstance(a, dict) and isinstance(b, dict):
        return {**a, **b}
    elif isinstance(a, list) and isinstance(b, list):
        return a + b
    else:
        return str(a) + str(b)

What is the output of combine({'x':1}, {'y':2}) and combine([1,2], [3,4])?

A{'x': 1, 'y': 2} and [1, 2, 3, 4, 5]

B{'x': 1} and [1, 2, 3, 4]

CError and [1, 2, 3, 4]

D{'x': 1, 'y': 2} and [1, 2, 3, 4]

Step-by-Step Solution

Solution:

Step 1: Combine two dicts
Using {**a, **b} merges dicts: {'x':1} and {'y':2} become {'x':1, 'y':2}.
Step 2: Combine two lists
Using + concatenates lists: [1,2] + [3,4] = [1,2,3,4].
Final Answer:
{'x': 1, 'y': 2} and [1, 2, 3, 4] -> Option D
Quick Check:
Dict merge and list concat produce {'x': 1, 'y': 2} and [1, 2, 3, 4] outputs [OK]

Quick Trick: Use ** to merge dicts and + to join lists [OK]

Common Mistakes:

MISTAKES

Expecting error when merging dicts
Adding extra elements to lists
Returning original dict instead of merged

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Consider this polymorphic function:

Step 1: Combine two dicts

Step 2: Combine two lists

Final Answer:

Quick Check:

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