Why dictionary comprehension is used in Python - Test Your Understanding

Practice - 5 Tasks

1fill in blank

easy

Complete the code to create a dictionary with numbers as keys and their squares as values.

Python

squares = {x: x[1]2 for x in range(1, 6)}
print(squares)

Drag options to blanks, or click blank then click option'

A+

B**

C*

D//

Attempts:

3 left

💡 Hint

Common Mistakes

Using multiplication operator instead of exponentiation.

The ** operator is used to raise a number to a power. Here, it squares the number.

2fill in blank

medium

Complete the code to create a dictionary of words and their lengths from a list.

Python

words = ['apple', 'banana', 'cherry']
lengths = {word: [1] for word in words}
print(lengths)

Drag options to blanks, or click blank then click option'

Aword

Blength(word)

Cword.length

Dlen(word)

Attempts:

3 left

💡 Hint

Common Mistakes

Using incorrect syntax like word.length which is not valid in Python.

The len() function returns the length of a string in Python.

3fill in blank

hard

Fix the error in the dictionary comprehension to include only even numbers as keys.

Python

evens = {x: x**2 for x in range(1, 11) if x [1] 2 == 0}
print(evens)

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A%

B!=

C//

D+

Attempts:

3 left

💡 Hint

Common Mistakes

Using != instead of % for checking even numbers.

The modulo operator % gives the remainder. If remainder is 0 when divided by 2, the number is even.

4fill in blank

hard

Fill both blanks to create a dictionary of numbers and their cubes only if the cube is greater than 10.

Python

cubes = {x: x[1]3 for x in range(1, 6) if x[2]3 > 10}
print(cubes)

Drag options to blanks, or click blank then click option'

A**

B*

C>

D<

Attempts:

3 left

💡 Hint

Common Mistakes

Using multiplication instead of exponentiation.

Using wrong comparison operator.

Use ** to cube the number and > to check if the cube is greater than 10.

5fill in blank

hard

Fill all three blanks to create a dictionary with uppercase keys and values only if the length of the word is greater than 4.

Python

words = ['dog', 'elephant', 'cat', 'giraffe']
result = [1]: [2] for word in words if len(word) [3] 4
print(result)

Drag options to blanks, or click blank then click option'

Aword.upper()

Bword

C>

D<

Attempts:

3 left

💡 Hint

Common Mistakes

Using wrong comparison operator.

Not converting keys to uppercase.

Use word.upper() to make keys uppercase, keep values as word, and filter words with length greater than 4 using >.