[Solved] What will be printed when the following code is executed?class DataHolder: def __init__(self): self._secret = 42 obj = DataHolder() print(obj._secret) | Python

Python - Encapsulation and Data Protection

What will be printed when the following code is executed?

class DataHolder:
    def __init__(self):
        self._secret = 42

obj = DataHolder()
print(obj._secret)

A42

BAttributeError

CNone

D0

Step-by-Step Solution

Solution:

Step 1: Understand attribute access
In Python, attributes with a single underscore prefix are accessible outside the class.
Step 2: Analyze the code
The attribute _secret is set to 42 in the constructor.
Step 3: Print statement
Printing obj._secret will output 42 without error.
Final Answer:
42 -> Option A
Quick Check:
Single underscore attributes are accessible [OK]

Quick Trick: Single underscore attributes are accessible outside class [OK]

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